在Oracle中似乎没有AUTO_INCREMENT的概念,直到并且包括版本11g。

如何在Oracle 11g中创建一个行为像自动递增的列?


当前回答

假设您指的是类似SQL Server标识列的列?

在Oracle中,您可以使用SEQUENCE来实现相同的功能。我看看能不能找到一个好的链接,然后贴在这里。

更新:看起来你自己找到了。这里是链接: http://www.techonthenet.com/oracle/sequences.php

其他回答

FUNCTION GETUNIQUEID_2 RETURN VARCHAR2
AS
v_curr_id NUMBER;
v_inc NUMBER;
v_next_val NUMBER;
pragma autonomous_transaction;
begin 
CREATE SEQUENCE sequnce
START WITH YYMMDD0000000001
INCREMENT BY 1
NOCACHE
select sequence.nextval into v_curr_id from dual;
if(substr(v_curr_id,0,6)= to_char(sysdate,'yymmdd')) then
v_next_val := to_number(to_char(SYSDATE+1, 'yymmdd') || '0000000000');
v_inc := v_next_val - v_curr_id;
execute immediate ' alter sequence sequence increment by ' || v_inc ;
select sequence.nextval into v_curr_id from dual;
execute immediate ' alter sequence sequence increment by 1';
else
dbms_output.put_line('exception : file not found');
end if;
RETURN 'ID'||v_curr_id;
END;
FUNCTION UNIQUE2(
 seq IN NUMBER
) RETURN VARCHAR2
AS
 i NUMBER := seq;
 s VARCHAR2(9);
 r NUMBER(2,0);
BEGIN
  WHILE i > 0 LOOP
    r := MOD( i, 36 );
    i := ( i - r ) / 36;
    IF ( r < 10 ) THEN
      s := TO_CHAR(r) || s;
    ELSE
      s := CHR( 55 + r ) || s;
    END IF;
  END LOOP;
  RETURN 'ID'||LPAD( s, 14, '0' );
END;

假设您指的是类似SQL Server标识列的列?

在Oracle中,您可以使用SEQUENCE来实现相同的功能。我看看能不能找到一个好的链接,然后贴在这里。

更新:看起来你自己找到了。这里是链接: http://www.techonthenet.com/oracle/sequences.php

这是我如何在一个现有的表和列(名为id)上做到这一点:

UPDATE table SET id=ROWNUM;
DECLARE
  maxval NUMBER;
BEGIN
  SELECT MAX(id) INTO maxval FROM table;
  EXECUTE IMMEDIATE 'DROP SEQUENCE table_seq';
  EXECUTE IMMEDIATE 'CREATE SEQUENCE table_seq START WITH '|| TO_CHAR(TO_NUMBER(maxval)+1) ||' INCREMENT BY 1 NOMAXVALUE';
END;
CREATE TRIGGER table_trigger
  BEFORE INSERT ON table
  FOR EACH ROW
BEGIN
  :new.id := table_seq.NEXTVAL;
END;
  create trigger t1_trigger
  before insert on AUDITLOGS
  for each row
   begin
     select t1_seq.nextval into :new.id from dual;
   end;

我只需要改变表名(AUDITLOGS)与你的表名和新的。使用new.column_name标识