如果你想递归复制源目录的所有内容，那么你需要将递归选项传递为true，并尝试通过fs-extra记录catch以进行同步

因为fs-extra完全替代了fs，所以你不需要导入基本模块

const fs = require('fs-extra');
let sourceDir = '/tmp/src_dir';
let destDir = '/tmp/dest_dir';
try {
  fs.copySync(sourceDir, destDir, { recursive: true })
  console.log('success!')
} catch (err) {
  console.error(err)
}

解决这个问题最简单的方法是只使用'fs'和'Path'模块和一些逻辑…

如果你只是想设置版本号，根文件夹中的所有文件都复制新名称，即" var v = '您的目录名'"

在文件名的前缀中添加带有文件名的内容。

var fs = require('fs-extra');
var path = require('path');

var c = 0;
var i = 0;
var v = "1.0.2";
var copyCounter = 0;
var directoryCounter = 0;
var directoryMakerCounter = 0;
var recursionCounter = -1;
var Flag = false;
var directoryPath = [];
var directoryName = [];
var directoryFileName = [];
var fileName;
var directoryNameStorer;
var dc = 0;
var route;

if (!fs.existsSync(v)) {
    fs.mkdirSync(v);
}

var basePath = path.join(__dirname, v);


function walk(dir) {

    fs.readdir(dir, function(err, items) {

        items.forEach(function(file) {

            file = path.resolve(dir, file);

            fs.stat(file, function(err, stat) {

                if(stat && stat.isDirectory()) {
                    directoryNameStorer = path.basename(file);
                    route = file;
                    route = route.replace("gd", v);

                    directoryFileName[directoryCounter] = route;
                    directoryPath[directoryCounter] = file;
                    directoryName[directoryCounter] = directoryNameStorer;

                    directoryCounter++;
                    dc++;

                    if (!fs.existsSync(basePath + "/" + directoryName[directoryMakerCounter])) {
                        fs.mkdirSync(directoryFileName[directoryMakerCounter]);
                        directoryMakerCounter++;
                    }
                }
                else {
                    fileName = path.basename(file);
                    if(recursionCounter >= 0) {
                        fs.copyFileSync(file, directoryFileName[recursionCounter] + "/" + v + "_" + fileName, err => {
                            if(err) return console.error(err);
                        });
                        copyCounter++;
                    }
                    else {
                        fs.copyFileSync(file, v + "/" + v + "_" + fileName, err => {
                            if(err) return console.error(err);
                        });
                        copyCounter++;
                    }
                }
                if(copyCounter + dc == items.length && directoryCounter > 0 && recursionCounter < directoryMakerCounter-1) {
                    console.log("COPY COUNTER:             " + copyCounter);
                    console.log("DC COUNTER:               " + dc);
                    recursionCounter++;
                    dc = 0;
                    copyCounter = 0;
                    console.log("ITEM DOT LENGTH:          " + items.length);
                    console.log("RECURSION COUNTER:        " + recursionCounter);
                    console.log("DIRECOTRY MAKER COUNTER:  " + directoryMakerCounter);
                    console.log(": START RECURSION:        " + directoryPath[recursionCounter]);
                    walk(directoryPath[recursionCounter]); //recursive call to copy sub-folder
                }
            })
        })
    });
}

walk('./gd', function(err, data) { // Just pass the root directory which you want to copy
    if(err)
        throw err;
    console.log("done");
})

如果你在Linux上，性能不是问题，你可以使用child_process模块中的exec函数来执行一个Bash命令:

const { exec } = require('child_process');
exec('cp -r source dest', (error, stdout, stderr) => {...});

在某些情况下，我发现这个解决方案比下载整个模块甚至使用fs模块更简洁。

由于我只是构建一个简单的Node.js脚本，我不希望脚本的用户需要导入一堆外部模块和依赖项，所以我开始思考，并从Bash shell中搜索运行命令。

这个Node.js代码片段递归地复制了一个名为node-webkit的文件夹。应用程序到一个名为build的文件夹:

child = exec("cp -r node-webkit.app build", function(error, stdout, stderr) {
    sys.print("stdout: " + stdout);
    sys.print("stderr: " + stderr);
    if(error !== null) {
        console.log("exec error: " + error);
    } else {

    }
});

感谢dzone的兰斯·波拉德让我开始。

上面的代码片段仅限于基于unix的平台，如macOS和Linux，但类似的技术也适用于Windows。

这可能是一个可能的解决方案使用异步生成器函数和迭代等待循环。这个解决方案包括过滤掉一些目录的可能性，将它们作为可选的第三个数组参数传递。

import path from 'path';
import { readdir, copy } from 'fs-extra';

async function* getFilesRecursive(srcDir: string, excludedDir?: PathLike[]): AsyncGenerator<string> {
  const directoryEntries: Dirent[] = await readdir(srcDir, { withFileTypes: true });
  if (!directoryEntries.length) yield srcDir; // If the directory is empty, return the directory path.
  for (const entry of directoryEntries) {
    const fileName = entry.name;
      const sourcePath = resolvePath(`${srcDir}/${fileName}`);
      if (entry.isDirectory()) {
        if (!excludedDir?.includes(sourcePath)) {
          yield* getFilesRecursive(sourcePath, excludedDir);
        }
      } else {
        yield sourcePath;
      }
  }
}

然后:

for await (const filePath of getFilesRecursive(path, ['dir1', 'dir2'])) {
   await copy(filePath, filePath.replace(path, path2));
}

打印稿版本

async function copyDir(source: string, destination: string): Promise<any> {
  const directoryEntries = await readdir(source, { withFileTypes: true });
  await mkdir(destination, { recursive: true });

  return Promise.all(
    directoryEntries.map(async (entry) => {
      const sourcePath = path.join(source, entry.name);
      const destinationPath = path.join(destination, entry.name);

      return entry.isDirectory()
        ? copyDir(sourcePath, destinationPath)
        : copyFile(sourcePath, destinationPath);
    })
  );
}