ECMAScript 6 引入了许可声明。

我听说它被描述为一个当地变量,但我仍然不确定它是如何行为不同于 var 关键词。

什么是差异?什么时候应该被允许使用而不是 var?


当前回答

让它是 es6的一部分,这些功能将以轻松的方式解释差异。

function varTest() {
  var x = 1;
  if (true) {
    var x = 2;  // same variable!
    console.log(x);  // 2
  }
  console.log(x);  // 2
}

function letTest() {
  let x = 1;
  if (true) {
    let x = 2;  // different variable
    console.log(x);  // 2
  }
  console.log(x);  // 1
}

其他回答

这个解释是从我在Medium上写的一篇文章中得出的:

Hoisting 是一个 JavaScript 机制,在其中变量和函数声明被转移到其范围的顶部,由分数者将源代码列入一个中间代表性之前,实际的代码执行由 JavaScript 解释器开始。

使用 var 声明定义的变量在其定义的整个函数中已知,从函数的开始。 (*) 使用 let 声明定义的变量仅在其定义的区块中已知,从其定义的时刻开始。

// i IS NOT known here
// j IS NOT known here
// k IS known here, but undefined
// l IS NOT known here

function loop(arr) {
    // i IS known here, but undefined
    // j IS NOT known here
    // k IS known here, but has a value only the second time loop is called
    // l IS NOT known here

    for( var i = 0; i < arr.length; i++ ) {
        // i IS known here, and has a value
        // j IS NOT known here
        // k IS known here, but has a value only the second time loop is called
        // l IS NOT known here
    };

    // i IS known here, and has a value
    // j IS NOT known here
    // k IS known here, but has a value only the second time loop is called
    // l IS NOT known here

    for( let j = 0; j < arr.length; j++ ) {
        // i IS known here, and has a value
        // j IS known here, and has a value
        // k IS known here, but has a value only the second time loop is called
        // l IS NOT known here
    };

    // i IS known here, and has a value
    // j IS NOT known here
    // k IS known here, but has a value only the second time loop is called
    // l IS NOT known here
}

loop([1,2,3,4]);

for( var k = 0; k < arr.length; k++ ) {
    // i IS NOT known here
    // j IS NOT known here
    // k IS known here, and has a value
    // l IS NOT known here
};

for( let l = 0; l < arr.length; l++ ) {
    // i IS NOT known here
    // j IS NOT known here
    // k IS known here, and has a value
    // l IS known here, and has a value
};

loop([1,2,3,4]);

// i IS NOT known here
// j IS NOT known here
// k IS known here, and has a value
// l IS NOT known here


今天使用安全吗?

有些人会说,在未来,我们只会使用让陈述,而这些陈述会变得过时。JavaScript老师Kyle Simpson写了一篇非常复杂的文章,他认为为什么不会这样。

事实上,我们实际上需要问自己是否安全使用放弃声明,这个问题的答案取决于你的环境:

此分類上一篇


如何跟踪浏览器支持


我想将这些关键词链接到执行背景,因为执行背景在这一切中都很重要。执行背景有两个阶段:创作阶段和执行阶段。

在创建阶段的执行背景, var, let 和 const 将仍然存储其变量在记忆中与未确定的值在该执行背景的变量环境中. 差异在执行阶段. 如果您使用参考一个变量定义为 var 之前它被分配一个值,它将只是不确定的。

function a(){
    b;
    let b;
}
a();
> Uncaught ReferenceError: b is not defined

函数 VS 区块范围:

与 var 和 let 的主要区别是,与 var 宣言的变量是函数分解的,而与 let 宣言的函数是区块分解的。

function testVar () {
  if(true) {
    var foo = 'foo';
  }

  console.log(foo);
}

testVar();  
// logs 'foo'


function testLet () {
  if(true) {
    let bar = 'bar';
  }

  console.log(bar);
}

testLet(); 
// reference error
// bar is scoped to the block of the if statement 

当第一个函数测试Var 被称为变量 foo 时,与 var 声明,仍然在 if 声明之外可用。

与Let的变量:

当第二个函数测试Let被称为变量栏,用Let表示,仅可在 if 声明中访问,因为用Let表示的变量是区块分开的(其中一个区块是曲线条之间的代码,例如,如果{},为{},函数{})。

请不要让变量变量:

变量与不要被抓住:

console.log(letVar);

let letVar = 10;
// referenceError, the variable doesn't get hoisted

与 var do 相容的变量:

console.log(varVar);

var varVar = 10;
// logs undefined, the variable gets hoisted

var bar = 5;
let foo  = 10;

console.log(bar); // logs 5
console.log(foo); // logs 10

console.log(window.bar);  
// logs 5, variable added to window object

console.log(window.foo);
// logs undefined, variable not added to window object

以下两个功能可以显示差异:

function varTest() {
    var x = 31;
    if (true) {
        var x = 71;  // Same variable!
        console.log(x);  // 71
    }
    console.log(x);  // 71
}

function letTest() {
    let x = 31;
    if (true) {
        let x = 71;  // Different variable
        console.log(x);  // 71
    }
    console.log(x);  // 31
}