我试图用多个其他单词替换字符串中的多个单词。字符串是“我有一只猫,一只狗和一只山羊。”

然而,这并不会产生“我有一只狗、一只山羊和一只猫”,而是产生“我有一只猫、一只猫和一只猫”。是否有可能在JavaScript中同时用多个其他字符串替换多个字符串,以便产生正确的结果?

var str = "I have a cat, a dog, and a goat.";
str = str.replace(/cat/gi, "dog");
str = str.replace(/dog/gi, "goat");
str = str.replace(/goat/gi, "cat");

//this produces "I have a cat, a cat, and a cat"
//but I wanted to produce the string "I have a dog, a goat, and a cat".

当前回答

你可以试试这个。买不聪明。

var str = "我有一只猫,一只狗,和一只山羊。"; console.log (str); str = str.replace(/cat/gi, "XXX"); console.log (str); STR = STR .replace(/goat/gi, "cat"); console.log (str); STR = STR .replace(/dog/gi, "goat"); console.log (str); str = str.replace(/XXX/gi, "dog"); console.log (str); 把: 我有一只狗,一只山羊和一只猫。

其他回答

使用我的replace-once包,您可以执行以下操作:

const replaceOnce = require('replace-once')

var str = 'I have a cat, a dog, and a goat.'
var find = ['cat', 'dog', 'goat']
var replace = ['dog', 'goat', 'cat']
replaceOnce(str, find, replace, 'gi')
//=> 'I have a dog, a goat, and a cat.'

以防有人想知道为什么原来海报上的解决方案不管用:

var str = "I have a cat, a dog, and a goat.";

str = str.replace(/cat/gi, "dog");
// now str = "I have a dog, a dog, and a goat."

str = str.replace(/dog/gi, "goat");
// now str = "I have a goat, a goat, and a goat."

str = str.replace(/goat/gi, "cat");
// now str = "I have a cat, a cat, and a cat."
<!DOCTYPE html>
<html>
<body>



<p id="demo">Mr Blue 
has a           blue house and a blue car.</p>

<button onclick="myFunction()">Try it</button>

<script>
function myFunction() {
    var str = document.getElementById("demo").innerHTML;
    var res = str.replace(/\n| |car/gi, function myFunction(x){

if(x=='\n'){return x='<br>';}
if(x==' '){return x='&nbsp';}
if(x=='car'){return x='BMW'}
else{return x;}//must need



});

    document.getElementById("demo").innerHTML = res;
}
</script>

</body>
</html>

我写了这个npm包stringinject https://www.npmjs.com/package/stringinject,它允许你做以下事情

var string = stringInject("this is a {0} string for {1}", ["test", "stringInject"]);

这将替换{0}和{1}与数组项,并返回以下字符串

"this is a test string for stringInject"

或者你可以像这样用对象键和值替换占位符:

var str = stringInject("My username is {username} on {platform}", { username: "tjcafferkey", platform: "GitHub" });

"My username is tjcafferkey on Github" 

使用编号的物品,防止再次更换。 如

let str = "I have a %1, a %2, and a %3";
let pets = ["dog","cat", "goat"];

then

str.replace(/%(\d+)/g, (_, n) => pets[+n-1])

它的工作原理:- %\d+查找跟在%后面的数字。括号表示数字。

这个数字(作为字符串)是lambda函数的第二个参数n。

+n-1将字符串转换为数字,然后减去1以索引宠物数组。

然后将%数字替换为数组下标处的字符串。

/g导致lambda函数被重复调用,每个数字被替换为数组中的字符串。

在现代JavaScript中:-

replace_n=(str,...ns)=>str.replace(/%(\d+)/g,(_,n)=>ns[n-1])