我使用swift字典，但在我的文件管理器类中转换它们和nsdictionary，如下所示:

    func writePlist(fileName:String, myDict:Dictionary<String, AnyObject>){
        let docsDir:String = dirPaths[0] as String
        let docPath = docsDir + "/" + fileName
        let thisDict = myDict as NSDictionary
        if(thisDict.writeToFile(docPath, atomically: true)){
            NSLog("success")
        } else {
            NSLog("failure")
        }

    }
    func getPlist(fileName:String)->Dictionary<String, AnyObject>{
        let docsDir:String = dirPaths[0] as String
        let docPath = docsDir + "/" + fileName
        let thisDict = NSDictionary(contentsOfFile: docPath)
        return thisDict! as! Dictionary<String, AnyObject>
    }

这似乎是最不麻烦的读写方式，但让我的其余代码保持尽可能快。

访问plist文件的简单结构(Swift 2.0)

struct Configuration {      
  static let path = NSBundle.mainBundle().pathForResource("Info", ofType: "plist")!
  static let dict = NSDictionary(contentsOfFile: path) as! [String: AnyObject]

  static let someValue = dict["someKey"] as! String
}

用法:

print("someValue = \(Configuration.someValue)")

最好使用本机字典和数组，因为它们已经针对swift进行了优化。也就是说你可以使用NS。我认为这种情况证明了这一点。下面是你如何实现它:

var path = NSBundle.mainBundle().pathForResource("Config", ofType: "plist")
var dict = NSDictionary(contentsOfFile: path)

到目前为止(在我看来)，这是访问plist最简单和最有效的方法，但在未来，我希望苹果将添加更多的功能(比如使用plist)到本地字典中。

Swift -读写plist和文本文件....

override func viewDidLoad() {
    super.viewDidLoad()

    let fileManager = (NSFileManager .defaultManager())
    let directorys : [String]? = NSSearchPathForDirectoriesInDomains(NSSearchPathDirectory.DocumentDirectory,NSSearchPathDomainMask.AllDomainsMask, true) as? [String]

    if (directorys != nil){
        let directories:[String] = directorys!;
        let dictionary = directories[0]; //documents directory


        //  Create and insert the data into the Plist file  ....
        let plistfile = "myPlist.plist"
        var myDictionary: NSMutableDictionary = ["Content": "This is a sample Plist file ........."]
        let plistpath = dictionary.stringByAppendingPathComponent(plistfile);

        if !fileManager .fileExistsAtPath(plistpath){//writing Plist file
            myDictionary.writeToFile(plistpath, atomically: false)
        }
        else{            //Reading Plist file
            println("Plist file found")

            let resultDictionary = NSMutableDictionary(contentsOfFile: plistpath)
            println(resultDictionary?.description)
        }


        //  Create and insert the data into the Text file  ....
        let textfile = "myText.txt"
        let sampleText = "This is a sample text file ......... "

        let textpath = dictionary.stringByAppendingPathComponent(textfile);
        if !fileManager .fileExistsAtPath(textpath){//writing text file
            sampleText.writeToFile(textpath, atomically: false, encoding: NSUTF8StringEncoding, error: nil);
        } else{
            //Reading text file
            let reulttext  = String(contentsOfFile: textpath, encoding: NSUTF8StringEncoding, error: nil)
            println(reulttext)
        }
    }
    else {
        println("directory is empty")
    }
}

能在一行内完成吗

    var dict = NSDictionary(contentsOfFile: NSBundle.mainBundle().pathForResource("Config", ofType: "plist"))

因为这个答案还没有在这里，只是想指出，你也可以使用infoDictionary属性来获取信息plist作为字典，Bundle.main.infoDictionary。

比如bundle。main。如果您只对info plist中的特定项感兴趣，则可以使用kCFBundleNameKey作为String)。

// Swift 4

// Getting info plist as a dictionary
let dictionary = Bundle.main.infoDictionary

// Getting the app display name from the info plist
Bundle.main.infoDictionary?[kCFBundleNameKey as String]

// Getting the app display name from the info plist (another way)
Bundle.main.object(forInfoDictionaryKey: kCFBundleNameKey as String)