我想让我的应用看起来更专业,所以我决定添加一个启动画面。
我应该如何进行实现呢?
我想让我的应用看起来更专业,所以我决定添加一个启动画面。
我应该如何进行实现呢?
当前回答
启动画面示例:
public class MainActivity extends Activity {
private ImageView splashImageView;
boolean splashloading = false;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
splashImageView = new ImageView(this);
splashImageView.setScaleType(ScaleType.FIT_XY);
splashImageView.setImageResource(R.drawable.ic_launcher);
setContentView(splashImageView);
splashloading = true;
Handler h = new Handler();
h.postDelayed(new Runnable() {
public void run() {
splashloading = false;
setContentView(R.layout.activity_main);
}
}, 3000);
}
}
其他回答
一个超级灵活的启动屏幕如何,可以使用相同的代码,并在AndroidManifest.xml中定义,因此代码永远不需要更改。我通常开发代码库,不喜欢定制代码,因为它很草率。
<activity
android:name=".SplashActivity">
<intent-filter>
<action android:name="android.intent.action.MAIN" />
<category android:name="android.intent.category.LAUNCHER" />
</intent-filter>
<meta-data android:name="launch_class" android:value="com.mypackage.MyFirstActivity" />
<meta-data android:name="duration" android:value="5000" />
</activity>
然后SpashActivity本身查找“launch_class”的元数据,然后创建Intent本身。元数据“持续时间”定义了启动画面持续的时间。
public class SplashActivity extends Activity {
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle icicle) {
super.onCreate(icicle);
setContentView(R.layout.activity_splash);
ComponentName componentName = new ComponentName(this, this.getClass());
try {
Bundle bundle = null;
bundle = getPackageManager().getActivityInfo(componentName, PackageManager.GET_META_DATA).metaData;
String launch_class = bundle.getString("launch_class");
//default of 2 seconds, otherwise defined in manifest
int duration = bundle.getInt("duration", 2000);
if(launch_class != null) {
try {
final Class<?> c = Class.forName(launch_class);
new Handler().postDelayed(new Runnable() {
@Override
public void run() {
Intent intent = new Intent(SplashActivity.this, c);
startActivity(intent);
finish();
}
}, duration);
} catch (ClassNotFoundException e) {
e.printStackTrace();
}
}
} catch (PackageManager.NameNotFoundException e) {
e.printStackTrace();
}
}
}
这是我所见过的关于启动画面的最好的帖子:http://saulmm.github.io/avoding-android-cold-starts
Saúl Molinero介绍了两种不同的启动画面选项:利用窗口背景动画进入初始屏幕和显示占位符UI(这是谷歌目前在大多数应用程序中使用的流行选择)。
每当我需要考虑冷启动时间和避免由于长启动时间而导致用户流失时,我都会参考这篇文章。
希望这能有所帮助!
简单的代码,它的工作:)简单的飞溅
int secondsDelayed = 1;
new Handler().postDelayed(new Runnable() {
public void run() {
startActivity(new Intent(LoginSuccessFull.this, LoginActivity.class));
finish();
}
}, secondsDelayed * 1500);
另一种方法是使用CountDownTimer实现
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.splashscreen);
new CountDownTimer(5000, 1000) { //5 seconds
public void onTick(long millisUntilFinished) {
mTextField.setText("seconds remaining: " + millisUntilFinished / 1000);
}
public void onFinish() {
startActivity(new Intent(SplashActivity.this, MainActivity.class));
finish();
}
}.start();
}
Create an Activity SplashScreen.java public class SplashScreen extends Activity { protected boolean _active = true; protected int _splashTime = 3000; // time to display the splash screen in ms @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.splashscreen); Thread splashTread = new Thread() { @Override public void run() { try { int waited = 0; while (_active && (waited < _splashTime)) { sleep(100); if (_active) { waited += 100; } } } catch (Exception e) { } finally { startActivity(new Intent(SplashScreen.this, MainActivity.class)); finish(); } }; }; splashTread.start(); } } splashscreen.xml will be like this <?xml version="1.0" encoding="utf-8"?> <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="600px" android:layout_height="1024px" android:background="#FF0000"> </RelativeLayout>