通常你会使用\n，但无论出于什么原因，在Visual Studio Code 2019 Individual中它将无法工作。但是你可以用这个:

# Workaround to \n not working
print("lorem ipsum", file=f)  # Python 3.0 onwards only
print >>f, "Text"             # Python 2.0 and under

另一个解决方案是使用fstring从列表中写入

lines = ['hello','world']
with open('filename.txt', "w") as fhandle:
  for line in lines:
    fhandle.write(f'{line}\n')

作为一个函数

def write_list(fname, lines):
    with open(fname, "w") as fhandle:
      for line in lines:
        fhandle.write(f'{line}\n')

write_list('filename.txt', ['hello','world'])

file_path = "/path/to/yourfile.txt"
with open(file_path, 'a') as file:
    file.write("This will be added to the next line\n")

or

log_file = open('log.txt', 'a')
log_file.write("This will be added to the next line\n")

为了支持多种操作系统的使用: 文件。写(f'some字符串和/或{variable}。{os.linesep}”)

你可以通过两种方式做到这一点:

f.write("text to write\n")

或者，取决于你的Python版本(2或3):

print >>f, "text to write"         # Python 2.x
print("text to write", file=f)     # Python 3.x

这是我自己想出来的解决方法为了系统地产生n作为分离器。它使用一个字符串列表，其中每个字符串是文件的一行，但它似乎也可以为您工作。(Python 3 +)。

#Takes a list of strings and prints it to a file.
def writeFile(file, strList):
    line = 0
    lines = []
    while line < len(strList):
        lines.append(cheekyNew(line) + strList[line])
        line += 1
    file = open(file, "w")
    file.writelines(lines)
    file.close()

#Returns "\n" if the int entered isn't zero, otherwise "".
def cheekyNew(line):
    if line != 0:
        return "\n"
    return ""