向canvas元素添加一个单击事件处理程序,返回单击的x和y坐标(相对于canvas元素),最简单的方法是什么?
不需要传统浏览器兼容性,Safari、Opera和Firefox就可以了。
向canvas元素添加一个单击事件处理程序,返回单击的x和y坐标(相对于canvas元素),最简单的方法是什么?
不需要传统浏览器兼容性,Safari、Opera和Firefox就可以了。
当前回答
我在创建一个应用程序,在pdf上有一个画布,这涉及到很多画布的大小调整,比如放大和缩小pdf,然后在每次放大/缩小pdf时,我都必须调整画布的大小以适应pdf的大小,我在stackOverflow中经历了很多答案,并没有找到一个完美的解决方案,最终将解决问题。
我使用的是rxjs和angular 6,没有找到任何针对最新版本的答案。
这里是整个代码片段,这将是有帮助的,任何人利用rxjs在画布上绘制。
private captureEvents(canvasEl: HTMLCanvasElement) {
this.drawingSubscription = fromEvent(canvasEl, 'mousedown')
.pipe(
switchMap((e: any) => {
return fromEvent(canvasEl, 'mousemove')
.pipe(
takeUntil(fromEvent(canvasEl, 'mouseup').do((event: WheelEvent) => {
const prevPos = {
x: null,
y: null
};
})),
takeUntil(fromEvent(canvasEl, 'mouseleave')),
pairwise()
)
})
)
.subscribe((res: [MouseEvent, MouseEvent]) => {
const rect = this.cx.canvas.getBoundingClientRect();
const prevPos = {
x: Math.floor( ( res[0].clientX - rect.left ) / ( rect.right - rect.left ) * this.cx.canvas.width ),
y: Math.floor( ( res[0].clientY - rect.top ) / ( rect.bottom - rect.top ) * this.cx.canvas.height )
};
const currentPos = {
x: Math.floor( ( res[1].clientX - rect.left ) / ( rect.right - rect.left ) * this.cx.canvas.width ),
y: Math.floor( ( res[1].clientY - rect.top ) / ( rect.bottom - rect.top ) * this.cx.canvas.height )
};
this.coordinatesArray[this.file.current_slide - 1].push(prevPos);
this.drawOnCanvas(prevPos, currentPos);
});
}
这里是修复的代码片段,鼠标坐标相对于画布的大小,不管你如何放大/缩小画布。
const prevPos = {
x: Math.floor( ( res[0].clientX - rect.left ) / ( rect.right - rect.left ) * this.cx.canvas.width ),
y: Math.floor( ( res[0].clientY - rect.top ) / ( rect.bottom - rect.top ) * this.cx.canvas.height )
};
const currentPos = {
x: Math.floor( ( res[1].clientX - rect.left ) / ( rect.right - rect.left ) * this.cx.canvas.width ),
y: Math.floor( ( res[1].clientY - rect.top ) / ( rect.bottom - rect.top ) * this.cx.canvas.height )
};
其他回答
我推荐这个链接 http://miloq.blogspot.in/2011/05/coordinates-mouse-click-canvas.html
<style type="text/css">
#canvas{background-color: #000;}
</style>
<script type="text/javascript">
document.addEventListener("DOMContentLoaded", init, false);
function init()
{
var canvas = document.getElementById("canvas");
canvas.addEventListener("mousedown", getPosition, false);
}
function getPosition(event)
{
var x = new Number();
var y = new Number();
var canvas = document.getElementById("canvas");
if (event.x != undefined && event.y != undefined)
{
x = event.x;
y = event.y;
}
else // Firefox method to get the position
{
x = event.clientX + document.body.scrollLeft +
document.documentElement.scrollLeft;
y = event.clientY + document.body.scrollTop +
document.documentElement.scrollTop;
}
x -= canvas.offsetLeft;
y -= canvas.offsetTop;
alert("x: " + x + " y: " + y);
}
</script>
你可以这样做:
var canvas = yourCanvasElement;
var mouseX = (event.clientX - (canvas.offsetLeft - canvas.scrollLeft)) - 2;
var mouseY = (event.clientY - (canvas.offsetTop - canvas.scrollTop)) - 2;
这将为您提供鼠标指针的确切位置。
更新(5/5/16):应该使用patriques的答案,因为它既简单又可靠。
Since the canvas isn't always styled relative to the entire page, the canvas.offsetLeft/Top doesn't always return what you need. It will return the number of pixels it is offset relative to its offsetParent element, which can be something like a div element containing the canvas with a position: relative style applied. To account for this you need to loop through the chain of offsetParents, beginning with the canvas element itself. This code works perfectly for me, tested in Firefox and Safari but should work for all.
function relMouseCoords(event){
var totalOffsetX = 0;
var totalOffsetY = 0;
var canvasX = 0;
var canvasY = 0;
var currentElement = this;
do{
totalOffsetX += currentElement.offsetLeft - currentElement.scrollLeft;
totalOffsetY += currentElement.offsetTop - currentElement.scrollTop;
}
while(currentElement = currentElement.offsetParent)
canvasX = event.pageX - totalOffsetX;
canvasY = event.pageY - totalOffsetY;
return {x:canvasX, y:canvasY}
}
HTMLCanvasElement.prototype.relMouseCoords = relMouseCoords;
最后一行可以方便地获取相对于canvas元素的鼠标坐标。要得到有用的坐标只需要
coords = canvas.relMouseCoords(event);
canvasX = coords.x;
canvasY = coords.y;
根据最新的Quirksmode,所有主流浏览器都支持clientX和clientY方法。 所以,它开始了-在滚动条页面上的滚动div中工作的良好工作代码:
function getCursorPosition(canvas, event) {
var x, y;
canoffset = $(canvas).offset();
x = event.clientX + document.body.scrollLeft + document.documentElement.scrollLeft - Math.floor(canoffset.left);
y = event.clientY + document.body.scrollTop + document.documentElement.scrollTop - Math.floor(canoffset.top) + 1;
return [x,y];
}
这也需要jQuery $(canvas).offset()。
Edit 2018:这个答案很老了,它使用检查不再需要的旧浏览器,因为clientX和clienti属性在所有当前的浏览器中都有效。您可能想要查看Patriques Answer,以获得一个更简单、更近期的解决方案。
最初的回答: 正如我当时发现的一篇文章所描述的那样,但现在已经不存在了:
var x;
var y;
if (e.pageX || e.pageY) {
x = e.pageX;
y = e.pageY;
}
else {
x = e.clientX + document.body.scrollLeft + document.documentElement.scrollLeft;
y = e.clientY + document.body.scrollTop + document.documentElement.scrollTop;
}
x -= gCanvasElement.offsetLeft;
y -= gCanvasElement.offsetTop;
对我来说效果很好。