我知道有很多这种性质的问题,但我需要使用JavaScript来做到这一点。我使用Dojo 1.8并在数组中拥有所有属性信息,它看起来像这样:
[["name1", "city_name1", ...]["name2", "city_name2", ...]]
知道我如何在客户端将此导出为CSV吗?
我知道有很多这种性质的问题,但我需要使用JavaScript来做到这一点。我使用Dojo 1.8并在数组中拥有所有属性信息,它看起来像这样:
[["name1", "city_name1", ...]["name2", "city_name2", ...]]
知道我如何在客户端将此导出为CSV吗?
当前回答
人们尝试创建自己的csv字符串,在边缘情况下失败,例如特殊字符,这肯定是一个解决的问题,对吧?
papaparse -用于JSON到CSV编码。Papa.unparse()。
import Papa from "papaparse";
const downloadCSV = (args) => {
let filename = args.filename || 'export.csv';
let columns = args.columns || null;
let csv = Papa.unparse({ data: args.data, fields: columns})
if (csv == null) return;
var blob = new Blob([csv]);
if (window.navigator.msSaveOrOpenBlob) // IE hack; see http://msdn.microsoft.com/en-us/library/ie/hh779016.aspx
window.navigator.msSaveBlob(blob, args.filename);
else
{
var a = window.document.createElement("a");
a.href = window.URL.createObjectURL(blob, {type: "text/plain"});
a.download = filename;
document.body.appendChild(a);
a.click(); // IE: "Access is denied"; see: https://connect.microsoft.com/IE/feedback/details/797361/ie-10-treats-blob-url-as-cross-origin-and-denies-access
document.body.removeChild(a);
}
}
示例使用
downloadCSV({
filename: "filename.csv",
data: [{"a": "1", "b": "2"}],
columns: ["a","b"]
});
https://github.com/mholt/PapaParse/issues/175 -请参阅此评论了解浏览器支持讨论。
其他回答
适用于所有语言
function convertToCsv(fName, rows) {
var csv = '';
for (var i = 0; i < rows.length; i++) {
var row = rows[i];
for (var j = 0; j < row.length; j++) {
var val = row[j] === null ? '' : row[j].toString();
val = val.replace(/\t/gi, " ");
if (j > 0)
csv += '\t';
csv += val;
}
csv += '\n';
}
// for UTF-16
var cCode, bArr = [];
bArr.push(255, 254);
for (var i = 0; i < csv.length; ++i) {
cCode = csv.charCodeAt(i);
bArr.push(cCode & 0xff);
bArr.push(cCode / 256 >>> 0);
}
var blob = new Blob([new Uint8Array(bArr)], { type: 'text/csv;charset=UTF-16LE;' });
if (navigator.msSaveBlob) {
navigator.msSaveBlob(blob, fName);
} else {
var link = document.createElement("a");
if (link.download !== undefined) {
var url = window.URL.createObjectURL(blob);
link.setAttribute("href", url);
link.setAttribute("download", fName);
link.style.visibility = 'hidden';
document.body.appendChild(link);
link.click();
document.body.removeChild(link);
window.URL.revokeObjectURL(url);
}
}
}
convertToCsv('download.csv', [
['Order', 'Language'],
['1', 'English'],
['2', 'Español'],
['3', 'Français'],
['4', 'Português'],
['5', 'čeština'],
['6', 'Slovenščina'],
['7', 'Tiếng Việt'],
['8', 'Türkçe'],
['9', 'Norsk bokmål'],
['10', 'Ελληνικά'],
['11', 'беларускі'],
['12', 'русский'],
['13', 'Українська'],
['14', 'հայերեն'],
['15', 'עִברִית'],
['16', 'اردو'],
['17', 'नेपाली'],
['18', 'हिंदी'],
['19', 'ไทย'],
['20', 'ქართული'],
['21', '中国'],
['22', '한국어'],
['23', '日本語'],
])
人们尝试创建自己的csv字符串,在边缘情况下失败,例如特殊字符,这肯定是一个解决的问题,对吧?
