我试图使用python模拟包来模拟python请求模块。让我在下面的场景中工作的基本调用是什么?

在views.py中,我有一个函数,它每次都以不同的响应进行各种request .get()调用

def myview(request):
  res1 = requests.get('aurl')
  res2 = request.get('burl')
  res3 = request.get('curl')

在我的测试类中,我想做类似的事情,但不能确定确切的方法调用

步骤1:

# Mock the requests module
# when mockedRequests.get('aurl') is called then return 'a response'
# when mockedRequests.get('burl') is called then return 'b response'
# when mockedRequests.get('curl') is called then return 'c response'

步骤2:

调用我的视图

步骤3:

验证响应包含'a response', 'b response', 'c response'

我如何完成第1步(模拟请求模块)?


当前回答

这对我来说是可行的,尽管我还没有做太多复杂的测试。

import json
from requests import Response

class MockResponse(Response):
    def __init__(self,
                 url='http://example.com',
                 headers={'Content-Type':'text/html; charset=UTF-8'},
                 status_code=200,
                 reason = 'Success',
                 _content = 'Some html goes here',
                 json_ = None,
                 encoding='UTF-8'
                 ):
    self.url = url
    self.headers = headers
    if json_ and headers['Content-Type'] == 'application/json':
        self._content = json.dumps(json_).encode(encoding)
    else:
        self._content = _content.encode(encoding)

    self.status_code = status_code
    self.reason = reason
    self.encoding = encoding

然后你可以创建响应:

mock_response = MockResponse(
    headers={'Content-Type' :'application/json'},
    status_code=401,
    json_={'success': False},
    reason='Unauthorized'
)
mock_response.raise_for_status()

给了

requests.exceptions.HTTPError: 401 Client Error: Unauthorized for url: http://example.com

其他回答

以下是对我有效的方法:

import mock
@mock.patch('requests.get', mock.Mock(side_effect = lambda k:{'aurl': 'a response', 'burl' : 'b response'}.get(k, 'unhandled request %s'%k)))

对于pytest用户,有一个来自https://pypi.org/project/pytest-responsemock/的方便的fixture

例如,模拟GET到http://some.domain,你可以:

def test_me(response_mock):

    with response_mock('GET http://some.domain -> 200 :Nice'):
        response = send_request()
        assert result.ok
        assert result.content == b'Nice'

我将添加这些信息,因为我很难弄清楚如何模拟异步api调用。

以下是我模拟异步调用所做的工作。

这是我想测试的函数

async def get_user_info(headers, payload):
    return await httpx.AsyncClient().post(URI, json=payload, headers=headers)

您仍然需要MockResponse类

class MockResponse:
    def __init__(self, json_data, status_code):
        self.json_data = json_data
        self.status_code = status_code

    def json(self):
        return self.json_data

添加MockResponseAsync类

class MockResponseAsync:
    def __init__(self, json_data, status_code):
        self.response = MockResponse(json_data, status_code)

    async def getResponse(self):
        return self.response

下面是测试。这里重要的是,我之前创建了响应,因为init函数不能是异步的,对getResponse的调用是异步的,所以它都签出了。

@pytest.mark.asyncio
@patch('httpx.AsyncClient')
async def test_get_user_info_valid(self, mock_post):
    """test_get_user_info_valid"""
    # Given
    token_bd = "abc"
    username = "bob"
    payload = {
        'USERNAME': username,
        'DBNAME': 'TEST'
    }
    headers = {
        'Authorization': 'Bearer ' + token_bd,
        'Content-Type': 'application/json'
    }
    async_response = MockResponseAsync("", 200)
    mock_post.return_value.post.return_value = async_response.getResponse()

    # When
    await api_bd.get_user_info(headers, payload)

    # Then
    mock_post.return_value.post.assert_called_once_with(
        URI, json=payload, headers=headers)

如果你有更好的方法告诉我,不过我觉得这样很干净。

您可以使用request -mock代替吗?

假设你的myview函数接受一个请求。Session对象,用它发出请求,并对输出做一些事情:

# mypackage.py
def myview(session):
    res1 = session.get("http://aurl")
    res2 = session.get("http://burl")
    res3 = session.get("http://curl")
    return f"{res1.text}, {res2.text}, {res3.text}"
# test_myview.py
from mypackage import myview
import requests

def test_myview(requests_mock):
    # set up requests
    a_req = requests_mock.get("http://aurl", text="a response")
    b_req = requests_mock.get("http://burl", text="b response")
    c_req = requests_mock.get("http://curl", text="c response")

    # test myview behaviour
    session = requests.Session()
    assert myview(session) == "a response, b response, c response"

    # check that requests weren't called repeatedly
    assert a_req.called_once
    assert b_req.called_once
    assert c_req.called_once
    assert requests_mock.call_count == 3

你也可以在Pytest之外的框架中使用requests_mock——文档非常棒。

下面是一个带有请求响应类的解决方案。恕我直言,它更干净。

import json
from unittest.mock import patch
from requests.models import Response

def mocked_requests_get(*args, **kwargs):
    response_content = None
    request_url = kwargs.get('url', None)
    if request_url == 'aurl':
        response_content = json.dumps('a response')
    elif request_url == 'burl':
        response_content = json.dumps('b response')
    elif request_url == 'curl':
        response_content = json.dumps('c response')
    response = Response()
    response.status_code = 200
    response._content = str.encode(response_content)
    return response

@mock.patch('requests.get', side_effect=mocked_requests_get)
def test_fetch(self, mock_get):
     response = requests.get(url='aurl')
     assert ...