在这一页上找不到任何解决方案吗

使用循环 使用javax.xml.bind.DatatypeConverter，它编译良好，但经常在运行时抛出java.lang.NoClassDefFoundError。

这里有一个解决方案，它没有上面的缺陷(不保证我的没有其他缺陷)

import java.math.BigInteger;

import static java.lang.System.out;
public final class App2 {
    // | proposed solution.
    public static String encode(byte[] bytes) {          
        final int length = bytes.length;

        // | BigInteger constructor throws if it is given an empty array.
        if (length == 0) {
            return "00";
        }

        final int evenLength = (int)(2 * Math.ceil(length / 2.0));
        final String format = "%0" + evenLength + "x";         
        final String result = String.format (format, new BigInteger(bytes));

        return result;
    }

    public static void main(String[] args) throws Exception {
        // 00
        out.println(encode(new byte[] {})); 

        // 01
        out.println(encode(new byte[] {1})); 

        //203040
        out.println(encode(new byte[] {0x20, 0x30, 0x40})); 

        // 416c6c20796f75722062617365206172652062656c6f6e6720746f2075732e
        out.println(encode("All your base are belong to us.".getBytes()));
    }
}   

我不能在62个操作码下得到这个，但如果你可以在第一个字节小于0x10的情况下没有0填充，那么下面的解决方案只使用23个操作码。真正展示了“容易实现自己”的解决方案，如“如果字符串长度为奇数，则填充为零”，如果本机实现还不可用(或者在本例中，如果BigInteger在toString中有一个以零作为前缀的选项)，则可能会非常昂贵。

public static String encode(byte[] bytes) {          
    final int length = bytes.length;

    // | BigInteger constructor throws if it is given an empty array.
    if (length == 0) {
        return "00";
    }

    return new BigInteger(bytes).toString(16);
}

从这里的讨论，特别是这个答案，这是我目前使用的函数:

private static final char[] HEX_ARRAY = "0123456789ABCDEF".toCharArray();
public static String bytesToHex(byte[] bytes) {
    char[] hexChars = new char[bytes.length * 2];
    for (int j = 0; j < bytes.length; j++) {
        int v = bytes[j] & 0xFF;
        hexChars[j * 2] = HEX_ARRAY[v >>> 4];
        hexChars[j * 2 + 1] = HEX_ARRAY[v & 0x0F];
    }
    return new String(hexChars);
}

My own tiny benchmarks (a million bytes a thousand times, 256 bytes 10 million times) showed it to be much faster than any other alternative, about half the time on long arrays. Compared to the answer I took it from, switching to bitwise ops --- as suggested in the discussion --- cut about 20% off of the time for long arrays. (Edit: When I say it's faster than the alternatives, I mean the alternative code offered in the discussions. Performance is equivalent to Commons Codec, which uses very similar code.)

2k20版本，相对于Java 9的压缩字符串:

private static final byte[] HEX_ARRAY = "0123456789ABCDEF".getBytes(StandardCharsets.US_ASCII);
public static String bytesToHex(byte[] bytes) {
    byte[] hexChars = new byte[bytes.length * 2];
    for (int j = 0; j < bytes.length; j++) {
        int v = bytes[j] & 0xFF;
        hexChars[j * 2] = HEX_ARRAY[v >>> 4];
        hexChars[j * 2 + 1] = HEX_ARRAY[v & 0x0F];
    }
    return new String(hexChars, StandardCharsets.UTF_8);
}

使用DataTypeConverter classjavax.xml.bind.DataTypeConverter

String hexString = DatatypeConverter。printHexBinary(原始字节[]);

我通常使用以下方法进行debuf语句，但我不知道这是否是最好的方法

private static String digits = "0123456789abcdef";

public static String toHex(byte[] data){
    StringBuffer buf = new StringBuffer();
    for (int i = 0; i != data.length; i++)
    {
        int v = data[i] & 0xff;
        buf.append(digits.charAt(v >> 4));
        buf.append(digits.charAt(v & 0xf));
    }
    return buf.toString();
}

为了完整起见，一个番石榴解决方案:

import com.google.common.io.BaseEncoding;
...
byte[] bytes = "Hello world".getBytes(StandardCharsets.UTF_8);
final String hex = BaseEncoding.base16().lowerCase().encode(bytes);

现在十六进制是“48656c6c6f20776f726c64”。

这个怎么样?

    String byteToHex(final byte[] hash)
    {
        Formatter formatter = new Formatter();
        for (byte b : hash)
        {
            formatter.format("%02x", b);
        }
        String result = formatter.toString();
        formatter.close();
        return result;
    }