papaparse -用于JSON到CSV编码。Papa.unparse()。
import Papa from "papaparse";
const downloadCSV = (args) => {
let filename = args.filename || 'export.csv';
let columns = args.columns || null;
let csv = Papa.unparse({ data: args.data, fields: columns})
if (csv == null) return;
var blob = new Blob([csv]);
if (window.navigator.msSaveOrOpenBlob) // IE hack; see http://msdn.microsoft.com/en-us/library/ie/hh779016.aspx
window.navigator.msSaveBlob(blob, args.filename);
else
{
var a = window.document.createElement("a");
a.href = window.URL.createObjectURL(blob, {type: "text/plain"});
a.download = filename;
document.body.appendChild(a);
a.click(); // IE: "Access is denied"; see: https://connect.microsoft.com/IE/feedback/details/797361/ie-10-treats-blob-url-as-cross-origin-and-denies-access
document.body.removeChild(a);
}
}
示例使用
downloadCSV({
filename: "filename.csv",
data: [{"a": "1", "b": "2"}],
columns: ["a","b"]
});
https://github.com/mholt/PapaParse/issues/175 -请参阅此评论了解浏览器支持讨论。
下面是我如何在Java GWT应用程序的客户端下载CSV文件。特别感谢Xavier John的解决方案。已验证在FF 24.6.0, IE 11.0.20, Chrome 45.0.2454.99(64位)下运行。我希望这能节省一些时间:
public class ExportFile
{
private static final String CRLF = "\r\n";
public static void exportAsCsv(String filename, List<List<String>> data)
{
StringBuilder sb = new StringBuilder();
for(List<String> row : data)
{
for(int i=0; i<row.size(); i++)
{
if(i>0) sb.append(",");
sb.append(row.get(i));
}
sb.append(CRLF);
}
generateCsv(filename, sb.toString());
}
private static native void generateCsv(String filename, String text)
/*-{
var blob = new Blob([text], { type: 'text/csv;charset=utf-8;' });
if (navigator.msSaveBlob) // IE 10+
{
navigator.msSaveBlob(blob, filename);
}
else
{
var link = document.createElement("a");
if (link.download !== undefined) // feature detection
{
// Browsers that support HTML5 download attribute
var url = URL.createObjectURL(blob);
link.setAttribute("href", url);
link.setAttribute("download", filename);
link.style.visibility = 'hidden';
document.body.appendChild(link);
link.click();
document.body.removeChild(link);
}
}
}-*/;
}
来自@Default的解决方案在Chrome上完美地工作(非常感谢!),但我有一个IE问题。
以下是一个解决方案(适用于IE10):
var csvContent=data; //here we load our csv data
var blob = new Blob([csvContent],{
type: "text/csv;charset=utf-8;"
});
navigator.msSaveBlob(blob, "filename.csv")
这里有两个问题:
如何将数组转换为csv字符串 如何将该字符串保存到文件
第一个问题的所有答案(除了millimetric给出的答案)似乎都有些夸张。Milimetric提供的方法不包括其他要求,比如用引号括住字符串或转换对象数组。
以下是我的看法:
对于一个简单的csv,一个map()和一个join()就足够了:
var test_array = [["name1", 2, 3], ["name2", 4, 5], ["name3", 6, 7], ["name4", 8, 9], ["name5", 10, 11]];
var csv = test_array.map(function(d){
return d.join();
}).join('\n');
/* Results in
name1,2,3
name2,4,5
name3,6,7
name4,8,9
name5,10,11
此方法还允许您在内部连接中指定除逗号之外的列分隔符。例如一个制表符:d.join('\t')
另一方面,如果你想正确地将字符串括在引号""中,那么你可以使用一些JSON魔法:
var csv = test_array.map(function(d){
return JSON.stringify(d);
})
.join('\n')
.replace(/(^\[)|(\]$)/mg, ''); // remove opening [ and closing ]
// brackets from each line
/* would produce
"name1",2,3
"name2",4,5
"name3",6,7
"name4",8,9
"name5",10,11
如果你有一个这样的对象数组:
var data = [
{"title": "Book title 1", "author": "Name1 Surname1"},
{"title": "Book title 2", "author": "Name2 Surname2"},
{"title": "Book title 3", "author": "Name3 Surname3"},
{"title": "Book title 4", "author": "Name4 Surname4"}
];
// use
var csv = data.map(function(d){
return JSON.stringify(Object.values(d));
})
.join('\n')
.replace(/(^\[)|(\]$)/mg, '');