我想让我的应用看起来更专业，所以我决定添加一个启动画面。
我应该如何进行实现呢?
当前回答
一个超级灵活的启动屏幕如何，可以使用相同的代码，并在AndroidManifest.xml中定义，因此代码永远不需要更改。我通常开发代码库，不喜欢定制代码，因为它很草率。
<activity
android:name=".SplashActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<meta-data android:name="launch_class" android:value="com.mypackage.MyFirstActivity" />
<meta-data android:name="duration" android:value="5000" />
</activity>
然后SpashActivity本身查找“launch_class”的元数据，然后创建Intent本身。元数据“持续时间”定义了启动画面持续的时间。
public class SplashActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
setContentView(R.layout.activity_splash);
ComponentName componentName = new ComponentName(this, this.getClass());
try {
Bundle bundle = null;
bundle = getPackageManager().getActivityInfo(componentName, PackageManager.GET_META_DATA).metaData;
String launch_class = bundle.getString("launch_class");
//default of 2 seconds, otherwise defined in manifest
int duration = bundle.getInt("duration", 2000);
if(launch_class != null) {
try {
final Class<?> c = Class.forName(launch_class);
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
Intent intent = new Intent(SplashActivity.this, c);
startActivity(intent);
finish();
}
}, duration);
} catch (ClassNotFoundException e) {
e.printStackTrace();
}
}
} catch (PackageManager.NameNotFoundException e) {
e.printStackTrace();
}
}
}
其他回答
这里有一个简单的!
~卢诺克斯
MainActivity.java
package com.example.splashscreen;
import androidx.appcompat.app.AppCompatActivity;
import android.os.Bundle;
public class MainActivity extends AppCompatActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
}
}
splashscreen.java
package com.example.splashscreen;
import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.os.Handler;
public class splashscreen extends Activity {
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.splashscreen);
//Splash Screen duration
int secondsDelayed = 1;
new Handler().postDelayed(new Runnable() {
public void run() {
startActivity(new Intent(splashscreen.this, MainActivity.class));
finish();
}
}, secondsDelayed * 3000);
}
}
activity_main.xml
<?xml version="1.0" encoding="utf-8"?>
<androidx.constraintlayout.widget.ConstraintLayout xmlns:android="http://schemas.android.com/apk/res/android"
xmlns:app="http://schemas.android.com/apk/res-auto"
xmlns:tools="http://schemas.android.com/tools"
android:layout_width="match_parent"
android:layout_height="match_parent"
tools:context=".MainActivity">
<TextView
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="Hello World!"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintLeft_toLeftOf="parent"
app:layout_constraintRight_toRightOf="parent"
app:layout_constraintTop_toTopOf="parent" />
</androidx.constraintlayout.widget.ConstraintLayout>
splashscreen.xml
<?xml version="1.0" encoding="utf-8"?>
<LinearLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:orientation="vertical" android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@drawable/splashlogo"
/>
splashlogo.png
splashlogo.png
GitHub
SplashScreen
在我的例子中，我不想创建一个新的活动只是为了显示2秒的图像。当启动我的MainActivity，图像被加载到持有者使用毕加索，我知道这需要大约1秒的加载，所以我决定做以下在我的MainActivity OnCreate:
splashImage = (ImageView) findViewById(R.id.spllll);
this.getWindow().setFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN,WindowManager.LayoutParams.FLAG_FULLSCREEN);
int secondsDelayed = 1;
new Handler().postDelayed(new Runnable() {
public void run() {
getWindow().clearFlags(WindowManager.LayoutParams.FLAG_FULLSCREEN);
splashImage.setVisibility(View.GONE);
}
}, secondsDelayed * 2000);
当启动应用程序时，发生的第一件事是显示ImageView，并通过将窗口标志设置为全屏来删除状态栏。然后我使用Handler运行2秒，2秒后我清除全屏标志，并设置ImageView的可见性为GONE。简单，简单，有效。
这是完整的代码
SplashActivity.java
public class SplashActivity extends AppCompatActivity {
