我有这样的代码:
def hello():
return 'Hi :)'
我如何直接从命令行运行它?
我有这样的代码:
def hello():
return 'Hi :)'
我如何直接从命令行运行它?
当前回答
我需要在命令行上使用各种python实用程序(range, string等),并为此专门编写了pyfunc工具。你可以用它来丰富你的命令行使用经验:
$ pyfunc -m range -a 1 7 2
1
3
5
$ pyfunc -m string.upper -a test
TEST
$ pyfunc -m string.replace -a 'analyze what' 'what' 'this'
analyze this
其他回答
这个脚本类似于这里的其他答案,但它也列出了可用的函数,带有参数和文档字符串:
"""Small script to allow functions to be called from the command line.
Run this script without argument to list the available functions:
$ python many_functions.py
Available functions in many_functions.py:
python many_functions.py a : Do some stuff
python many_functions.py b : Do another stuff
python many_functions.py c x y : Calculate x + y
python many_functions.py d : ?
Run this script with arguments to try to call the corresponding function:
$ python many_functions.py a
Function a
$ python many_functions.py c 3 5
3 + 5 = 8
$ python many_functions.py z
Function z not found
"""
import sys
import inspect
#######################################################################
# Your functions here #
#######################################################################
def a():
"""Do some stuff"""
print("Function a")
def b():
"""Do another stuff"""
a()
print("Function b")
def c(x, y):
"""Calculate x + y"""
print(f"{x} + {y} = {int(x) + int(y)}")
def d():
# No doc
print("Function d")
#######################################################################
# Some logic to find and display available functions #
#######################################################################
def _get_local_functions():
local_functions = {}
for name, obj in inspect.getmembers(sys.modules[__name__]):
if inspect.isfunction(obj) and not name.startswith('_') and obj.__module__ == __name__:
local_functions[name] = obj
return local_functions
def _list_functions(script_name):
print(f"Available functions in {script_name}:")
for name, f in _get_local_functions().items():
print()
arguments = inspect.signature(f).parameters
print(f"python {script_name} {name} {' '.join(arguments)} : {f.__doc__ or '?'}")
if __name__ == '__main__':
script_name, *args = sys.argv
if args:
functions = _get_local_functions()
function_name = args.pop(0)
if function_name in functions:
function = functions[function_name]
function(*args)
else:
print(f"Function {function_name} not found")
_list_functions(script_name)
else:
_list_functions(script_name)
运行不带参数的脚本列出可用的函数:
$ python many_functions.py
Available functions in many_functions.py:
python many_functions.py a : Do some stuff
python many_functions.py b : Do another stuff
python many_functions.py c x y : Calculate x + y
python many_functions.py d : ?
运行这个带有参数的脚本,尝试调用相应的函数:
$ python many_functions.py a
Function a
$ python many_functions.py c 3 5
3 + 5 = 8
$ python many_functions.py z
Function z not found
使用-c(命令)参数(假设你的文件名为foo.py):
$ python -c 'import foo; print foo.hello()'
或者,如果你不关心命名空间污染:
$ python -c 'from foo import *; print hello()'
中间立场是:
$ python -c 'from foo import hello; print hello()'
此函数不能从命令行运行,因为它返回的值将不被传递。您可以删除返回并使用print代替
使用python-c工具(pip install python-c),然后简单地写:
$ python-c foo 'hello()'
或者如果你的python文件中没有函数名冲突:
$ python-c 'hello()'
将此代码片段添加到脚本底部
def myfunction():
...
if __name__ == '__main__':
globals()[sys.argv[1]]()
现在可以通过运行来调用函数
python myscript.py myfunction
这是因为您将命令行参数(函数名的字符串)传递到locals中,locals是一个包含当前局部符号表的字典。最后的parantheses将使函数被调用。
更新:如果你想让函数从命令行接受一个参数,你可以传入sys。Argv[2]像这样:
def myfunction(mystring):
print(mystring)
if __name__ == '__main__':
globals()[sys.argv[1]](sys.argv[2])
这样,运行python myscript.py myfunction "hello"将输出hello。