我知道以前也有人问过类似的问题,但这个问题有点不同。我有一个未命名对象的数组,其中包含一个命名对象的数组,我需要得到其中“name”为“string 1”的对象。下面是一个示例数组。

var array = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

更新:我应该早点说,但一旦我找到它,我想用一个编辑过的对象替换它。


当前回答

var array = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

var foundValue = array.filter(obj=>obj.name==='string 1');

console.log(foundValue);

其他回答

一行回答。 你可以使用过滤函数来得到结果。

Var数组= [ {name:"string 1", value:"this", other: "that"}, {name:"string 2", value:"this", other: "that"} ]; Console.log (array.filter(function(arr){return arr.name == 'string 1'})[0]);

function getValue(){
    for(var i = 0 ; i< array.length; i++){
        var obj = array[i];
        var arr = array["types"];
        for(var j = 0; j<arr.length;j++ ){
            if(arr[j] == "value"){
                return obj;
            }
        }

    }
}

考虑到您有以下片段:

var array = [
    { name:"string 1", value:"this", other: "that" },
    { name:"string 2", value:"this", other: "that" }
];

您可以使用以下函数来搜索项目

const search = what => array.find(element => element.name === what);

您可以检查是否找到了该项目。

const found = search("string1");
if (found) {
    console.log(found.value, found.other);
} else {
    console.log('No result found');
}

你可以使用npm中的查询对象。您可以使用筛选器搜索对象数组。

const queryable = require('query-objects');

const users = [
    {
      firstName: 'George',
      lastName: 'Eracleous',
      age: 28
    },
    {
      firstName: 'Erica',
      lastName: 'Archer',
      age: 50
    },
    {
      firstName: 'Leo',
      lastName: 'Andrews',
      age: 20
    }
];

const filters = [
    {
      field: 'age',
      value: 30,
      operator: 'lt'
    },
    {
      field: 'firstName',
      value: 'Erica',
      operator: 'equals'
    }
];

// Filter all users that are less than 30 years old AND their first name is Erica
const res = queryable(users).and(filters);

// Filter all users that are less than 30 years old OR their first name is Erica
const res = queryable(users).or(filters);

你可以循环数组并测试该属性: 函数搜索(nameKey, myArray){ For(令i=0;i < myArray.length;我+ +){ if (myArray[i].name === nameKey) { 返回myArray[我]; } } } Const数组= [ {name:"string 1", value:"this", other: "that"}, {name:"string 2", value:"this", other: "that"} ]; const resultObject = search("string 1",数组); console.log (resultObject)