如何验证一个电子邮件地址在swift?

有人知道如何在Swift中验证电子邮件地址吗?我找到了这个代码:

- (BOOL) validEmail:(NSString*) emailString {

    if([emailString length]==0){
        return NO;
    }

    NSString *regExPattern = @"[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,4}";

    NSRegularExpression *regEx = [[NSRegularExpression alloc] initWithPattern:regExPattern options:NSRegularExpressionCaseInsensitive error:nil];
    NSUInteger regExMatches = [regEx numberOfMatchesInString:emailString options:0 range:NSMakeRange(0, [emailString length])];

    NSLog(@"%i", regExMatches);
    if (regExMatches == 0) {
        return NO;
    } else {
        return YES;
    }
}

但我无法翻译成斯威夫特。

当前回答

我喜欢扩展

   extension String {

func isValidateEmail() -> Bool {
    let emailFormat = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}"
    let emailPredicate = NSPredicate(format:"SELF MATCHES %@", emailFormat)
    return emailPredicate.evaluate(with: self)
}

}

用法:

if emailid.text!.isValidateEmail() == false(){
 //do what ever you want if string is not matched.

}

2018-05-15 18:01:05

其他回答

我建议使用它作为String的扩展:

extension String {    
    public var isEmail: Bool {
        let dataDetector = try? NSDataDetector(types: NSTextCheckingResult.CheckingType.link.rawValue)

        let firstMatch = dataDetector?.firstMatch(in: self, options: NSRegularExpression.MatchingOptions.reportCompletion, range: NSRange(location: 0, length: length))

        return (firstMatch?.range.location != NSNotFound && firstMatch?.url?.scheme == "mailto")
    }

    public var length: Int {
        return self.characters.count
    }
}

要使用它:

if "hodor@gameofthrones.com".isEmail { // true
    print("Hold the Door")
}

2016-06-21 12:55:37

//Email validation
func validateEmail(enterEmail:String) -> Bool{
    let emailFormat = "[A-Z0-9a-z._%+-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,64}"
    let emailPredicate = NSPredicate(format:"SELF MATCHES %@",emailFormat)
    return emailPredicate.evaluate(with:enterEmail)
}

100%工作和测试

2018-03-08 09:24:07

斯威夫特5

 func isValidEmailAddress(emailAddressString: String) -> Bool {

 var returnValue = true
 let emailRegEx = "[A-Z0-9a-z.-_]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,3}"

 do {
        let regex = try NSRegularExpression(pattern: emailRegEx)
        let nsString = emailAddressString as NSString
        let results = regex.matches(in: emailAddressString, range: NSRange(location: 0, length: nsString.length))

        if results.count == 0
        {
            returnValue = false
        }

    } catch let error as NSError {
        print("invalid regex: \(error.localizedDescription)")
        returnValue = false
    }

    return  returnValue
}

然后:

let validEmail = isValidEmailAddress(emailAddressString: "your@email.com")
print(validEmail)

2019-06-25 17:17:11

完美的正则表达式，如谷歌电子邮件

"^[A-Z0-9a-z][a-zA-Z0-9_.-]+@[A-Za-z0-9.-]+\\.[A-Za-z]{2,}"

2017-09-22 07:58:04

创建简单的扩展:

extension NSRegularExpression {

    convenience init(pattern: String) {
        try! self.init(pattern: pattern, options: [])
    }
}

extension String {

    var isValidEmail: Bool {
        return isMatching(expression: NSRegularExpression(pattern: "^[A-Z0-9a-z\\._%+-]+@([A-Za-z0-9-]+\\.)+[A-Za-z]{2,4}$"))
    }

    //MARK: - Private

    private func isMatching(expression: NSRegularExpression) -> Bool {
        return expression.numberOfMatches(in: self, range: NSRange(location: 0, length: characters.count)) > 0
    }
}

例子:

"b@bb.pl".isValidEmail //true
"b@bb".isValidEmail //false

你可以扩展以下扩展到任何你需要的:isValidPhoneNumber, isValidPassword等…

2017-05-10 09:44:08

如何验证一个电子邮件地址在swift?

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