在Android中，每个单独的View子类都有一个setVisibility()方法，允许你修改View对象的可见性
有3个设置可见性的选项:
可见:在布局中显示视图 不可见:隐藏视图，但留下一个空白，相当于视图在可见时所占据的空白 消失:隐藏视图，并将其完全从布局中移除。就好像它的高和宽都是0dp
对于Flutter中的小部件，是否有与上述相同的东西?
快速参考: https://developer.android.com/reference/android/view/View.html#attr_android:visibility
当前回答
class VisibilityExample extends StatefulWidget {
const VisibilityExample({Key? key}) : super(key: key);
@override
_VisibilityExampleState createState() => _VisibilityExampleState();
}
class _VisibilityExampleState extends State<VisibilityExample> {
bool visible = false;
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: const Text('Lines'),
),
body: Container(
color: Colors.black87,
child: Stack(alignment: Alignment.bottomCenter, children: [
ListView(
shrinkWrap: true,
children: [
Container(
height: 200,
),
InkWell(
onTap: () {},
onHover: (value) {
print(value);
setState(() {
visible = !visible;
});
},
child: Visibility(
maintainSize: true,
maintainAnimation: true,
maintainState: true,
visible: visible,
child: Row(
mainAxisAlignment: MainAxisAlignment.center,
children: [
IconButton(
color: Colors.white54,
icon: const Icon(
Icons.arrow_left_outlined,
),
onPressed: () {},
),
const SizedBox(
width: 5,
),
IconButton(
color: Colors.white54,
icon: const Icon(
Icons.add_circle_outlined,
),
onPressed: () {},
),
const SizedBox(
width: 5,
),
IconButton(
color: Colors.white54,
icon: const Icon(
Icons.remove_circle,
),
onPressed: () {},
),
const SizedBox(
width: 5,
),
IconButton(
color: Colors.white54,
icon: const Icon(
Icons.arrow_right_outlined,
),
onPressed: () {},
),
const SizedBox(
width: 5,
),
IconButton(
color: Colors.white54,
icon: const Icon(Icons.replay_circle_filled_outlined),
onPressed: () {},
),
],
),
),
),
],
),
]),
),
);
}
}
其他回答
在flutter 1.5和Dart 2.3中，对于可视性消失，您可以在集合中使用if语句设置可见性，而不必使用容器。
e.g
child: Column(
mainAxisAlignment: MainAxisAlignment.center,
children: <Widget>[
Text('This is text one'),
if (_isVisible) Text('can be hidden or shown'), // no dummy container/ternary needed
Text('This is another text'),
RaisedButton(child: Text('show/hide'), onPressed: (){
setState(() {
_isVisible = !_isVisible;
});
},)
],
)
更新:因为这个答案是写的，可见性被引入，并提供了这个问题的最佳解决方案。
你可以在不透明度:为0.0的情况下使用不透明度来绘制隐藏的元素，但仍然占用空间。
为了使它不占用空间，将其替换为空Container()。
编辑: 要将它包装在不透明对象中，请执行以下操作:
new Opacity(opacity: 0.0, child: new Padding(
padding: const EdgeInsets.only(
left: 16.0,
),
child: new Icon(pencil, color: CupertinoColors.activeBlue),
))
谷歌开发者不透明度快速教程:https://youtu.be/9hltevOHQBw
尝试Offstage小部件
如果属性off - stage:true则不占用物理空间且不可见，
如果属性offstage:false它将占用物理空间而可见
Offstage(
offstage: true,
child: Text("Visible"),
),
class VisibilityExample extends StatefulWidget {
const VisibilityExample({Key? key}) : super(key: key);
@override
_VisibilityExampleState createState() => _VisibilityExampleState();
}
class _VisibilityExampleState extends State<VisibilityExample> {
bool visible = false;
@override
Widget build(BuildContext context) {
return Scaffold(
appBar: AppBar(
title: const Text('Lines'),
),
body: Container(
color: Colors.black87,
child: Stack(alignment: Alignment.bottomCenter, children: [
ListView(
shrinkWrap: true,
children: [
Container(
height: 200,
),
InkWell(
onTap: () {},
onHover: (value) {
print(value);
setState(() {
visible = !visible;
});
},
child: Visibility(
maintainSize: true,
maintainAnimation: true,
maintainState: true,
visible: visible,
child: Row(
mainAxisAlignment: MainAxisAlignment.center,
children: [
IconButton(
color: Colors.white54,
icon: const Icon(
Icons.arrow_left_outlined,
),
onPressed: () {},
),
const SizedBox(
width: 5,
),
IconButton(
color: Colors.white54,
icon: const Icon(
Icons.add_circle_outlined,
),
onPressed: () {},
),
const SizedBox(
width: 5,
),
IconButton(
color: Colors.white54,
icon: const Icon(
Icons.remove_circle,
),
onPressed: () {},
),
const SizedBox(
width: 5,
),
IconButton(
color: Colors.white54,
icon: const Icon(
Icons.arrow_right_outlined,
),
onPressed: () {},
),
const SizedBox(
width: 5,
),
IconButton(
color: Colors.white54,
icon: const Icon(Icons.replay_circle_filled_outlined),
onPressed: () {},
),
],
),
),
),
],
),
]),
),
);
}
}
正如@CopsOnRoad已经强调的那样， 您可以使用Visibility小部件。但是，如果你想保持它的状态，例如，如果你想建立一个viewpager，让一个按钮根据页面出现和消失，你可以这样做
void checkVisibilityButton() {
setState(() {
isVisibileNextBtn = indexPage + 1 < pages.length;
});
}
Stack(children: <Widget>[
PageView.builder(
itemCount: pages.length,
onPageChanged: (index) {
indexPage = index;
checkVisibilityButton();
},
itemBuilder: (context, index) {
return pages[index];
},
controller: controller,
),
Container(
alignment: Alignment.bottomCenter,
child: Row(
mainAxisAlignment: MainAxisAlignment.end,
children: <Widget>[
Visibility(
visible: isVisibileNextBtn,
child: "your widget"
)
],
),
)
]))
