The following script uses only "cmd.exe" and outputs the number of milliseconds from the time a pipeline is created to the time that the process preceding the script exits. i.e., Type your command, and pipe the to the script. Example: "timeout 3 | runtime.cmd" should yield something like "2990." If you need both the runtime output and the stdin output, redirect stdin before the pipe - ex: "dir /s 1>temp.txt | runtime.cmd" would dump the output of the "dir" command to "temp.txt" and would print the runtime to the console.

:: --- runtime.cmd ----
@echo off
setlocal enabledelayedexpansion

:: find target for recursive calls
if not "%1"=="" (
    shift /1
    goto :%1
    exit /b
)

:: set pipeline initialization time
set t1=%time%

:: wait for stdin
more > nul

:: set time at which stdin was ready
set t2=!time!

::parse t1
set t1=!t1::= !
set t1=!t1:.= !
set t1=!t1: 0= !

:: parse t2
set t2=!t2::= !
set t2=!t2:.= !
set t2=!t2: 0= !

:: calc difference
pushd %~dp0
for /f %%i in ('%0 calc !t1!') do for /f %%j in ('%0 calc !t2!') do (
    set /a t=%%j-%%i
    echo !t!
)
popd
exit /b
goto :eof

:calc
set /a t=(%1*(3600*1000))+(%2*(60*1000))+(%3*1000)+(%4)
echo !t!
goto :eof

endlocal

driblio的答案可以短一点(虽然可读性不高)

@echo off

:: Calculate the start timestamp
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _started=_hours*60*60*100+_min*60*100+_sec*100+_cs


:: yourCommandHere


:: Calculate the difference in cSeconds
set _time=%time%
set /a _hours=100%_time:~0,2%%%100,_min=100%_time:~3,2%%%100,_sec=100%_time:~6,2%%%100,_cs=%_time:~9,2%
set /a _duration=_hours*60*60*100+_min*60*100+_sec*100+_cs-_started

:: Populate variables for rendering (100+ needed for padding)
set /a _hours=_duration/60/60/100,_min=100+_duration/60/100%%60,_sec=100+(_duration/100%%60%%60),_cs=100+_duration%%100

echo Done at: %_time% took : %_hours%:%_min:~-2%:%_sec:~-2%.%_cs:~-2%

::prints something like:
::Done at: 12:37:53,70 took: 0:02:03.55

根据Luke Sampson的评论，这个版本是八进制安全的，尽管任务应该在24小时内完成。

还有TimeMem(2012年3月):

这是一个Windows实用程序，执行一个程序并显示它 执行时间、内存使用和IO统计信息。这与 Unix time实用程序的功能。

一个解决方案使用纯PHP为cmd和一个env。变量:

@echo off
setlocal enableextensions

REM set start time env var
FOR /F "tokens=* USEBACKQ" %%F IN (`php -r "echo microtime(true);"`) DO ( SET start_time=%%F )

## PUT_HERE_THE_COMMAND_TO_RUN ##

REM echo elapsed time
php -r "echo 'elapsed: ' . (round(microtime(true) - trim(getenv('start_time')), 2)) . ' seconds' . mb_convert_encoding('
', 'UTF-8', 'HTML-ENTITIES');"

不需要cygwin或不受信任的实用程序。当PHP在本地可用时非常有用 精度和输出格式可以很容易地调整 同样的想法也可以移植到PowerShell

我使用的是Windows XP，由于某些原因，time .exe不适合我。我找到了另一种选择——PTIME。这工作得很好。

http://www.pc-tools.net/win32/ptime/

的例子,

C:\> ptime

ptime 1.0 for Win32, Freeware - http://www.pc-tools.net/
Copyright(C) 2002, Jem Berkes <jberkes@pc-tools.net>

Syntax: ptime command [arguments ...]

ptime will run the specified command and measure the execution time
(run time) in seconds, accurate to 5 millisecond or better. It is an
automatic process timer, or program timer.


