我试图做POST与HttpURLConnection(我需要使用这种方式，不能使用HttpPost)，我想添加参数的连接，如
post.setEntity(new UrlEncodedFormEntity(nvp));
在哪里
nvp = new ArrayList<NameValuePair>();
有一些数据存储在。我找不到一种方法如何添加这个数组列表到我的HttpURLConnection在这里:
HttpsURLConnection https = (HttpsURLConnection) url.openConnection();
https.setHostnameVerifier(DO_NOT_VERIFY);
http = https;
http.setRequestMethod("POST");
http.setDoInput(true);
http.setDoOutput(true);
出现这种尴尬的https和http组合的原因是不需要验证证书。不过，这不是问题，它可以很好地发布服务器。但我需要它来张贴论点。
什么好主意吗?
重复的免责声明:
早在2012年，我还不知道如何在HTTP POST请求中插入参数。我一直在使用NameValuePair，因为它在教程中。这个问题可能看起来像一个重复的问题，然而，我2012年自己读了另一个问题，它没有使用NameValuePair。事实上，这并没有解决我的问题。
因为NameValuePair已弃用。想过分享我的代码
public String performPostCall(String requestURL,
HashMap<String, String> postDataParams) {
URL url;
String response = "";
try {
url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(15000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write(getPostDataString(postDataParams));
writer.flush();
writer.close();
os.close();
int responseCode=conn.getResponseCode();
if (responseCode == HttpsURLConnection.HTTP_OK) {
String line;
BufferedReader br=new BufferedReader(new InputStreamReader(conn.getInputStream()));
while ((line=br.readLine()) != null) {
response+=line;
}
}
else {
response="";
}
} catch (Exception e) {
e.printStackTrace();
}
return response;
}
....
private String getPostDataString(HashMap<String, String> params) throws UnsupportedEncodingException{
StringBuilder result = new StringBuilder();
boolean first = true;
for(Map.Entry<String, String> entry : params.entrySet()){
if (first)
first = false;
else
result.append("&");
result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
result.append("=");
result.append(URLEncoder.encode(entry.getValue(), "UTF-8"));
}
return result.toString();
}
因为NameValuePair已弃用。想过分享我的代码
public String performPostCall(String requestURL,
HashMap<String, String> postDataParams) {
URL url;
String response = "";
try {
url = new URL(requestURL);
HttpURLConnection conn = (HttpURLConnection) url.openConnection();
conn.setReadTimeout(15000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write(getPostDataString(postDataParams));
writer.flush();
writer.close();
os.close();
int responseCode=conn.getResponseCode();
if (responseCode == HttpsURLConnection.HTTP_OK) {
String line;
BufferedReader br=new BufferedReader(new InputStreamReader(conn.getInputStream()));
while ((line=br.readLine()) != null) {
response+=line;
}
}
else {
response="";
}
} catch (Exception e) {
e.printStackTrace();
}
return response;
}
....
private String getPostDataString(HashMap<String, String> params) throws UnsupportedEncodingException{
StringBuilder result = new StringBuilder();
boolean first = true;
for(Map.Entry<String, String> entry : params.entrySet()){
if (first)
first = false;
else
result.append("&");
result.append(URLEncoder.encode(entry.getKey(), "UTF-8"));
result.append("=");
result.append(URLEncoder.encode(entry.getValue(), "UTF-8"));
}
return result.toString();
}
如果你不需要ArrayList<NameValuePair>作为参数，这是一个更短的解决方案，它使用Uri构建查询字符串。建筑类:
URL url = new URL("http://yoururl.com");
HttpsURLConnection conn = (HttpsURLConnection) url.openConnection();
conn.setReadTimeout(10000);
conn.setConnectTimeout(15000);
conn.setRequestMethod("POST");
conn.setDoInput(true);
conn.setDoOutput(true);
Uri.Builder builder = new Uri.Builder()
.appendQueryParameter("firstParam", paramValue1)
.appendQueryParameter("secondParam", paramValue2)
.appendQueryParameter("thirdParam", paramValue3);
String query = builder.build().getEncodedQuery();
OutputStream os = conn.getOutputStream();
BufferedWriter writer = new BufferedWriter(
new OutputStreamWriter(os, "UTF-8"));
writer.write(query);
writer.flush();
writer.close();
os.close();
conn.connect();
一个解决方案是让你自己的params字符串。
这是我在我的最新项目中使用的实际方法。你需要将args从hashtable更改为namevaluepair:
private static String getPostParamString(Hashtable<String, String> params) {
if(params.size() == 0)
return "";
StringBuffer buf = new StringBuffer();
Enumeration<String> keys = params.keys();
while(keys.hasMoreElements()) {
buf.append(buf.length() == 0 ? "" : "&");
String key = keys.nextElement();
buf.append(key).append("=").append(params.get(key));
}
return buf.toString();
}
发布参数:
OutputStreamWriter writer = new OutputStreamWriter(conn.getOutputStream());
writer.write(getPostParamString(req.getPostParams()));
AsyncTask通过POST方法将数据作为JSONObect发送
public class PostMethodDemo extends AsyncTask<String , Void ,String> {
String server_response;
@Override
protected String doInBackground(String... strings) {
URL url;
HttpURLConnection urlConnection = null;
try {
url = new URL(strings[0]);
urlConnection = (HttpURLConnection) url.openConnection();
urlConnection.setDoOutput(true);
urlConnection.setDoInput(true);
urlConnection.setRequestMethod("POST");
DataOutputStream wr = new DataOutputStream(urlConnection.getOutputStream ());
try {
JSONObject obj = new JSONObject();
obj.put("key1" , "value1");
obj.put("key2" , "value2");
wr.writeBytes(obj.toString());
Log.e("JSON Input", obj.toString());
wr.flush();
wr.close();
} catch (JSONException ex) {
ex.printStackTrace();
}
urlConnection.connect();
int responseCode = urlConnection.getResponseCode();
if(responseCode == HttpURLConnection.HTTP_OK){
server_response = readStream(urlConnection.getInputStream());
}
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(String s) {
super.onPostExecute(s);
Log.e("Response", "" + server_response);
}
}
public static String readStream(InputStream in) {
BufferedReader reader = null;
StringBuffer response = new StringBuffer();
try {
reader = new BufferedReader(new InputStreamReader(in));
String line = "";
while ((line = reader.readLine()) != null) {
response.append(line);
}
} catch (IOException e) {
e.printStackTrace();
} finally {
if (reader != null) {
try {
reader.close();
} catch (IOException e) {
e.printStackTrace();
}
}
}
return response.toString();
}
