你不能在一个PHP类中放入两个具有唯一参数签名的__construct函数。我想这样做:

class Student 
{
   protected $id;
   protected $name;
   // etc.

   public function __construct($id){
       $this->id = $id;
      // other members are still uninitialized
   }

   public function __construct($row_from_database){
       $this->id = $row_from_database->id;
       $this->name = $row_from_database->name;
       // etc.
   }
}

PHP中最好的方法是什么?


当前回答

按数据类型调用构造函数:

class A 
{ 
    function __construct($argument)
    { 
       $type = gettype($argument);

       if($type == 'unknown type')
       {
            // type unknown
       }

       $this->{'__construct_'.$type}($argument);
    } 

    function __construct_boolean($argument) 
    { 
        // do something
    }
    function __construct_integer($argument) 
    { 
        // do something
    }
    function __construct_double($argument) 
    { 
        // do something
    }
    function __construct_string($argument) 
    { 
        // do something
    }
    function __construct_array($argument) 
    { 
        // do something
    }
    function __construct_object($argument) 
    { 
        // do something
    }
    function __construct_resource($argument) 
    { 
        // do something
    }

    // other functions

} 

其他回答

你可以这样做:

public function __construct($param)
{
    if(is_int($param)) {
         $this->id = $param;
    } elseif(is_object($param)) {
     // do something else
    }
 }

更现代的方法: 你把独立的类混合成一个,实体和数据水合。 对于你的案例,你应该有两个类:

class Student 
{
   protected $id;
   protected $name;
   // etc.
}
class StudentHydrator
{
   public function hydrate(Student $student, array $data){
      $student->setId($data['id']);
      if(isset($data['name')){
        $student->setName($data['name']);
      }
      // etc. Can be replaced with foreach
      return $student;
   }
}

//usage
$hydrator = new StudentHydrator();
$student = $hydrator->hydrate(new Student(), ['id'=>4]);
$student2 = $hydrator->hydrate(new Student(), $rowFromDB);

另外请注意,您应该使用doctrine或其他已经提供自动实体水合的ORM。 你应该使用依赖注入来跳过手动创建像StudentHydrator这样的对象。

public function __construct() {
    $parameters = func_get_args();
    ...
}

$o = new MyClass('One', 'Two', 3);

现在$ parameters将是一个值为'One', 'Two', 3的数组。

编辑,

我可以加上

func_num_args()

会给出函数的参数个数。

PHP是一种动态语言,因此不能重载方法。你必须像这样检查参数的类型:

class Student 
{
   protected $id;
   protected $name;
   // etc.

   public function __construct($idOrRow){
    if(is_int($idOrRow))
    {
        $this->id = $idOrRow;
        // other members are still uninitialized
    }
    else if(is_array($idOrRow))
    {
       $this->id = $idOrRow->id;
       $this->name = $idOrRow->name;
       // etc.  
    }
}

我知道我在这方面非常晚,但我提出了一个相当灵活的模式,应该允许一些真正有趣和通用的实现。

像往常一样设置类,使用您喜欢的任何变量。

class MyClass{ protected $myVar1; protected $myVar2; public function __construct($obj = null){ if($obj){ foreach (((object)$obj) as $key => $value) { if(isset($value) && in_array($key, array_keys(get_object_vars($this)))){ $this->$key = $value; } } } } } When you make your object just pass an associative array with the keys of the array the same as the names of your vars, like so... $sample_variable = new MyClass([ 'myVar2'=>123, 'i_dont_want_this_one'=> 'This won\'t make it into the class' ]); print_r($sample_variable); The print_r($sample_variable); after this instantiation yields the following: MyClass Object ( [myVar1:protected] => [myVar2:protected] => 123 ) Because we've initialize $group to null in our __construct(...), it is also valid to pass nothing whatsoever into the constructor as well, like so... $sample_variable = new MyClass(); print_r($sample_variable); Now the output is exactly as expected: MyClass Object ( [myVar1:protected] => [myVar2:protected] => ) The reason I wrote this was so that I could directly pass the output of json_decode(...) to my constructor, and not worry about it too much. This was executed in PHP 7.1. Enjoy!