是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?
我只是想知道我是否错过了一个函数,理想情况下是这样工作的:
fs.copy("/path/to/source/folder", "/path/to/destination/folder");
关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用
是否有一种更简单的方法来复制文件夹及其所有内容,而无需手动执行一系列的fs。readir, fs。readfile, fs。writefile递归?
我只是想知道我是否错过了一个函数,理想情况下是这样工作的:
fs.copy("/path/to/source/folder", "/path/to/destination/folder");
关于这个历史问题。注意fs。Cp和fs。cpSync可以递归复制文件夹,在Node v16+中可用
当前回答
打印稿版本
async function copyDir(source: string, destination: string): Promise<any> {
const directoryEntries = await readdir(source, { withFileTypes: true });
await mkdir(destination, { recursive: true });
return Promise.all(
directoryEntries.map(async (entry) => {
const sourcePath = path.join(source, entry.name);
const destinationPath = path.join(destination, entry.name);
return entry.isDirectory()
? copyDir(sourcePath, destinationPath)
: copyFile(sourcePath, destinationPath);
})
);
}
其他回答
我写了这个函数用于在目录之间递归地复制(copyFileSync)或移动(renameSync)文件:
// Copy files
copyDirectoryRecursiveSync(sourceDir, targetDir);
// Move files
copyDirectoryRecursiveSync(sourceDir, targetDir, true);
function copyDirectoryRecursiveSync(source, target, move) {
if (!fs.lstatSync(source).isDirectory())
return;
var operation = move ? fs.renameSync : fs.copyFileSync;
fs.readdirSync(source).forEach(function (itemName) {
var sourcePath = path.join(source, itemName);
var targetPath = path.join(target, itemName);
if (fs.lstatSync(sourcePath).isDirectory()) {
fs.mkdirSync(targetPath);
copyDirectoryRecursiveSync(sourcePath, targetPath);
}
else {
operation(sourcePath, targetPath);
}
});
}
fs-extra模块工作起来很有魅力。
安装fs-extra:
$ npm install fs-extra
下面是将源目录复制到目标目录的程序。
// Include the fs-extra package
var fs = require("fs-extra");
var source = 'folderA'
var destination = 'folderB'
// Copy the source folder to the destination
fs.copy(source, destination, function (err) {
if (err){
console.log('An error occurred while copying the folder.')
return console.error(err)
}
console.log('Copy completed!')
});
参考文献
fs-extra: https://www.npmjs.com/package/fs-extra
示例:Node.js教程- Node.js复制文件夹
内联版本
node -e "const fs=require('fs');const p=require('path');function copy(src, dest) {if (!fs.existsSync(src)) {return;} if (fs.statSync(src).isFile()) {fs.copyFileSync(src, dest);}else{fs.mkdirSync(dest, {recursive: true});fs.readdirSync(src).forEach(f=>copy(p.join(src, f), p.join(dest, f)));}}const args=Array.from(process.argv); copy(args[args.length-2], args[args.length-1]);" dist temp\dest
或者节点16.x+
node -e "const fs=require('fs');const args=Array.from(process.argv); fs.cpSync(args[args.length-2], args[args.length-1], {recursive: true});"
在“节点14.20.0”上测试,但假设它在节点10.x上工作?
来自user8894303和pen的回答:https://stackoverflow.com/a/52338335/458321
如果在包中使用,请务必转义引号。json脚本
package.json:
"scripts": {
"rmrf": "node -e \"const fs=require('fs/promises');const args=Array.from(process.argv); Promise.allSettled(args.map(a => fs.rm(a, { recursive: true, force: true })));\"",
"cp": "node -e \"const fs=require('fs');const args=Array.from(process.argv);if (args.length>2){ fs.cpSync(args[args.length-2], args[args.length-1], {recursive: true});}else{console.log('args missing', args);}\""
"copy": "node -e \"const fs=require('fs');const p=require('path');function copy(src, dest) {if (!fs.existsSync(src)) {return;} if (fs.statSync(src).isFile()) {fs.copyFileSync(src, dest);}else{fs.mkdirSync(dest, {recursive: true});fs.readdirSync(src).forEach(f=>copy(p.join(src, f), p.join(dest, f)));}}const args=Array.from(process.argv);if (args.length>2){copy(args[args.length-2], args[args.length-1]);}else{console.log('args missing', args);}\"",
"mkdir": "node -e \"const fs=require('fs');const args=Array.from(process.argv);fs.mkdirSync(args[args.length-1],{recursive:true});\"",
"clean": "npm run rmrf -- temp && npm run mkdir -- temp && npm run copy -- dist temp"
}
注:RMRF脚本需要14.20节点。X还是12.20.x?
奖金:
deno eval "import { existsSync, mkdirSync, copyFileSync, readdirSync, statSync } from 'node:fs';import { join } from 'node:path';function copy(src, dest) {if (!existsSync(src)) {return;} if (statSync(src).isFile()) {copyFileSync(src, dest);}else{mkdirSync(dest, {recursive: true});readdirSync(src).forEach(f=>copy(join(src, f), join(dest, f)));}}const args=Array.from(Deno.args);copy(args[0], args[1]);" dist temp\dest -- --allow-read --allow-write
Deno支持-> NPM I Deno -bin支持节点中的Deno -bin
支持符号链接的:
const path = require("path");
const {
existsSync,
mkdirSync,
readdirSync,
lstatSync,
copyFileSync,
symlinkSync,
readlinkSync,
} = require("fs");
export function copyFolderSync(src, dest) {
if (!existsSync(dest)) {
mkdirSync(dest);
}
readdirSync(src).forEach((entry) => {
const srcPath = path.join(src, entry);
const destPath = path.join(dest, entry);
const stat = lstatSync(srcPath);
if (stat.isFile()) {
copyFileSync(srcPath, destPath);
} else if (stat.isDirectory()) {
copyFolderSync(srcPath, destPath);
} else if (stat.isSymbolicLink()) {
symlinkSync(readlinkSync(srcPath), destPath);
}
});
}
我知道这里已经有很多答案了,但是没有一个答案是简单的。
关于fs-exra官方文档,您可以非常轻松地完成。
const fs = require('fs-extra')
// Copy file
fs.copySync('/tmp/myfile', '/tmp/mynewfile')
// Copy directory, even if it has subdirectories or files
fs.copySync('/tmp/mydir', '/tmp/mynewdir')