Xcode 8, Swift 3:

let gAppVersion = Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") ?? "0"
let gAppBuild = Bundle.main.object(forInfoDictionaryKey: "CFBundleVersion") ?? "0"

我为UIApplication创建了一个扩展。

extension UIApplication {
    static var appVersion: String {
        let versionNumber = Bundle.main.infoDictionary?[IdentifierConstants.InfoPlist.versionNumber] as? String
        let buildNumber = Bundle.main.infoDictionary?[IdentifierConstants.InfoPlist.buildNumber] as? String
        
        let formattedBuildNumber = buildNumber.map {
            return "(\($0))"
        }

        return [versionNumber,formattedBuildNumber].compactMap { $0 }.joined(separator: " ")
    }
}

enum Constants {
    enum InfoPlist {
        static let versionNumber = "CFBundleShortVersionString"
        static let buildNumber = "CFBundleVersion"
    }
}

OP同时要求版本号和版本号。不幸的是，大多数答案都不提供这两个选项。另外，还有一些添加了不必要的扩展方法。这里有一个非常简单的方法，可以解决OP的问题:

// Example output: "1.0 (234)"
private func versionAndBuildNumber() -> String {
  let versionNumber = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String
  let buildNumber = Bundle.main.infoDictionary?["CFBundleVersion"] as? String
  if let versionNumber = versionNumber, let buildNumber = buildNumber {
    return "\(versionNumber) (\(buildNumber))"
  } else if let versionNumber = versionNumber {
    return versionNumber
  } else if let buildNumber = buildNumber {
    return buildNumber
  } else {
    return ""
  }
}

斯威夫特3:

版本号

if let versionNumberString = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String { // do something }

建立数

if let buildNumberString = Bundle.main.infoDictionary?["CFBundleVersion"] as? String { // do something }

我知道这个问题已经有人回答了，但我个人认为这个问题更清晰一些:

斯威夫特3.0:

 if let version = Bundle.main.infoDictionary?["CFBundleShortVersionString"] as? String {
    self.labelVersion.text = version
}

斯威夫特< 2.3

if let version = NSBundle.mainBundle().infoDictionary?["CFBundleShortVersionString"] as? String {
    self.labelVersion.text = version
}

这样，if let版本就负责条件处理(在我的例子中设置标签文本)，如果infoDictionary或CFBundleShortVersionString为nil，则可选的展开将导致代码被跳过。

public var appVersionNumberString: String {
    get {
        return Bundle.main.object(forInfoDictionaryKey: "CFBundleShortVersionString") as! String
    }
}