如果数组不大，可以使用indexOf()循环并逐个检查每个子字符串。或者，您可以构造一个带有子字符串作为替代的正则表达式，这可能更有效，也可能不更有效。

我并不是建议你去扩展/修改String的原型，但这是我所做的:

String.prototype.includes ()

String.prototype.includes = function (includes) { console.warn("String.prototype.includes() has been modified."); return function (searchString, position) { if (searchString instanceof Array) { for (var i = 0; i < searchString.length; i++) { if (includes.call(this, searchString[i], position)) { return true; } } return false; } else { return includes.call(this, searchString, position); } } }(String.prototype.includes); console.log('"Hello, World!".includes("foo");', "Hello, World!".includes("foo") ); // false console.log('"Hello, World!".includes(",");', "Hello, World!".includes(",") ); // true console.log('"Hello, World!".includes(["foo", ","])', "Hello, World!".includes(["foo", ","]) ); // true console.log('"Hello, World!".includes(["foo", ","], 6)', "Hello, World!".includes(["foo", ","], 6) ); // false

Javascript函数使用搜索字符串或搜索字符串数组搜索标签或关键字数组。(使用ES5的一些数组方法和ES6的箭头函数)

// returns true for 1 or more matches, where 'a' is an array and 'b' is a search string or an array of multiple search strings
function contains(a, b) {
    // array matches
    if (Array.isArray(b)) {
        return b.some(x => a.indexOf(x) > -1);
    }
    // string match
    return a.indexOf(b) > -1;
}

使用示例:

var a = ["a","b","c","d","e"];
var b = ["a","b"];
if ( contains(a, b) ) {
    // 1 or more matches found
}

借鉴T.J. Crowder的解决方案，我创建了一个原型来处理这个问题:

Array.prototype.check = function (s) {
  return this.some((v) => {
    return s.indexOf(v) >= 0;
  });
};

单线解决方案

substringsArray.some(substring=>yourBigString.includes(substring))

如果子字符串存在\不存在，则返回true\false

需要ES6支持

var str = "texttexttext";
var arr = ["asd", "ghj", "xtte"];
for (var i = 0, len = arr.length; i < len; ++i) {
    if (str.indexOf(arr[i]) != -1) {
        // str contains arr[i]
    }
}

编辑: 如果测试的顺序不重要，你可以使用这个(只有一个循环变量):

var str = "texttexttext";
var arr = ["asd", "ghj", "xtte"];
for (var i = arr.length - 1; i >= 0; --i) {
    if (str.indexOf(arr[i]) != -1) {
        // str contains arr[i]
    }
}