如果你想删除/忽略字符串中的字符，例如，你有这个字符串，

“[11:L: 0]”

来自web API响应或类似的东西，比如CSV文件，假设你在使用请求

import requests
udid = 123456
url = 'http://webservices.yourserver.com/action/id-' + udid
s = requests.Session()
s.verify = False
resp = s.get(url, stream=True)
content = resp.content

循环并去除不需要的字符:

for line in resp.iter_lines():
  line = line.replace("[", "")
  line = line.replace("]", "")
  line = line.replace('"', "")

可选的分割，你将能够单独读取值:

listofvalues = line.split(':')

现在访问每个值更容易了:

print listofvalues[0]
print listofvalues[1]
print listofvalues[2]

这将打印

11 l 0

您可以简单地使用列表推导式。

假设你有字符串:my name is，你想删除字符m.使用以下代码:

"".join([x for x in "my name is" if x is not 'm'])

def kill_char(string, n): # n = position of which character you want to remove
    begin = string[:n]    # from beginning to n (n not included)
    end = string[n+1:]    # n+1 through end of string
    return begin + end
print kill_char("EXAMPLE", 3)  # "M" removed

我在这里某处见过。

字符串在Python中是不可变的，所以这两个选项的意思基本上是一样的。

字符串是不可变的。但是你可以把它们转换成一个可变的列表，然后在你改变它之后再把它转换回字符串。

s = "this is a string"

l = list(s)  # convert to list

l[1] = ""    # "delete" letter h (the item actually still exists but is empty)
l[1:2] = []  # really delete letter h (the item is actually removed from the list)
del(l[1])    # another way to delete it

p = l.index("a")  # find position of the letter "a"
del(l[p])         # delete it

s = "".join(l)  # convert back to string

您还可以创建一个新字符串，就像其他人演示的那样，从现有字符串中取出所需字符以外的所有内容。

如果你想删除/忽略字符串中的字符，例如，你有这个字符串，

“[11:L: 0]”

来自web API响应或类似的东西，比如CSV文件，假设你在使用请求

import requests
udid = 123456
url = 'http://webservices.yourserver.com/action/id-' + udid
s = requests.Session()
s.verify = False
resp = s.get(url, stream=True)
content = resp.content

循环并去除不需要的字符:

for line in resp.iter_lines():
  line = line.replace("[", "")
  line = line.replace("]", "")
  line = line.replace('"', "")

可选的分割，你将能够单独读取值:

listofvalues = line.split(':')

现在访问每个值更容易了:

print listofvalues[0]
print listofvalues[1]
print listofvalues[2]

这将打印

11 l 0