C:\> ptime cd

ptime 1.0 for Win32, Freeware - http://www.pc-tools.net/
Copyright(C) 2002, Jem Berkes <jberkes@pc-tools.net>

===  cd ===
C:\

Execution time: 0.015 s

下面的脚本模拟*nix纪元时间，但它是本地和区域性的。它应该处理日历边缘情况，包括闰年。如果Cygwin可用，则可以通过指定Cygwin选项来比较epoch值。

我在EST，报告的差异是4小时，这是相对正确的。有一些有趣的解决方案可以删除TZ和区域依赖，但我注意到没有什么微不足道的。

@ECHO off
SETLOCAL EnableDelayedExpansion

::
::  Emulates local epoch seconds
::

:: Call passing local date and time
CALL :SECONDS "%DATE%" "%TIME%"
IF !SECONDS! LEQ 0 GOTO END

:: Not testing - print and exit
IF NOT "%~1"=="cygwin" (
    ECHO !SECONDS!
    GOTO END
)

:: Call on Cygwin to get epoch time
FOR /F %%c IN ('C:\cygwin\bin\date +%%s') DO SET EPOCH=%%c

:: Show the results
ECHO Local Seconds: !SECONDS!
ECHO Epoch Seconds: !EPOCH!

:: Calculate difference between script and Cygwin
SET /A HOURS=(!EPOCH!-!SECONDS!)/3600
SET /A FRAC=(!EPOCH!-!SECONDS!)%%3600

:: Delta hours shown reflect TZ
ECHO Delta Hours: !HOURS! Remainder: !FRAC!

GOTO END

:SECONDS
SETLOCAL  EnableDelayedExpansion

    :: Expecting values from caller
    SET DATE=%~1
    SET TIME=%~2

    :: Emulate Unix epoch time without considering TZ
    SET "SINCE_YEAR=1970"

    :: Regional constraint! Expecting date and time in the following formats:
    ::   Sun 03/08/2015   Day MM/DD/YYYY
    ::   20:04:53.64         HH:MM:SS
    SET VALID_DATE=0
    ECHO !DATE! | FINDSTR /R /C:"^... [0-9 ][0-9]/[0-9 ][0-9]/[0-9][0-9][0-9][0-9]" > nul && SET VALID_DATE=1
    SET VALID_TIME=0
    ECHO !TIME! | FINDSTR /R /C:"^[0-9 ][0-9]:[0-9 ][0-9]:[0-9 ][0-9]" > nul && SET VALID_TIME=1
    IF NOT "!VALID_DATE!!VALID_TIME!"=="11" (
        IF !VALID_DATE! EQU 0  ECHO Unsupported Date value: !DATE! 1>&2
        IF !VALID_TIME! EQU 0  ECHO Unsupported Time value: !TIME! 1>&2
        SET SECONDS=0
        GOTO SECONDS_END
    )

    :: Parse values
    SET "YYYY=!DATE:~10,4!"
    SET "MM=!DATE:~4,2!"
    SET "DD=!DATE:~7,2!"
    SET "HH=!TIME:~0,2!"
    SET "NN=!TIME:~3,2!"
    SET "SS=!TIME:~6,2!"
    SET /A YEARS=!YYYY!-!SINCE_YEAR!
    SET /A DAYS=!YEARS!*365

    :: Bump year if after February  - want leading zeroes for this test
    IF "!MM!!DD!" GEQ "0301" SET /A YEARS+=1

    :: Remove leading zeros that can cause octet probs for SET /A
    FOR %%r IN (MM,DD,HH,NN,SS) DO (
        SET "v=%%r"
        SET "t=!%%r!"
        SET /A N=!t:~0,1!0
        IF 0 EQU !N! SET "!v!=!t:~1!"
    )

    :: Increase days according to number of leap years
    SET /A DAYS+=(!YEARS!+3)/4-(!SINCE_YEAR!%%4+3)/4

    :: Increase days by preceding months of current year
    FOR %%n IN (31:1,28:2,31:3,30:4,31:5,30:6,31:7,31:8,30:9,31:10,30:11) DO (
        SET "n=%%n"
        IF !MM! GTR !n:~3! SET /A DAYS+=!n:~0,2!
    )

    :: Multiply and add it all together
    SET /A SECONDS=(!DAYS!+!DD!-1)*86400+!HH!*3600+!NN!*60+!SS!

:SECONDS_END
ENDLOCAL & SET "SECONDS=%SECONDS%"
GOTO :EOF

:END
ENDLOCAL