每次调用file.write()时,我都想在字符串中添加换行符。在Python中最简单的方法是什么?


当前回答

好的,这里有一个安全的方法。

with open('example.txt', 'w') as f:
 for i in range(10):
  f.write(str(i+1))
  f.write('\n')


这将在新行中对每个数字写入1到10。

其他回答

对我来说,在print()语句上使用append (a)和open()看起来更容易:

save_url  = ".\test.txt"

your_text = "This will be on line 1"
print(your_text, file=open(save_url, "a+"))

another_text = "This will be on line 2"
print(another_text, file=open(save_url, "a+"))

another_text = "This will be on line 3"
print(another_text, file=open(save_url, "a+"))
file_path = "/path/to/yourfile.txt"
with open(file_path, 'a') as file:
    file.write("This will be added to the next line\n")

or

log_file = open('log.txt', 'a')
log_file.write("This will be added to the next line\n")

你可以这样做:

file.write(your_string + '\n')

正如另一个答案所建议的,但为什么在可以调用文件时使用字符串连接(缓慢,容易出错)。写两次:

file.write(your_string)
file.write("\n")

注意,写操作是被缓冲的,所以两者是一样的。

你可以通过两种方式做到这一点:

f.write("text to write\n")

或者,取决于你的Python版本(2或3):

print >>f, "text to write"         # Python 2.x
print("text to write", file=f)     # Python 3.x

另一个解决方案是使用fstring从列表中写入

lines = ['hello','world']
with open('filename.txt', "w") as fhandle:
  for line in lines:
    fhandle.write(f'{line}\n')

作为一个函数

def write_list(fname, lines):
    with open(fname, "w") as fhandle:
      for line in lines:
        fhandle.write(f'{line}\n')

write_list('filename.txt', ['hello','world'])