我有一个JSON对象，由AJAX请求返回，我有一些问题与.length，因为它一直返回未定义。只是想知道我是否用对了:
console.log(data.length);
console.log(data.phones.length);
它们都返回undefined，尽管它们是有效的对象。
更新: 返回的JSON对象示例:
{"reqStatus":true,"phones":{"one":{"number":"XXXXXXXXXX","type":"mobile"},"two":{"number":"XXXXXXXXXX","type":"mobile"}}}
当前回答
你可以用这样的东西
var myObject = {'name'：'Kasun'， 'address'：'columbo'，'age'： '29'} var count = Object.keys（myObject）.length; 控制台.log（计数）;
其他回答
用这个
种(jsonObject) . length
你不需要改变JSON格式。
替换:
console.log(data.phones.length);
:
console.log( Object.keys( data.phones ).length ) ;
var json=[{"id":"431","code":"0.85.PSFR01215","price":"2457.77","volume":"23.0","total":"565.29"},{"id":"430","code":"0.85.PSFR00608","price":"1752.45","volume":"4.0","total":"70.1"},{"id":"429","code":"0.84.SMAB00060","price":"4147.5","volume":"2.0","total":"82.95"},{"id":"428","code":"0.84.SMAB00050","price":"4077.5","volume":"3.0","total":"122.32"}]
var obj = JSON.parse(json);
var length = Object.keys(obj).length; //you get length json result 4
$(document).ready(function () {
$('#count_my_data').click(function () {
var count = 0;
while (true) {
try {
var v1 = mydata[count].TechnologyId.toString();
count = count + 1;
}
catch (e)
{ break; }
}
alert(count);
});
});
考虑使用underscore.js。它将允许你检查大小，如:
var data = {one : 1, two : 2, three : 3};
_.size(data);
//=> 3
_.keys(data);
//=> ["one", "two", "three"]
_.keys(data).length;
//=> 3
