如何在Node.js中获取脚本的路径?

我知道有流程。Cwd,但它只引用调用脚本的目录,而不是脚本本身。例如,假设我在/home/kyle/目录下,然后运行以下命令:

node /home/kyle/some/dir/file.js

如果我调用process.cwd(),我会得到/home/kyle/,而不是/home/kyle/some/dir/。有办法得到那个目录吗?


当前回答

你可以使用process.env.PWD来获取当前应用程序的文件夹路径。

其他回答

当涉及到主脚本时,它非常简单:

process.argv[1]

来自Node.js文档:

process.argv 包含命令行参数的数组。第一个元素是“node”,第二个元素是JavaScript文件的路径。下一个元素将是任何额外的命令行参数。

如果你需要知道模块文件的路径,那么使用__filename。

基本上你可以这样做:

fs.readFile(path.resolve(__dirname, 'settings.json'), 'UTF-8', callback);

使用resolve()而不是连接'/'或'\',否则您将遇到跨平台问题。

注意:__dirname是模块或包含脚本的本地路径。如果你正在编写一个插件,需要知道主脚本的路径,它是:

require.main.filename

或者,获取文件夹名称:

require('path').dirname(require.main.filename)

如果你想在shell脚本中使用类似$0的东西,试试这个:

var path = require('path');

var command = getCurrentScriptPath();

console.log(`Usage: ${command} <foo> <bar>`);

function getCurrentScriptPath () {
    // Relative path from current working directory to the location of this script
    var pathToScript = path.relative(process.cwd(), __filename);

    // Check if current working dir is the same as the script
    if (process.cwd() === __dirname) {
        // E.g. "./foobar.js"
        return '.' + path.sep + pathToScript;
    } else {
        // E.g. "foo/bar/baz.js"
        return pathToScript;
    }
}

这个命令返回当前目录:

var currentPath = process.cwd();

例如,使用路径读取文件:

var fs = require('fs');
fs.readFile(process.cwd() + "\\text.txt", function(err, data)
{
    if(err)
        console.log(err)
    else
        console.log(data.toString());
});

I know this is pretty old, and the original question I was responding to is marked as duplicate and directed here, but I ran into an issue trying to get jasmine-reporters to work and didn't like the idea that I had to downgrade in order for it to work. I found out that jasmine-reporters wasn't resolving the savePath correctly and was actually putting the reports folder output in jasmine-reporters directory instead of the root directory of where I ran gulp. In order to make this work correctly I ended up using process.env.INIT_CWD to get the initial Current Working Directory which should be the directory where you ran gulp. Hope this helps someone.

var reporters = require('jasmine-reporters');
var junitReporter = new reporters.JUnitXmlReporter({
  savePath: process.env.INIT_CWD + '/report/e2e/',
  consolidateAll: true,
  captureStdout: true
 });