解决这个问题的另一种方法是不依赖于显示的正确返回值，而是依赖于Android资源的解析。

在res/values-land和res/values-port文件夹中创建文件layouts.xml，内容如下:

res / values-land / layouts.xml:

<?xml version="1.0" encoding="utf-8"?>
<resources>
    <bool name="is_landscape">true</bool>
</resources>

res / values-port / layouts.xml:

<?xml version="1.0" encoding="utf-8"?>
<resources>
    <bool name="is_landscape">false</bool>
</resources>

在你的源代码中，你现在可以访问当前方向，如下所示:

context.getResources().getBoolean(R.bool.is_landscape)

你可以使用这个(基于这里):

public static boolean isPortrait(Activity activity) {
    final int currentOrientation = getCurrentOrientation(activity);
    return currentOrientation == ActivityInfo.SCREEN_ORIENTATION_REVERSE_PORTRAIT || currentOrientation == ActivityInfo.SCREEN_ORIENTATION_PORTRAIT;
}

public static int getCurrentOrientation(Activity activity) {
    //code based on https://www.captechconsulting.com/blog/eric-miles/programmatically-locking-android-screen-orientation
    final Display display = activity.getWindowManager().getDefaultDisplay();
    final int rotation = display.getRotation();
    final Point size = new Point();
    display.getSize(size);
    int result;
    if (rotation == Surface.ROTATION_0
            || rotation == Surface.ROTATION_180) {
        // if rotation is 0 or 180 and width is greater than height, we have
        // a tablet
        if (size.x > size.y) {
            if (rotation == Surface.ROTATION_0) {
                result = ActivityInfo.SCREEN_ORIENTATION_LANDSCAPE;
            } else {
                result = ActivityInfo.SCREEN_ORIENTATION_REVERSE_LANDSCAPE;
            }
        } else {
            // we have a phone
            if (rotation == Surface.ROTATION_0) {
                result = ActivityInfo.SCREEN_ORIENTATION_PORTRAIT;
            } else {
                result = ActivityInfo.SCREEN_ORIENTATION_REVERSE_PORTRAIT;
            }
        }
    } else {
        // if rotation is 90 or 270 and width is greater than height, we
        // have a phone
        if (size.x > size.y) {
            if (rotation == Surface.ROTATION_90) {
                result = ActivityInfo.SCREEN_ORIENTATION_LANDSCAPE;
            } else {
                result = ActivityInfo.SCREEN_ORIENTATION_REVERSE_LANDSCAPE;
            }
        } else {
            // we have a tablet
            if (rotation == Surface.ROTATION_90) {
                result = ActivityInfo.SCREEN_ORIENTATION_REVERSE_PORTRAIT;
            } else {
                result = ActivityInfo.SCREEN_ORIENTATION_PORTRAIT;
            }
        }
    }
    return result;
}

有很多方法可以做到这一点，这段代码适合我

 if (this.getWindow().getWindowManager().getDefaultDisplay()
                .getOrientation() == ActivityInfo.SCREEN_ORIENTATION_PORTRAIT) {
             // portrait mode
} else if (this.getWindow().getWindowManager().getDefaultDisplay()
                .getOrientation() == ActivityInfo.SCREEN_ORIENTATION_LANDSCAPE) {
                      // landscape
        }

我认为这个解决方案很容易检验的是景观

 public static boolean isLandscape(Context context) {
    final int rotation = ((WindowManager) context.getSystemService(Context.WINDOW_SERVICE)).getDefaultDisplay().getRotation();
    
    if (rotation == Surface.ROTATION_0 || rotation == Surface.ROTATION_180) {
        return false;
    }

    return rotation == Surface.ROTATION_90 || rotation == Surface.ROTATION_270;
}

用这种方法，

    int orientation = getResources().getConfiguration().orientation;
    String Orintaion = "";
    switch (orientation)
    {
        case Configuration.ORIENTATION_UNDEFINED: Orintaion = "Undefined"; break;
        case Configuration.ORIENTATION_LANDSCAPE: Orintaion = "Landscrape"; break;
        case Configuration.ORIENTATION_PORTRAIT:  Orintaion = "Portrait"; break;
        default: Orintaion = "Square";break;
    }

在字符串中，你有方向

简单易行:)

制作2个xml布局(即纵向和横向) 在java文件中，写入: private int intOrientation; 在onCreate方法和setContentView之前写入: intOrientation = getResources().getConfiguration().orientation; if (intOrientation == Configuration.ORIENTATION_PORTRAIT) setContentView (R.layout.activity_main); 其他的 setContentView (R.layout.layout_land);//我测试了它，它工作正常。