如何可能生成一个随机的,唯一的字符串使用数字和字母用于验证链接?就像你在一个网站上创建了一个账户,它会给你发一封带有链接的电子邮件,你必须点击那个链接才能验证你的账户

如何使用PHP生成其中一个?


当前回答

一个简单的解决方案是通过丢弃非字母数字字符将64进制转换为字母数字。

它使用random_bytes()来获得加密安全的结果。

function random_alphanumeric(int $length): string
{
    $result='';
    do
    {
        //Base 64 produces 4 characters for each 3 bytes, so most times this will give enough bytes in a single pass
        $bytes=random_bytes(($length+3-strlen($result))*2);
        //Discard non-alhpanumeric characters
        $result.=str_replace(['/','+','='],['','',''],base64_encode($bytes));
        //Keep adding characters until the string is long enough
        //Add a few extra because the last 2 or 3 characters of a base 64 string tend to be less diverse
    }while(strlen($result)<$length+3);
    return substr($result,0,$length);
}

编辑:我只是重新审视了一下,因为我需要一些更灵活的东西。这里有一个解决方案,执行得比上面的好一点,并提供了指定ASCII字符集的任何子集的选项:

<?php
class RandomText
{
    protected
        $allowedChars,
        //Maximum index to use
        $allowedCount,
        //Index values will be taken from a pool of this size
        //It is a power of 2 to keep the distribution of values even
        $distributionSize,
        //This many characters will be generated for each output character
        $ratio;
    /**
     * @param string $allowedChars characters to choose from
     */
    public function __construct(string $allowedChars)
    {
        $this->allowedCount = strlen($allowedChars);
        if($this->allowedCount < 1 || $this->allowedCount > 256) throw new \Exception('At least 1 and no more than 256 allowed character(s) must be specified.');
        $this->allowedChars = $allowedChars;
        //Find the power of 2 equal or greater than the number of allowed characters
        $this->distributionSize = pow(2,ceil(log($this->allowedCount, 2)));
        //Generating random bytes is the expensive part of this algorithm
        //In most cases some will be wasted so it is helpful to produce some extras, but not too many
        //On average, this is how many characters needed to produce 1 character in the allowed set
        //50% of the time, more characters will be needed. My tests have shown this to perform well.
        $this->ratio = $this->distributionSize / $this->allowedCount;
    }

    /**
     * @param int $length string length of required result
     * @return string random text
     */
    public function get(int $length) : string
    {
        if($length < 1) throw new \Exception('$length must be >= 1.');
        $result = '';
        //Keep track of result length to prevent having to compute strlen()
        $l = 0;
        $indices = null;
        $i = null;
        do
        {
            //Bytes will be used to index the character set. Convert to integers.
            $indices = unpack('C*', random_bytes(ceil(($length - $l) * $this->ratio)));
            foreach($indices as $i)
            {
                //Reduce to the smallest range that gives an even distribution
                $i %= $this->distributionSize;
                //If the index is within the range of characters, add one char to the string
                if($i < $this->allowedCount)
                {
                    $l++;
                    $result .= $this->allowedChars[$i];
                }
                if($l >= $length) break;
            }
        }while($l < $length);
        return $result;
    }
}

其他回答

这是我在我的一个项目上使用的,它工作得很好,它生成了一个唯一的随机TOKEN:

$timestampz=time();

function generateRandomString($length = 60) {
    $characters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
    $charactersLength = strlen($characters);
    $randomString = '';
    for ($i = 0; $i < $length; $i++) {
        $randomString .= $characters[rand(0, $charactersLength - 1)];
    }
    return $randomString;
}


$tokenparta = generateRandomString();


$token = $timestampz*3 . $tokenparta;

echo $token;

请注意,我将时间戳乘以3,以引起用户的困惑,他们可能想知道这个令牌是如何生成的;)

我希望它能帮助你:)

这是一个有趣的问题

public function randomStr($length = 16) {
    $string = '';
        
    while (($len = strlen($string)) < $length) {
        $size = $length - $len;
            
        $bytes = random_bytes($size);
            
        $string .= substr(str_replace(['/', '+', '='], '', base64_encode($bytes)), 0, $size);
    }
        
        return $string;
}

从laravel偷来的

function codeGenerate() {
  $randCode  = (string)mt_rand(1000,9999);
  $randChar  = rand(65,90);
  $randInx   = rand(0,3);
  $randCode[$randInx] = chr($randChar);
  return $randCode;
}
echo codeGenerate();

输出

38I7
33V7
E836
736U

我认为这是最好的方法。

str_shuffle(md5(rand(0,100000)))

生成一个随机数使用 你最喜欢的随机数 发电机 乘除 得到一个与数字匹配的数字 你的代码字母表中的字符 将该索引处的项插入 你的代码字母。 重复1),直到你有你想要的长度 想要

例如(伪代码)

int myInt = random(0, numcharacters)
char[] codealphabet = 'ABCDEF12345'
char random = codealphabet[i]
repeat until long enough