private final int SPLASH_DISPLAY_DURATION = 1000;
@Override
public void onCreate(Bundle bundle) {
super.onCreate(bundle);
new Handler().postDelayed(new Runnable(){
@Override
public void run() {
Intent mainIntent = new Intent(SplashActivity.this,MainActivity.class);
SplashActivity.this.startActivity(mainIntent);
SplashActivity.this.finish();
}
}, SPLASH_DISPLAY_DURATION);
}}
在drawables中创建bg_splash.xml
<?xml version="1.0" encoding="utf-8"?><layer-list xmlns:android="http://schemas.android.com/apk/res/android">
<item
android:drawable="@color/app_color"/>
<item>
<bitmap
android:gravity="center"
android:src="@drawable/ic_in_app_logo_big"/>
</item></layer-list>
在styles.xml中创建一个自定义主题
<style name="SplashTheme" parent="Theme.AppCompat.NoActionBar">
<item name="android:windowBackground">@drawable/bg_splash</item>
</style>
最后在AndroidManifest.xml中指定活动的主题
<activity
android:name=".activities.SplashActivity"
android:label="@string/app_name"
android:screenOrientation="portrait"
android:theme="@style/SplashTheme">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
</activity>
欢呼。
在Android中，启动画面是一个有点不可用的对象:为了隐藏主活动启动的延迟，它不能尽快加载。使用它有两个原因:广告和网络运营。
实现为对话框使跳跃没有延迟从启动画面到主UI的活动。
public class SplashDialog extends Dialog {
ImageView splashscreen;
SplashLoader loader;
int splashTime = 4000;
public SplashDialog(Context context, int theme) {
super(context, theme);
}
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_splash);
setCancelable(false);
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
cancel();
}
}, splashTime);
}
}
布局:
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
android:layout_width="fill_parent"
android:layout_height="fill_parent"
android:background="@color/white">
<ImageView
android:id="@+id/splashscreen"
android:layout_width="190dp"
android:layout_height="190dp"
android:background="@drawable/whistle"
android:layout_centerInParent="true" />
</RelativeLayout>
并开始:
public class MyActivity extends ActionBarActivity {
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
if (getIntent().getCategories() != null && getIntent().getCategories().contains("android.intent.category.LAUNCHER")) {
showSplashScreen();
}
}
protected Dialog splashDialog;
protected void showSplashScreen() {
splashDialog = new SplashDialog(this, R.style.SplashScreen);
splashDialog.show();
}
...
}
一个超级灵活的启动屏幕如何，可以使用相同的代码，并在AndroidManifest.xml中定义，因此代码永远不需要更改。我通常开发代码库，不喜欢定制代码，因为它很草率。
<activity
android:name=".SplashActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<meta-data android:name="launch_class" android:value="com.mypackage.MyFirstActivity" />
<meta-data android:name="duration" android:value="5000" />
</activity>
然后SpashActivity本身查找“launch_class”的元数据，然后创建Intent本身。元数据“持续时间”定义了启动画面持续的时间。
public class SplashActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
setContentView(R.layout.activity_splash);
ComponentName componentName = new ComponentName(this, this.getClass());
try {
Bundle bundle = null;
bundle = getPackageManager().getActivityInfo(componentName, PackageManager.GET_META_DATA).metaData;
String launch_class = bundle.getString("launch_class");
//default of 2 seconds, otherwise defined in manifest
int duration = bundle.getInt("duration", 2000);
if(launch_class != null) {
try {
final Class<?> c = Class.forName(launch_class);
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
Intent intent = new Intent(SplashActivity.this, c);
startActivity(intent);
finish();
}
}, duration);
} catch (ClassNotFoundException e) {
e.printStackTrace();
}
}
} catch (PackageManager.NameNotFoundException e) {
e.printStackTrace();
}
}
}
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