使用DataTypeConverter classjavax.xml.bind.DataTypeConverter

String hexString = DatatypeConverter。printHexBinary(原始字节[]);

最简单的解决方案，没有外部库，没有数字常量:

public static String byteArrayToHex(byte[] a) {
   StringBuilder sb = new StringBuilder(a.length * 2);
   for(byte b: a)
      sb.append(String.format("%02x", b));
   return sb.toString();
}

在存储查找表的很小代价下，这个实现非常简单和快速。

 private static final char[] BYTE2HEX=(
    "000102030405060708090A0B0C0D0E0F"+
    "101112131415161718191A1B1C1D1E1F"+
    "202122232425262728292A2B2C2D2E2F"+
    "303132333435363738393A3B3C3D3E3F"+
    "404142434445464748494A4B4C4D4E4F"+
    "505152535455565758595A5B5C5D5E5F"+
    "606162636465666768696A6B6C6D6E6F"+
    "707172737475767778797A7B7C7D7E7F"+
    "808182838485868788898A8B8C8D8E8F"+
    "909192939495969798999A9B9C9D9E9F"+
    "A0A1A2A3A4A5A6A7A8A9AAABACADAEAF"+
    "B0B1B2B3B4B5B6B7B8B9BABBBCBDBEBF"+
    "C0C1C2C3C4C5C6C7C8C9CACBCCCDCECF"+
    "D0D1D2D3D4D5D6D7D8D9DADBDCDDDEDF"+
    "E0E1E2E3E4E5E6E7E8E9EAEBECEDEEEF"+
    "F0F1F2F3F4F5F6F7F8F9FAFBFCFDFEFF").toCharArray();
   ; 

  public static String getHexString(byte[] bytes) {
    final int len=bytes.length;
    final char[] chars=new char[len<<1];
    int hexIndex;
    int idx=0;
    int ofs=0;
    while (ofs<len) {
      hexIndex=(bytes[ofs++] & 0xFF)<<1;
      chars[idx++]=BYTE2HEX[hexIndex++];
      chars[idx++]=BYTE2HEX[hexIndex];
    }
    return new String(chars);
  }

Converts bytes data to hex characters

@param bytes byte array to be converted to hex string
@return byte String in hex format

private static String bytesToHex(byte[] bytes) {
    char[] hexChars = new char[bytes.length * 2];
    int v;
    for (int j = 0; j < bytes.length; j++) {
        v = bytes[j] & 0xFF;
        hexChars[j * 2] = HEX_ARRAY[v >>> 4];
        hexChars[j * 2 + 1] = HEX_ARRAY[v & 0x0F];
    }
    return new String(hexChars);
}

//移位字节更有效 //你也可以用这个

public static String getHexString (String s) 
{
    byte[] buf = s.getBytes();

    StringBuffer sb = new StringBuffer();

    for (byte b:buf)
    {
        sb.append(String.format("%x", b));
    }


        return sb.toString();
}

这个简单的联机程序适合我 String result = new BigInteger(1, inputBytes).toString(16); EDIT -使用此命令将删除前导0，但在我的用例中它们是有效的。感谢@Voicu指出这一点