如何使用JavaScript解码JWT的有效负载?没有图书馆。令牌只返回一个有效负载对象,前端应用可以使用它。

示例令牌:xxxxxxxxx.XXXXXXXX.xxxxxxxx

结果就是有效载荷:

{exp: 10012016 name: john doe, scope:['admin']}

当前回答

在Node.js (TypeScript)中:

import { TextDecoder } from 'util';

function decode(jwt: string) {
    const { 0: encodedHeader, 1: encodedPayload, 2: signature, length } = jwt.split('.');

    if (length !== 3) {
        throw new TypeError('Invalid JWT');
    }

    const decode = (input: string): JSON => { return JSON.parse(new TextDecoder().decode(new Uint8Array(Buffer.from(input, 'base64')))); };

    return { header: decode(encodedHeader), payload: decode(encodedPayload), signature: signature };
}

与jose在GitHub上的panva,你可以使用最小的导入{解码为base64Decode}从'jose/util/base64url'和替换新的Uint8Array(Buffer.from(输入,'base64'))与base64Decode(输入)。这样代码就可以在浏览器和Node.js中正常工作。

其他回答

function parseJwt(token) {
  var base64Payload = token.split('.')[1];
  var payload = Buffer.from(base64Payload, 'base64');
  return JSON.parse(payload.toString());
}
let payload= parseJwt("eyJhbGciOiJIUzI1NiIsInR5cCI6IkpXVCJ9.eyJzdWIiOiIxMjM0NTY3ODkwIiwibmFtZSI6IkpvaG4gRG9lIiwiaWF0IjoxNTE2MjM5MDIyfQ.SflKxwRJSMeKKF2QT4fwpMeJf36POk6yJV_adQssw5c");
console.log("payload:- ", payload);

如果使用node,你可能需要使用缓冲包:

npm install buffer
var Buffer = require('buffer/').Buffer

解码JSON Web令牌(JWT)的简单NodeJS解决方案

function decodeTokenComponent(value) {
    const buff = new Buffer(value, 'base64')
    const text = buff.toString('ascii')
    return JSON.parse(text)
}

const token = 'xxxxxxxxx.XXXXXXXX.xxxxxxxx'
const [headerEncoded, payloadEncoded, signature] = token.split('.')
const [header, payload] = [headerEncoded, payloadEncoded].map(decodeTokenComponent)

console.log(`header: ${header}`)
console.log(`payload: ${payload}`)
console.log(`signature: ${signature}`)

由于nodejs环境中没有“window”对象, 我们可以使用以下代码行:

let base64Url = token.split('.')[1]; // token you get
let base64 = base64Url.replace('-', '+').replace('_', '/');
let decodedData = JSON.parse(Buffer.from(base64, 'base64').toString('binary'));

它非常适合我。希望能有所帮助。

如果你正在使用Typescript或普通JavaScript,这里有一个零依赖,准备复制粘贴到你的项目简单函数(基于@Rajan Maharjan的回答)。

This answer is particularly good, not only because it does not depend on any npm module, but also because it does not depend an any node.js built-in module (like Buffer) that some other solutions here are using and of course would fail in the browser (unless polyfilled, but there's no reason to do that in the first place). Additionally JSON.parse can fail at runtime and this version (especially in Typescript) will force handling of that. The JSDoc annotations will make future maintainers of your code thankful. :)

/**
 * Returns a JS object representation of a Javascript Web Token from its common encoded
 * string form.
 *
 * @template T the expected shape of the parsed token
 * @param {string} token a Javascript Web Token in base64 encoded, `.` separated form
 * @returns {(T | undefined)} an object-representation of the token
 * or undefined if parsing failed
 */
export function getParsedJwt<T extends object = { [k: string]: string | number }>(
  token: string,
): T | undefined {
  try {
    return JSON.parse(atob(token.split('.')[1]))
  } catch {
    return undefined
  }
}

为了完成,这里还有一个普通的javascript版本:

/**
 * Returns a JS object representation of a Javascript Web Token from its common encoded
 * string form.
 *
 * @param {string} token a Javascript Web Token in base64 encoded, `.` separated form
 * @returns {(object | undefined)} an object-representation of the token
 * or undefined if parsing failed
 */
export function getParsedJwt(token) {
  try {
    return JSON.parse(atob(token.split('.')[1]))
  } catch (error) {
    return undefined
  }
}

简单的功能与试接

const parseJwt = (token) => {
  try {
    return JSON.parse(atob(token.split('.')[1]));
  } catch (e) {
    return null;
  }
};

谢谢!