你不能在一个PHP类中放入两个具有唯一参数签名的__construct函数。我想这样做:
class Student
{
protected $id;
protected $name;
// etc.
public function __construct($id){
$this->id = $id;
// other members are still uninitialized
}
public function __construct($row_from_database){
$this->id = $row_from_database->id;
$this->name = $row_from_database->name;
// etc.
}
}
PHP中最好的方法是什么?
正如这里已经展示的,在PHP中有许多方法来声明多个构造函数,但是没有一种方法是正确的(因为PHP技术上不允许这样做)。
但这并不能阻止我们破解这个功能……
下面是另一个例子:
<?php
class myClass {
public function __construct() {
$get_arguments = func_get_args();
$number_of_arguments = func_num_args();
if (method_exists($this, $method_name = '__construct'.$number_of_arguments)) {
call_user_func_array(array($this, $method_name), $get_arguments);
}
}
public function __construct1($argument1) {
echo 'constructor with 1 parameter ' . $argument1 . "\n";
}
public function __construct2($argument1, $argument2) {
echo 'constructor with 2 parameter ' . $argument1 . ' ' . $argument2 . "\n";
}
public function __construct3($argument1, $argument2, $argument3) {
echo 'constructor with 3 parameter ' . $argument1 . ' ' . $argument2 . ' ' . $argument3 . "\n";
}
}
$object1 = new myClass('BUET');
$object2 = new myClass('BUET', 'is');
$object3 = new myClass('BUET', 'is', 'Best.');
使用和理解多个构造函数的最简单方法:
希望这能有所帮助。:)
从PHP 8开始,我们可以使用命名参数:
class Student {
protected int $id;
protected string $name;
public function __construct(int $id = null, string $name = null, array $row_from_database = null) {
if ($id !== null && $name !== null && $row_from_database === null) {
$this->id = $id;
$this->name = $name;
} elseif ($id === null && $name === null
&& $row_from_database !== null
&& array_keys($row_from_database) === [ 'id', 'name' ]
&& is_int($row_from_database['id'])
&& is_string($row_from_database['name'])) {
$this->id = $row_from_database['id'];
$this->name = $row_from_database['name'];
} else {
throw new InvalidArgumentException('Invalid arguments');
}
}
}
$student1 = new Student(id: 3, name: 'abc');
$student2 = new Student(row_from_database: [ 'id' => 4, 'name' => 'def' ]);
通过适当的检查,可以排除无效的参数组合,这样创建的实例在构造函数的末尾是一个有效的实例(但错误只会在运行时检测到)。
我知道我在这方面非常晚,但我提出了一个相当灵活的模式,应该允许一些真正有趣和通用的实现。
像往常一样设置类,使用您喜欢的任何变量。
class MyClass{
protected $myVar1;
protected $myVar2;
public function __construct($obj = null){
if($obj){
foreach (((object)$obj) as $key => $value) {
if(isset($value) && in_array($key, array_keys(get_object_vars($this)))){
$this->$key = $value;
}
}
}
}
}
When you make your object just pass an associative array with the keys of the array the same as the names of your vars, like so...
$sample_variable = new MyClass([
'myVar2'=>123,
'i_dont_want_this_one'=> 'This won\'t make it into the class'
]);
print_r($sample_variable);
The print_r($sample_variable); after this instantiation yields the following:
MyClass Object ( [myVar1:protected] => [myVar2:protected] => 123 )
Because we've initialize $group to null in our __construct(...), it is also valid to pass nothing whatsoever into the constructor as well, like so...
$sample_variable = new MyClass();
print_r($sample_variable);
Now the output is exactly as expected:
MyClass Object ( [myVar1:protected] => [myVar2:protected] => )
The reason I wrote this was so that I could directly pass the output of json_decode(...) to my constructor, and not worry about it too much.
This was executed in PHP 7.1. Enjoy!
让我在这里加一粒沙子
我个人喜欢将构造函数作为返回类(对象)实例的静态函数添加。代码示例如下:
class Person
{
private $name;
private $email;
public static function withName($name)
{
$person = new Person();
$person->name = $name;
return $person;
}
public static function withEmail($email)
{
$person = new Person();
$person->email = $email;
return $person;
}
}
注意,现在你可以像这样创建Person类的实例:
$person1 = Person::withName('Example');
$person2 = Person::withEmail('yo@mi_email.com');
我的代码来自:
http://alfonsojimenez.com/post/30377422731/multiple-constructors-in-php