我如何才能最好地编写一个查询,从总共600k中随机选择10行?


当前回答

您可以轻松地使用带限制的随机偏移量

PREPARE stm from 'select * from table limit 10 offset ?';
SET @total = (select count(*) from table);
SET @_offset = FLOOR(RAND() * @total);
EXECUTE stm using @_offset;

您还可以像这样应用where子句

PREPARE stm from 'select * from table where available=true limit 10 offset ?';
SET @total = (select count(*) from table where available=true);
SET @_offset = FLOOR(RAND() * @total);
EXECUTE stm using @_offset;

在600,000行(700MB)表查询执行上的测试花费了大约0.016秒的硬盘驱动器时间。

EDIT:偏移量可能取接近表末尾的值,这将导致select语句返回更少的行(或者可能只有一行),为了避免这种情况,我们可以在声明偏移量后再次检查,如下所示

SET @rows_count = 10;
PREPARE stm from "select * from table where available=true limit ? offset ?";
SET @total = (select count(*) from table where available=true);
SET @_offset = FLOOR(RAND() * @total);
SET @_offset = (SELECT IF(@total-@_offset<@rows_count,@_offset-@rows_count,@_offset));
SET @_offset = (SELECT IF(@_offset<0,0,@_offset));
EXECUTE stm using @rows_count,@_offset;

其他回答

如果有一个自动生成的id,我发现一个很好的方法是使用模运算符'%'。例如,如果您需要70,000条随机记录中的10,000条,您可以简化为每7行中需要1行。这可以在这个查询中简化:

SELECT * FROM 
    table 
WHERE 
    id % 
    FLOOR(
        (SELECT count(1) FROM table) 
        / 10000
    ) = 0;

如果目标行除以total available的结果不是一个整数,那么你将得到比你要求的更多的行,所以你应该添加一个LIMIT子句来帮助你像这样修剪结果集:

SELECT * FROM 
    table 
WHERE 
    id % 
    FLOOR(
        (SELECT count(1) FROM table) 
        / 10000
    ) = 0
LIMIT 10000;

这确实需要一个完整的扫描,但它比ORDER BY RAND更快,在我看来,比本文中提到的其他选项更容易理解。另外,如果写入数据库的系统批量创建了一组行,你可能不会得到你所期望的随机结果。

另一个简单的解决方案是对行进行排名,并随机获取其中之一,有了这个解决方案,你将不需要在表中有任何基于“Id”的列。

SELECT d.* FROM (
SELECT  t.*,  @rownum := @rownum + 1 AS rank
FROM mytable AS t,
    (SELECT @rownum := 0) AS r,
    (SELECT @cnt := (SELECT RAND() * (SELECT COUNT(*) FROM mytable))) AS n
) d WHERE rank >= @cnt LIMIT 10;

您可以根据需要更改限制值,以便访问尽可能多的行,但大多数情况下是连续的值。

然而,如果你不想要连续的随机值,那么你可以获取一个更大的样本并从中随机选择。就像……

SELECT * FROM (
SELECT d.* FROM (
    SELECT  c.*,  @rownum := @rownum + 1 AS rank
    FROM buildbrain.`commits` AS c,
        (SELECT @rownum := 0) AS r,
        (SELECT @cnt := (SELECT RAND() * (SELECT COUNT(*) FROM buildbrain.`commits`))) AS rnd
) d 
WHERE rank >= @cnt LIMIT 10000 
) t ORDER BY RAND() LIMIT 10;
SELECT column FROM table
ORDER BY RAND()
LIMIT 10

这不是有效的解决方案,但确实有效

所有最好的答案都已经贴出来了(主要是那些引用了http://jan.kneschke.de/projects/mysql/order-by-rand/的链接)。

I want to pinpoint another speed-up possibility - caching. Think of why you need to get random rows. Probably you want display some random post or random ad on a website. If you are getting 100 req/s, is it really needed that each visitor gets random rows? Usually it is completely fine to cache these X random rows for 1 second (or even 10 seconds). It doesn't matter if 100 unique visitors in the same 1 second get the same random posts, because the next second another 100 visitors will get different set of posts.

当使用这种缓存时,你也可以使用一些较慢的解决方案来获取随机数据,因为不管你的req/s如何,它每秒只会从MySQL中获取一次。

我是这样做的:

select * 
from table_with_600k_rows
where rand() < 10/600000
limit 10

我喜欢它,因为它不需要其他表,写起来很简单,执行起来非常快。