getattr根据对象的名称调用方法。但此对象应该是调用类的父对象。父类可以由super（self.__class__，self）获取

class Base:
    def call_base(func):
        """This does not work"""
        def new_func(self, *args, **kwargs):
            name = func.__name__
            getattr(super(self.__class__, self), name)(*args, **kwargs)
        return new_func

    def f(self, *args):
        print(f"BASE method invoked.")

    def g(self, *args):
        print(f"BASE method invoked.")

class Inherit(Base):
    @Base.call_base
    def f(self, *args):
        """function body will be ignored by the decorator."""
        pass

    @Base.call_base
    def g(self, *args):
        """function body will be ignored by the decorator."""
        pass

Inherit().f() # The goal is to print "BASE method invoked."

关于这个问题，如何使用方法名分配给标记为与此重复的变量[重复]来动态调用类中的方法，我在这里发布了一个相关的答案：

场景是，一个类中的一个方法想要动态调用同一个类上的另一个方法，我在原始示例中添加了一些细节，这提供了更广泛的场景和清晰性：

class MyClass:
    def __init__(self, i):
        self.i = i

    def get(self):
        func = getattr(MyClass, 'function{}'.format(self.i))
        func(self, 12)   # This one will work
        # self.func(12)    # But this does NOT work.


    def function1(self, p1):
        print('function1: {}'.format(p1))
        # do other stuff

    def function2(self, p1):
        print('function2: {}'.format(p1))
        # do other stuff


if __name__ == "__main__":
    class1 = MyClass(1)
    class1.get()
    class2 = MyClass(2)
    class2.get()

输出（Python 3.7.x）功能1：12功能2:12

值得一提的是，如果您需要将函数（或类）名称和应用程序名称作为字符串传递，那么可以这样做：

myFnName  = "MyFn"
myAppName = "MyApp"
app = sys.modules[myAppName]
fn  = getattr(app,myFnName)

getattr根据对象的名称调用方法。但此对象应该是调用类的父对象。父类可以由super（self.__class__，self）获取

class Base:
    def call_base(func):
        """This does not work"""
        def new_func(self, *args, **kwargs):
            name = func.__name__
            getattr(super(self.__class__, self), name)(*args, **kwargs)
        return new_func

    def f(self, *args):
        print(f"BASE method invoked.")

    def g(self, *args):
        print(f"BASE method invoked.")

class Inherit(Base):
    @Base.call_base
    def f(self, *args):
        """function body will be ignored by the decorator."""
        pass

    @Base.call_base
    def g(self, *args):
        """function body will be ignored by the decorator."""
        pass

Inherit().f() # The goal is to print "BASE method invoked."

这些建议对我都没有帮助。但我确实发现了这一点。

<object>.__getattribute__(<string name>)(<params>)

我使用的是python 2.66

希望这有帮助

只是一个简单的贡献。如果我们需要实例化的类在同一个文件中，我们可以使用类似的方法：

# Get class from globals and create an instance
m = globals()['our_class']()

# Get the function (from the instance) that we need to call
func = getattr(m, 'function_name')

# Call it
func()

例如：

class A:
    def __init__(self):
        pass

    def sampleFunc(self, arg):
        print('you called sampleFunc({})'.format(arg))

m = globals()['A']()
func = getattr(m, 'sampleFunc')
func('sample arg')

# Sample, all on one line
getattr(globals()['A'](), 'sampleFunc')('sample arg')

如果不是类：

def sampleFunc(arg):
    print('you called sampleFunc({})'.format(arg))

globals()['sampleFunc']('sample arg')