步骤1:简单和最快的方法来解析plist在swift 3+

extension Bundle {

    func parsePlist(ofName name: String) -> [String: AnyObject]? {

        // check if plist data available
        guard let plistURL = Bundle.main.url(forResource: name, withExtension: "plist"),
            let data = try? Data(contentsOf: plistURL)
            else {
                return nil
        }

        // parse plist into [String: Anyobject]
        guard let plistDictionary = try? PropertyListSerialization.propertyList(from: data, options: [], format: nil) as? [String: AnyObject] else {
            return nil
        }

        return plistDictionary
    }
}

第二步:使用方法:

Bundle().parsePlist(ofName: "Your-Plist-Name")

在swift 3.0从Plist读取。

func readPropertyList() {
        var propertyListFormat =  PropertyListSerialization.PropertyListFormat.xml //Format of the Property List.
        var plistData: [String: AnyObject] = [:] //Our data
        let plistPath: String? = Bundle.main.path(forResource: "data", ofType: "plist")! //the path of the data
        let plistXML = FileManager.default.contents(atPath: plistPath!)!
        do {//convert the data to a dictionary and handle errors.
            plistData = try PropertyListSerialization.propertyList(from: plistXML, options: .mutableContainersAndLeaves, format: &propertyListFormat) as! [String:AnyObject]

        } catch {
            print("Error reading plist: \(error), format: \(propertyListFormat)")
        }
    }

阅读更多 如何在swift中使用属性列表(. plist)。

你可以使用它，我在github https://github.com/DaRkD0G/LoadExtension中创建了一个简单的字典扩展

extension Dictionary {
    /**
        Load a Plist file from the app bundle into a new dictionary

        :param: File name
        :return: Dictionary<String, AnyObject>?
    */
    static func loadPlistFromProject(filename: String) -> Dictionary<String, AnyObject>? {

        if let path = NSBundle.mainBundle().pathForResource("GameParam", ofType: "plist") {
            return NSDictionary(contentsOfFile: path) as? Dictionary<String, AnyObject>
        }
        println("Could not find file: \(filename)")
        return nil
    }
}

你可以用它来计算负载

/**
  Example function for load Files Plist

  :param: Name File Plist
*/
func loadPlist(filename: String) -> ExampleClass? {
    if let dictionary = Dictionary<String, AnyObject>.loadPlistFromProject(filename) {
        let stringValue = (dictionary["name"] as NSString)
        let intergerValue = (dictionary["score"] as NSString).integerValue
        let doubleValue = (dictionary["transition"] as NSString).doubleValue

        return ExampleClass(stringValue: stringValue, intergerValue: intergerValue, doubleValue: doubleValue)
    }
    return nil
}

斯威夫特4.0

现在可以使用decodedable协议将.plist解码为自定义结构。我将介绍一个基本的例子，对于更复杂的。plist结构，我建议阅读Decodable/Encodable(一个很好的资源是:https://benscheirman.com/2017/06/swift-json/)。

首先将结构设置为.plist文件的格式。对于这个例子，我将考虑一个根级字典和3个条目:1个字符串键“name”，1个Int键“age”，1个布尔键“single”。下面是结构体:

struct Config: Decodable {
    private enum CodingKeys: String, CodingKey {
        case name, age, single
    }

    let name: String
    let age: Int
    let single: Bool
}

很简单。现在是最酷的部分。使用PropertyListDecoder类，我们可以很容易地将.plist文件解析为这个结构体的实例化:

func parseConfig() -> Config {
    let url = Bundle.main.url(forResource: "Config", withExtension: "plist")!
    let data = try! Data(contentsOf: url)
    let decoder = PropertyListDecoder()
    return try! decoder.decode(Config.self, from: data)
}

不用担心太多代码，而且都在Swift中。更好的是，我们现在有一个Config结构的实例化，我们可以很容易地使用:

let config = parseConfig()
print(config.name) 
print(config.age)
print(config.single) 

打印。plist中“name”、“age”和“single”键的值。

能在一行内完成吗

    var dict = NSDictionary(contentsOfFile: NSBundle.mainBundle().pathForResource("Config", ofType: "plist"))

如果你有信息。Plist，然后使用

Bundle.main.infoDictionary