如何在Node.js中获取脚本的路径?
我知道有流程。Cwd,但它只引用调用脚本的目录,而不是脚本本身。例如,假设我在/home/kyle/目录下,然后运行以下命令:
node /home/kyle/some/dir/file.js
如果我调用process.cwd(),我会得到/home/kyle/,而不是/home/kyle/some/dir/。有办法得到那个目录吗?
如何在Node.js中获取脚本的路径?
我知道有流程。Cwd,但它只引用调用脚本的目录,而不是脚本本身。例如,假设我在/home/kyle/目录下,然后运行以下命令:
node /home/kyle/some/dir/file.js
如果我调用process.cwd(),我会得到/home/kyle/,而不是/home/kyle/some/dir/。有办法得到那个目录吗?
当前回答
使用path模块的basename方法:
var path = require('path');
var filename = path.basename(__filename);
console.log(filename);
下面是上面例子的文档。
正如Dan指出的,Node正在处理带有“——experimental-modules”标志的ECMAScript模块。节点12仍然支持前面提到的__dirname和__filename。
如果您正在使用——experimental-modules标志,还有另一种方法。
另一种方法是获取当前ES模块的路径:
import { fileURLToPath } from 'url';
const __filename = fileURLToPath(new URL(import.meta.url));
对于包含当前模块的目录:
import { fileURLToPath } from 'url';
import path from 'path';
const __dirname = path.dirname(fileURLToPath(new URL(import.meta.url)));
其他回答
我又看了一遍文件后找到的。我要找的是__filename和__dirname模块级变量。
__filename是当前模块的文件名。这是当前模块文件的解析绝对路径。(例:/ home /凯尔/一些/ dir / file.js) __dirname是当前模块的目录名。(例:/ home /凯尔/一些/ dir)
基本上你可以这样做:
fs.readFile(path.resolve(__dirname, 'settings.json'), 'UTF-8', callback);
使用resolve()而不是连接'/'或'\',否则您将遇到跨平台问题。
注意:__dirname是模块或包含脚本的本地路径。如果你正在编写一个插件,需要知道主脚本的路径,它是:
require.main.filename
或者,获取文件夹名称:
require('path').dirname(require.main.filename)
如果你想在shell脚本中使用类似$0的东西,试试这个:
var path = require('path');
var command = getCurrentScriptPath();
console.log(`Usage: ${command} <foo> <bar>`);
function getCurrentScriptPath () {
// Relative path from current working directory to the location of this script
var pathToScript = path.relative(process.cwd(), __filename);
// Check if current working dir is the same as the script
if (process.cwd() === __dirname) {
// E.g. "./foobar.js"
return '.' + path.sep + pathToScript;
} else {
// E.g. "foo/bar/baz.js"
return pathToScript;
}
}
你可以使用process.env.PWD来获取当前应用程序的文件夹路径。
I know this is pretty old, and the original question I was responding to is marked as duplicate and directed here, but I ran into an issue trying to get jasmine-reporters to work and didn't like the idea that I had to downgrade in order for it to work. I found out that jasmine-reporters wasn't resolving the savePath correctly and was actually putting the reports folder output in jasmine-reporters directory instead of the root directory of where I ran gulp. In order to make this work correctly I ended up using process.env.INIT_CWD to get the initial Current Working Directory which should be the directory where you ran gulp. Hope this helps someone.
var reporters = require('jasmine-reporters');
var junitReporter = new reporters.JUnitXmlReporter({
savePath: process.env.INIT_CWD + '/report/e2e/',
consolidateAll: true,
captureStdout: true
});