只是使用lambdas添加一个显式的答案:

  for (int i = 0; i < n1; ++i) {
    [&] {
      for (int j = 0; j < n2; ++j) {
        for (int k = 0; k < n3; ++k) {
          return; // yay we're breaking out of 2 loops here
        }
      }
    }();
  }

当然，这种模式有一定的局限性，显然只适用于c++ 11，但我认为它非常有用。

我知道这是老帖子了。但我想提出一个更合理、更简单的答案。

for(unsigned int i=0; i < 50; i++)
    {
        for(unsigned int j=0; j < conditionj; j++)
        {
            for(unsigned int k=0; k< conditionk ; k++)
            {
                // If condition is true

                j= conditionj;
               break;
            }
        }
    }

break语句终止它出现的最近的封闭do、for、switch或while语句的执行。控制权转移到终止语句后面的语句。

从msdn。

我认为goto在这种情况下是有效的:

要模拟中断/继续，你需要:

打破

for ( ;  ;  ) {
    for ( ;  ;  ) {
        /*Code here*/
        if (condition) {
            goto theEnd;
        }
    }
}
theEnd:

继续

for ( ;  ; ) {
    for ( ;  ;  ) {
        /*Code here*/
        if (condition) {
            i++;
            goto multiCont;
        }
    }
    multiCont:
}

Breaking out of a for-loop is a little strange to me, since the semantics of a for-loop typically indicate that it will execute a specified number of times. However, it's not bad in all cases; if you're searching for something in a collection and want to break after you find it, it's useful. Breaking out of nested loops, however, isn't possible in C++; it is in other languages through the use of a labeled break. You can use a label and a goto, but that might give you heartburn at night..? Seems like the best option though.

一个使用goto和标签跳出嵌套循环的代码示例:

for (;;)
  for (;;)
    goto theEnd;
theEnd: