我在c#中寻找树或图数据结构,但我猜没有提供。使用c# 2.0的数据结构的广泛检查。是否有一个方便的库通常用于提供这个功能?也许可以通过策略模式来解决文章中提出的问题。

我觉得实现我自己的树有点傻,就像实现我自己的数组列表一样。

我只想要一个一般的树,它可以是不平衡的。想象一个目录树。C5看起来很漂亮,但它们的树结构似乎被实现为更适合搜索的平衡红黑树,而不是表示节点的层次结构。


当前回答

我已经使用上面的NTree类添加了一个完整的解决方案和示例。我还添加了AddChild方法…

    public class NTree<T>
    {
        public T data;
        public LinkedList<NTree<T>> children;

        public NTree(T data)
        {
            this.data = data;
            children = new LinkedList<NTree<T>>();
        }

        public void AddChild(T data)
        {
            var node = new NTree<T>(data) { Parent = this };
            children.AddFirst(node);
        }

        public NTree<T> Parent { get; private set; }

        public NTree<T> GetChild(int i)
        {
            foreach (NTree<T> n in children)
                if (--i == 0)
                    return n;
            return null;
        }

        public void Traverse(NTree<T> node, TreeVisitor<T> visitor, string t, ref NTree<T> r)
        {
            visitor(node.data, node, t, ref r);
            foreach (NTree<T> kid in node.children)
                Traverse(kid, visitor, t, ref r);
        }
    }

    public static void DelegateMethod(KeyValuePair<string, string> data, NTree<KeyValuePair<string, string>> node, string t, ref NTree<KeyValuePair<string, string>> r)
    {
        string a = string.Empty;
        if (node.data.Key == t)
        {
            r = node;
            return;
        }
    }

使用它

 NTree<KeyValuePair<string, string>> ret = null;
 tree.Traverse(tree, DelegateMethod, node["categoryId"].InnerText, ref ret);

其他回答

如果要在GUI上显示这个树,可以使用TreeView和TreeNode。(我认为从技术上讲,你可以创建一个TreeNode而不把它放在GUI上,但它确实比一个简单的自定义TreeNode实现有更多的开销。)

见https://github.com/YaccConstructor/QuickGraph(原http://quickgraph.codeplex.com/)

QuickGraph为。net 2.0及更高版本提供了通用的有向/无向图数据结构和算法。QuickGraph提供了深度优先搜索、宽度优先搜索、A*搜索、最短路径、k-最短路径、最大流量、最小生成树、最小公共祖先等算法……QuickGraph支持MSAGL, GLEE和Graphviz来呈现图形,序列化到GraphML等。

delegate void TreeVisitor<T>(T nodeData);

class NTree<T>
{
    private T data;
    private LinkedList<NTree<T>> children;

    public NTree(T data)
    {
         this.data = data;
        children = new LinkedList<NTree<T>>();
    }

    public void AddChild(T data)
    {
        children.AddFirst(new NTree<T>(data));
    }

    public NTree<T> GetChild(int i)
    {
        foreach (NTree<T> n in children)
            if (--i == 0)
                return n;
        return null;
    }

    public void Traverse(NTree<T> node, TreeVisitor<T> visitor)
    {
        visitor(node.data);
        foreach (NTree<T> kid in node.children)
            Traverse(kid, visitor);
    }
}

简单的递归实现… < 40行代码… 你只需要在类外保留一个对树根的引用, 或者在另一个类中包装它,也许重命名为TreeNode??

具有通用数据的树

using System;
using System.Collections.Concurrent;
using System.Collections.Generic;
using System.Linq;
using System.Threading;
using System.Threading.Tasks;

public class Tree<T>
{
    public T Data { get; set; }
    public LinkedList<Tree<T>> Children { get; set; } = new LinkedList<Tree<T>>();
    public Task Traverse(Func<T, Task> actionOnNode, int maxDegreeOfParallelism = 1) => Traverse(actionOnNode, new SemaphoreSlim(maxDegreeOfParallelism, maxDegreeOfParallelism));
    private async Task Traverse(Func<T, Task> actionOnNode, SemaphoreSlim semaphore)
    {
        await actionOnNode(Data);
        SafeRelease(semaphore);
        IEnumerable<Task> tasks = Children.Select(async input =>
        {
            await semaphore.WaitAsync().ConfigureAwait(false);
            try
            {
                await input.Traverse(actionOnNode, semaphore).ConfigureAwait(false);
            }
            finally
            {
                SafeRelease(semaphore);
            }
        });
        await Task.WhenAll(tasks);
    }
    private void SafeRelease(SemaphoreSlim semaphore)
    {
        try
        {
            semaphore.Release();
        }
        catch (Exception ex)
        {
            if (ex.Message.ToLower() != "Adding the specified count to the semaphore would cause it to exceed its maximum count.".ToLower())
            {
                throw;
            }
        }
    }

    public async Task<IEnumerable<T>> ToList()
    {
        ConcurrentBag<T> lst = new ConcurrentBag<T>();
        await Traverse(async (data) => lst.Add(data));
        return lst;
    }
    public async Task<int> Count() => (await ToList()).Count();
}



单元测试

using System.Threading.Tasks;
using Xunit;

public class Tree_Tests
{
    [Fact]
    public async Task Tree_ToList_Count()
    {
        Tree<int> head = new Tree<int>();

        Assert.NotEmpty(await head.ToList());
        Assert.True(await head.Count() == 1);

        // child
        var child = new Tree<int>();
        head.Children.AddFirst(child);
        Assert.True(await head.Count() == 2);
        Assert.NotEmpty(await head.ToList());

        // grandson
        child.Children.AddFirst(new Tree<int>());
        child.Children.AddFirst(new Tree<int>());
        Assert.True(await head.Count() == 4);
        Assert.NotEmpty(await head.ToList());
    }

    [Fact]
    public async Task Tree_Traverse()
    {
        Tree<int> head = new Tree<int>() { Data = 1 };

        // child
        var child = new Tree<int>() { Data = 2 };
        head.Children.AddFirst(child);

        // grandson
        child.Children.AddFirst(new Tree<int>() { Data = 3 });
        child.Children.AddLast(new Tree<int>() { Data = 4 });

        int counter = 0;
        await head.Traverse(async (data) => counter += data);
        Assert.True(counter == 10);

        counter = 0;
        await child.Traverse(async (data) => counter += data);
        Assert.True(counter == 9);

        counter = 0;
        await child.Children.First!.Value.Traverse(async (data) => counter += data);
        Assert.True(counter == 3);

        counter = 0;
        await child.Children.Last!.Value.Traverse(async (data) => counter += data);
        Assert.True(counter == 4);
    }
}

如果你需要一个使用较少内存的根树数据结构实现,你可以这样写你的Node类(c++实现):

class Node {
       Node* parent;
       int item; // depending on your needs

       Node* firstChild; //pointer to left most child of node
       Node* nextSibling; //pointer to the sibling to the right
}