以下是对Sky Sander的解决方案的轻微修改，允许日期作为字符串输入，并能够显示像“1分钟”而不是“73秒”这样的跨度

var timeSince = function(date) { if (typeof date !== 'object') { date = new Date(date); } var seconds = Math.floor((new Date() - date) / 1000); var intervalType; var interval = Math.floor(seconds / 31536000); if (interval >= 1) { intervalType = 'year'; } else { interval = Math.floor(seconds / 2592000); if (interval >= 1) { intervalType = 'month'; } else { interval = Math.floor(seconds / 86400); if (interval >= 1) { intervalType = 'day'; } else { interval = Math.floor(seconds / 3600); if (interval >= 1) { intervalType = "hour"; } else { interval = Math.floor(seconds / 60); if (interval >= 1) { intervalType = "minute"; } else { interval = seconds; intervalType = "second"; } } } } } if (interval > 1 || interval === 0) { intervalType += 's'; } return interval + ' ' + intervalType; }; var aDay = 24 * 60 * 60 * 1000; console.log(timeSince(new Date(Date.now() - aDay))); console.log(timeSince(new Date(Date.now() - aDay * 2)));

我用js和python写了一个，在两个项目中使用，非常漂亮和简单:一个简单的库(少于2kb)，用于*** time ago语句格式化日期。

简单，小巧，易于使用，并且经过良好测试。

NPM安装timeago.js 从timeago.js导入timeago;//或使用脚本标签 使用API格式。

示例:

var timeagoIns  = timeago();
timeagoIns .format('2016-06-12');

你也可以实时渲染。

var timeagoIns = timeago();
timeagoIns.render(document.querySelectorAll('time'));

function calDateAgo(dString=null){
    //var dString = "2021-04-1 12:00:00";
     
    var d1 = new Date(dString);
    var d2 = new Date();
    var t2 = d2.getTime();
    var t1 = d1.getTime();
    var d1Y = d1.getFullYear();
    var d2Y = d2.getFullYear();
    var d1M = d1.getMonth();
    var d2M = d2.getMonth();
     
    var time_obj = {};
    time_obj.year = d2.getFullYear()-d1.getFullYear();
    time_obj.month = (d2M+12*d2Y)-(d1M+12*d1Y);
    time_obj.week = parseInt((t2-t1)/(24*3600*1000*7));
    time_obj.day = parseInt((t2-t1)/(24*3600*1000));
    time_obj.hour = parseInt((t2-t1)/(3600*1000));
    time_obj.minute = parseInt((t2-t1)/(60*1000));
    time_obj.second = parseInt((t2-t1)/(1000));

    for (const obj_key in time_obj) {
        if(time_obj[obj_key] == 0){
            delete time_obj[obj_key];
        }
    }
    var ago_text = 'just now';

    if(typeof Object.keys(time_obj)[0] != 'undefined'){
        var time_key = Object.keys(time_obj)[0];
        var time_val = time_obj[Object.keys(time_obj)[0]];
        time_key += (time_val > 1) ? 's':'';
        ago_text = time_val+' '+time_key+' ago'; 
    }
    
    return ago_text;
}

在这种情况下可能有点过头了，但如果有机会，moment.js真的很棒!

js是一个javascript datetime库，在这种情况下使用它，你需要做:

moment(yourdate).fromNow()

http://momentjs.com/docs/#/displaying/fromnow/

2018附录:Luxon是一个新的现代图书馆，可能值得一看!

2022年附录:Day.js是一个较新的库，比Luxon轻80%左右，具有类似的功能。

function mdiv(dividend, divisor) {
    return [ Math.floor(dividend/divisor), dividend % divisor ];
}
// pass in milliseconds, gained by Date1.getTime() - Date2.getTime()
// if max_units is two, the result will be, for example
// 2years 12months ago, or 2hours 38minutes ago
// return formated period

function readable_period(ms, max_units=2){
    let [yy, yr] = mdiv(ms, 3.154e10);
    let [mm, mr] = mdiv(yr, 2.628e9);
    let [dd, dr] = mdiv(mr, 8.64e7);
    let [hh, hr] = mdiv(dr, 3.6e6);
    let [tt, ss] = mdiv(hr, 6e4);

    var ymdht = ['year', 'month', 'day', 'hour', 'minute'];
    let res = [];
    [yy, mm, dd, hh, tt].forEach((tis, ii)=>{
        if(res.length === max_units){return};
        if(tis !== 0){
            res.push(tis === 1 ? `${tis}${ymdht[ii]}` : `${tis}${ymdht[ii]}s`);
        }
    });
    return res.length === 0 ? '' : res.join(' ') + ' ago';
}

下面是我所做的(对象返回时间单位及其值):

function timeSince(post_date, reference) { var reference = reference ? new Date(reference) : new Date(), diff = reference - new Date(post_date + ' GMT-0000'), date = new Date(diff), object = { unit: null, value: null }; if (diff < 86400000) { var secs = date.getSeconds(), mins = date.getMinutes(), hours = date.getHours(), array = [ ['second', secs], ['minute', mins], ['hour', hours] ]; } else { var days = date.getDate(), weeks = Math.floor(days / 7), months = date.getMonth(), years = date.getFullYear() - 1970, array = [ ['day', days], ['week', weeks], ['month', months], ['year', years] ]; } for (var i = 0; i < array.length; i++) { array[i][0] += array[i][1] != 1 ? 's' : ''; object.unit = array[i][1] >= 1 ? array[i][0] : object.unit; object.value = array[i][1] >= 1 ? array[i][1] : object.value; } return object; }