验证字符串是否是有效的电子邮件地址的最优雅的代码是什么?
当前回答
以前,我写了一个EmailAddressValidationAttribute,它应该正确地验证表单中几乎任何相对正常的电子邮件地址
local-part@domain
它是System.ComponentModel.DataAnnotations。ValidationAttribute,所以使用非常简单。
而且,由于挖掘所有rfc和勘误表,并组装所需的所有位来正确枚举所有规则……太乏味了!-我在回答c#电子邮件地址验证源代码的问题时发布了验证器的源代码。
我的验证器无论怎么想象都不是完美的,只是对于初学者来说,它没有任何内置的对发出客户端javascript验证的支持,尽管将其添加进来并不太难。从我上面的回答来看:
Here's the validation attribute I wrote. It validates pretty much every "raw" email address, that is those of the form local-part@domain. It doesn't support any of the other, more...creative constructs that the RFCs allow (this list is not comprehensive by any means): comments (e.g., jsmith@whizbang.com (work)) quoted strings (escaped text, to allow characters not allowed in an atom) domain literals (e.g. foo@[123.45.67.012]) bang-paths (aka source routing) angle addresses (e.g. John Smith <jsmith@whizbang.com>) folding whitespace double-byte characters in either local-part or domain (7-bit ASCII only). etc. It should accept almost any email address that can be expressed thusly foo.bar@bazbat.com without requiring the use of quotes ("), angle brackets ('<>') or square brackets ([]). No attempt is made to validate that the rightmost dns label in the domain is a valid TLD (top-level domain). That is because the list of TLDs is far larger now than the "big 6" (.com, .edu, .gov, .mil, .net, .org) plus 2-letter ISO country codes. ICANN actually updates the TLD list daily, though I suspect that the list doesn't actually change daily. Further, [ICANN just approved a big expansion of the generic TLD namespace][2]). And some email addresses don't have what you'd recognize as a TLD (did you know that postmaster@. is theoretically valid and mailable? Mail to that address should get delivered to the postmaster of the DNS root zone.) Extending the regular expression to support domain literals shouldn't be too difficult.
其他回答
我认为最好的方法如下:
public static bool EmailIsValid(string email)
{
string expression = "\\w+([-+.']\\w+)*@\\w+([-.]\\w+)*\\.\\w+([-.]\\w+)*";
if (Regex.IsMatch(email, expression))
{
if (Regex.Replace(email, expression, string.Empty).Length == 0)
{
return true;
}
}
return false;
}
你可以在一个通用类中使用这个静态函数。
老实说,在产品代码中,我所做的最好的事情就是检查@符号。
我从来没有在一个地方完全验证电子邮件。你知道我怎么判断它是否有效吗?如果发送出去了。如果没有,那就糟了,如果有,生活就好了。这就是我需要知道的。
我写了一个函数来检查电子邮件是否有效。在大多数情况下,这似乎对我很有效。
结果:
dasddas-@.com => FALSE
-asd@das.com => FALSE
as3d@dac.coas- => FALSE
dsq!a?@das.com => FALSE
_dasd@sd.com => FALSE
dad@sds => FALSE
asd-@asd.com => FALSE
dasd_-@jdas.com => FALSE
asd@dasd@asd.cm => FALSE
da23@das..com => FALSE
_dasd_das_@9.com => FALSE
d23d@da9.co9 => TRUE
dasd.dadas@dasd.com => TRUE
dda_das@das-dasd.com => TRUE
dasd-dasd@das.com.das => TRUE
代码:
private bool IsValidEmail(string email)
{
bool valid = false;
try
{
var addr = new System.Net.Mail.MailAddress(email);
valid = true;
}
catch
{
valid = false;
goto End_Func;
}
valid = false;
int pos_at = email.IndexOf('@');
char checker = Convert.ToChar(email.Substring(pos_at + 1, 1));
var chars = "qwertyuiopasdfghjklzxcvbnm0123456789";
foreach (char chr in chars)
{
if (checker == chr)
{
valid = true;
break;
}
}
if (valid == false)
{
goto End_Func;
}
int pos_dot = email.IndexOf('.', pos_at + 1);
if(pos_dot == -1)
{
valid = false;
goto End_Func;
}
valid = false;
try
{
checker = Convert.ToChar(email.Substring(pos_dot + 1, 1));
foreach (char chr in chars)
{
if (checker == chr)
{
valid = true;
break;
}
}
}
catch
{
valid = false;
goto End_Func;
}
Regex valid_checker = new Regex(@"^[a-zA-Z0-9_@.-]*$");
valid = valid_checker.IsMatch(email);
if (valid == false)
{
goto End_Func;
}
List<int> pos_list = new List<int> { };
int pos = 0;
while (email.IndexOf('_', pos) != -1)
{
pos_list.Add(email.IndexOf('_', pos));
pos = email.IndexOf('_', pos) + 1;
}
pos = 0;
while (email.IndexOf('.', pos) != -1)
{
pos_list.Add(email.IndexOf('.', pos));
pos = email.IndexOf('.', pos) + 1;
}
pos = 0;
while (email.IndexOf('-', pos) != -1)
{
pos_list.Add(email.IndexOf('-', pos));
pos = email.IndexOf('-', pos) + 1;
}
int sp_cnt = pos_list.Count();
pos_list.Sort();
for (int i = 0; i < sp_cnt - 1; i++)
{
if (pos_list[i] + 1 == pos_list[i + 1])
{
valid = false;
break;
}
if (pos_list[i]+1 == pos_at || pos_list[i]+1 == pos_dot)
{
valid = false;
break;
}
}
if(valid == false)
{
goto End_Func;
}
if (pos_list[sp_cnt - 1] == email.Length - 1 || pos_list[0] == 0)
{
valid = false;
}
End_Func:;
return valid;
}
如果您将多个解决方案组合在一起来编写完美的代码呢?
我得到了排名最高的2个解决方案和评论,并结合起来得到更准确的答案。 它的短,快和可爱。
public static bool isValidEmail(string email)
{
try
{
var addr = new System.Net.Mail.MailAddress(email);
if (addr.Address == email)
{
string expression = "\\w+([-+.']\\w+)*@\\w+([-.]\\w+)*\\.\\w+([-.]\\w+)*";
if (Regex.IsMatch(email, expression))
{
if (Regex.Replace(email, expression, string.Empty).Length == 0)
return true;
}
return false;
}
return false;
}
catch
{
return false;
}
}
.net 4.5增加了System.ComponentModel.DataAnnotations.EmailAddressAttribute
你可以浏览EmailAddressAttribute的源代码,这是它内部使用的正则表达式:
const string pattern = @"^((([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+(\.([a-z]|\d|[!#\$%&'\*\+\-\/=\?\^_`{\|}~]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])+)*)|((\x22)((((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(([\x01-\x08\x0b\x0c\x0e-\x1f\x7f]|\x21|[\x23-\x5b]|[\x5d-\x7e]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(\\([\x01-\x09\x0b\x0c\x0d-\x7f]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF]))))*(((\x20|\x09)*(\x0d\x0a))?(\x20|\x09)+)?(\x22)))@((([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|\d|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.)+(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])|(([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])([a-z]|\d|-|\.|_|~|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])*([a-z]|[\u00A0-\uD7FF\uF900-\uFDCF\uFDF0-\uFFEF])))\.?$";
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