break语句终止它出现的最近的封闭do、for、switch或while语句的执行。控制权转移到终止语句后面的语句。

从msdn。

你可以使用“goto”来留下嵌套循环 下面是我的原始代码，包括“goto”

int main()
{
    string str;
    while (cin >> str)
    {
        if (str == "0")
            break;
        int sum = 0;
        for (auto ch : str)
        {
            if (ch <= 'z' && ch >= 'a')
                sum += (ch - 'a' + 1);
            else if (ch >= 'A' && ch <= 'Z')
                sum += (ch - 'A' + 1);
            else
            {
                cout << "Fail" << endl;
                goto fail;
            }
        }

        cout << sum << endl;
        fail:
    }
    return 0;
}

然而，我可以通过添加函数“计算”来避免“goto”

void calculate(const string &str)
{
    int sum = 0;
    for (auto ch : str)
    {
        if (ch <= 'z' && ch >= 'a')
            sum += (ch - 'a' + 1);
        else if (ch >= 'A' && ch <= 'Z')
            sum += (ch - 'A' + 1);
        else
        {
            cout << "Fail" << endl;
            return;
        }
    }

    cout << sum << endl;
}

int main()
{
    string str;
    while (cin >> str)
    {
        if (str == "0")
            break;
        calculate(str);
    }
    return 0;
}

虽然这个答案已经提出了，但我认为一个很好的方法是这样做:

for(unsigned int z = 0; z < z_max; z++)
{
    bool gotoMainLoop = false;
    for(unsigned int y = 0; y < y_max && !gotoMainLoop; y++)
    {
        for(unsigned int x = 0; x < x_max && !gotoMainLoop; x++)
        {
                          //do your stuff
                          if(condition)
                            gotoMainLoop = true;
        }
    }

}

Breaking out of a for-loop is a little strange to me, since the semantics of a for-loop typically indicate that it will execute a specified number of times. However, it's not bad in all cases; if you're searching for something in a collection and want to break after you find it, it's useful. Breaking out of nested loops, however, isn't possible in C++; it is in other languages through the use of a labeled break. You can use a label and a goto, but that might give you heartburn at night..? Seems like the best option though.

打破嵌套循环的另一种方法是将两个循环分解成一个单独的函数，并在希望退出时从该函数返回。

当然，这也引发了另一个争论，即是否应该显式地从函数的任何地方返回，而不是在函数的末尾。

我知道这是老帖子了。但我想提出一个更合理、更简单的答案。

for(unsigned int i=0; i < 50; i++)
    {
        for(unsigned int j=0; j < conditionj; j++)
        {
            for(unsigned int k=0; k< conditionk ; k++)
            {
                // If condition is true

                j= conditionj;
               break;
            }
        }
    }