我如何写一个列表文件?writelines()不插入换行符,所以我需要这样做:
f.writelines([f"{line}\n" for line in lines])
我如何写一个列表文件?writelines()不插入换行符,所以我需要这样做:
f.writelines([f"{line}\n" for line in lines])
当前回答
我建议这个解决方案。
with open('your_file.txt', 'w') as f:
list(map(lambda item : f.write("%s\n" % item),my_list))
其他回答
我建议这个解决方案。
with open('your_file.txt', 'w') as f:
list(map(lambda item : f.write("%s\n" % item),my_list))
将stdout重定向到一个文件也可以用于此目的:
from contextlib import redirect_stdout
with open('test.txt', 'w') as f:
with redirect_stdout(f):
for i in range(mylst.size):
print(mylst[i])
另一种迭代和添加换行符的方法:
for item in items:
filewriter.write(f"{item}" + "\n")
with open ("test.txt","w")as fp:
for line in list12:
fp.write(line+"\n")
在一般情况下
下面是writelines()方法的语法
fileObject.writelines( sequence )
例子
#!/usr/bin/python
# Open a file
fo = open("foo.txt", "rw+")
seq = ["This is 6th line\n", "This is 7th line"]
# Write sequence of lines at the end of the file.
line = fo.writelines( seq )
# Close opend file
fo.close()
参考
http://www.tutorialspoint.com/python/file_writelines.htm