我遇到了一些情况,现在,它将是方便的,能够找到“最顶层”的视图控制器(一个负责当前视图),但还没有找到一种方法。
基本上,挑战是这样的:给定一个在一个类中执行,这个类不是一个视图控制器(或一个视图)[并且没有活动视图的地址],并且没有传递最顶层视图控制器的地址(或者,比如说,导航控制器的地址),是否有可能找到那个视图控制器?(如果是的话,是怎么做到的?)
或者,如果找不到,有没有可能找到最高处的风景?
我遇到了一些情况,现在,它将是方便的,能够找到“最顶层”的视图控制器(一个负责当前视图),但还没有找到一种方法。
基本上,挑战是这样的:给定一个在一个类中执行,这个类不是一个视图控制器(或一个视图)[并且没有活动视图的地址],并且没有传递最顶层视图控制器的地址(或者,比如说,导航控制器的地址),是否有可能找到那个视图控制器?(如果是的话,是怎么做到的?)
或者,如果找不到,有没有可能找到最高处的风景?
当前回答
这对于从任何根视图控件中找到top viewcontroller1非常有效
+ (UIViewController *)topViewControllerFor:(UIViewController *)viewController
{
if(!viewController.presentedViewController)
return viewController;
return [MF5AppDelegate topViewControllerFor:viewController.presentedViewController];
}
/* View Controller for Visible View */
AppDelegate *app = [UIApplication sharedApplication].delegate;
UIViewController *visibleViewController = [AppDelegate topViewControllerFor:app.window.rootViewController];
其他回答
使用扩展为Swift获得最顶部的视图控制器
代码:
extension UIViewController {
@objc func topMostViewController() -> UIViewController {
// Handling Modal views
if let presentedViewController = self.presentedViewController {
return presentedViewController.topMostViewController()
}
// Handling UIViewController's added as subviews to some other views.
else {
for view in self.view.subviews
{
// Key property which most of us are unaware of / rarely use.
if let subViewController = view.next {
if subViewController is UIViewController {
let viewController = subViewController as! UIViewController
return viewController.topMostViewController()
}
}
}
return self
}
}
}
extension UITabBarController {
override func topMostViewController() -> UIViewController {
return self.selectedViewController!.topMostViewController()
}
}
extension UINavigationController {
override func topMostViewController() -> UIViewController {
return self.visibleViewController!.topMostViewController()
}
}
用法:
UIApplication.sharedApplication().keyWindow!.rootViewController!.topMostViewController()
这是对Eric的回答的改进:
UIViewController *_topMostController(UIViewController *cont) {
UIViewController *topController = cont;
while (topController.presentedViewController) {
topController = topController.presentedViewController;
}
if ([topController isKindOfClass:[UINavigationController class]]) {
UIViewController *visible = ((UINavigationController *)topController).visibleViewController;
if (visible) {
topController = visible;
}
}
return (topController != cont ? topController : nil);
}
UIViewController *topMostController() {
UIViewController *topController = [UIApplication sharedApplication].keyWindow.rootViewController;
UIViewController *next = nil;
while ((next = _topMostController(topController)) != nil) {
topController = next;
}
return topController;
}
UIViewController *cont是一个辅助函数。
现在你所需要做的就是调用topMostController()和最顶端的UIViewController应该被返回!
我认为大多数答案都完全忽略了UINavigationViewController,所以我用下面的实现来处理这个用例。
+ (UIViewController *)topMostController {
UIViewController * topController = [UIApplication sharedApplication].keyWindow.rootViewController;
while (topController.presentedViewController || [topController isMemberOfClass:[UINavigationController class]]) {
if([topController isMemberOfClass:[UINavigationController class]]) {
topController = [topController childViewControllers].lastObject;
} else {
topController = topController.presentedViewController;
}
}
return topController;
}
使用下面的扩展抓取当前可见的UIViewController。适用于Swift 4.0及更高版本
Swift 4.0及以上版本:
extension UIApplication {
class func topViewController(_ viewController: UIViewController? = UIApplication.shared.keyWindow?.rootViewController) -> UIViewController? {
if let nav = viewController as? UINavigationController {
return topViewController(nav.visibleViewController)
}
if let tab = viewController as? UITabBarController {
if let selected = tab.selectedViewController {
return topViewController(selected)
}
}
if let presented = viewController?.presentedViewController {
return topViewController(presented)
}
return viewController
}
}
如何使用?
let objViewcontroller = UIApplication.topViewController()
另一个Swift解决方案
func topController() -> UIViewController? {
// recursive follow
func follow(from:UIViewController?) -> UIViewController? {
if let to = (from as? UITabBarController)?.selectedViewController {
return follow(to)
} else if let to = (from as? UINavigationController)?.visibleViewController {
return follow(to)
} else if let to = from?.presentedViewController {
return follow(to)
}
return from
}
let root = UIApplication.sharedApplication().keyWindow?.rootViewController
return follow(root)
}