有没有一个聪明的方法让用户在隐藏和查看密码之间切换在一个android EditText? 许多基于PC的应用程序都允许用户这样做。
当前回答
用复选框显示和隐藏密码Edit_Text
XML
<?xml version="1.0" encoding="utf-8"?>
<RelativeLayout
xmlns:android="http://schemas.android.com/apk/res/android" android:layout_width="match_parent"
android:layout_height="match_parent">
<EditText
android:inputType="textPassword"
android:id="@+id/edtPass"
android:textSize="20dp"
android:hint="password"
android:padding="20dp"
android:background="#efeaea"
android:layout_width="match_parent"
android:layout_margin="20dp"
android:layout_height="wrap_content" />
<CheckBox
android:background="#ff4"
android:layout_centerInParent="true"
android:textSize="25dp"
android:text="show password"
android:layout_below="@id/edtPass"
android:id="@+id/showPassword"
android:layout_marginTop="20dp"
android:layout_width="wrap_content"
android:gravity="top|right"
android:layout_height="wrap_content" />
</RelativeLayout>
java代码
package com.example.root.sql2;
import android.annotation.SuppressLint;
import android.os.Bundle;
import android.support.design.widget.FloatingActionButton;
import android.support.design.widget.Snackbar;
import android.support.v7.app.AppCompatActivity;
import android.support.v7.widget.AppCompatCheckBox;
import android.support.v7.widget.Toolbar;
import android.text.method.HideReturnsTransformationMethod;
import android.text.method.PasswordTransformationMethod;
import android.view.View;
import android.widget.CheckBox;
import android.widget.CompoundButton;
import android.widget.EditText;
public class password extends AppCompatActivity {
EditText password;
CheckBox show_hide_password;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.hide);
findViewById();
show_hide_pass();
}//end onCreate
public void show_hide_pass(){
show_hide_password.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener() {
@Override
public void onCheckedChanged(CompoundButton compoundButton, boolean b) {
if (!b){
// hide password
password.setTransformationMethod(PasswordTransformationMethod.getInstance());
}else{
// show password
password.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
}
}
});
} // end show_hide_pass
public void findViewById(){ // find ids ui and
password = (EditText) findViewById(R.id.edtPass);
show_hide_password = (CheckBox) findViewById(R.id.showPassword);
}//end findViewById
}// end class
其他回答
you can use this
private fun showPasswordSwitch(checked: Boolean) {
registerBinding.registerActivityEditTextPassword.also {
// Password hide-show
it.inputType =
if (checked) TEXT_PASSWORD_SHOW else TEXT_PASSWORD_HIDE
}
}
const val TEXT_PASSWORD_SHOW = InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_VISIBLE_PASSWORD
const val TEXT_PASSWORD_HIDE = InputType.TYPE_CLASS_TEXT or InputType.TYPE_TEXT_VARIATION_PASSWORD
if (inputPassword.getTransformationMethod() == PasswordTransformationMethod.getInstance()) {
//password is visible
inputPassword.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
}
else if(inputPassword.getTransformationMethod() == HideReturnsTransformationMethod.getInstance()) {
//password is hidden
inputPassword.setTransformationMethod(PasswordTransformationMethod.getInstance());
}
首先,这是屏幕加载图像矢量资产可见性
点击它将改变这个图像的可见性关闭
以上密码开关代码(xml代码)
<androidx.constraintlayout.widget.ConstraintLayout
android:id="@+id/laypass"
android:layout_width="330dp"
android:layout_height="50dp"
android:layout_marginTop="24dp"
app:layout_constraintEnd_toEndOf="@+id/editText3"
app:layout_constraintStart_toStartOf="@+id/editText3"
app:layout_constraintTop_toBottomOf="@+id/editText3">
<EditText
android:id="@+id/edit_password"
style="@style/EditTextTheme"
android:layout_width="match_parent"
android:layout_height="match_parent"
android:background="@drawable/round"
android:drawableLeft="@drawable/ic_password"
android:drawablePadding="10dp"
android:ems="10"
android:hint="Password"
android:inputType="textPassword"
android:paddingLeft="10dp"
android:paddingRight="15dp"
android:textColor="@color/cyan92a6"
android:textColorHint="@color/cyan92a6"
android:textCursorDrawable="@null"
android:textSize="18sp"
/>
<ImageView
android:id="@+id/show_pass_btn"
android:layout_width="40dp"
android:layout_height="40dp"
android:layout_alignParentRight="true"
android:layout_centerVertical="true"
android:layout_marginEnd="8dp"
android:alpha=".5"
android:onClick="ShowHidePass"
android:padding="5dp"
android:src="@drawable/ic_visibility"
app:layout_constraintBottom_toBottomOf="parent"
app:layout_constraintEnd_toEndOf="@+id/laypass"
app:layout_constraintTop_toTopOf="@+id/edit_password" />
</androidx.constraintlayout.widget.ConstraintLayout>
按钮操作的Java代码
public void ShowHidePass(View view) {
if(view.getId()==R.id.show_pass_btn){
if(edit_password.getTransformationMethod().equals(PasswordTransformationMethod.getInstance())){
((ImageView)(view)).setImageResource(R.drawable.ic_visibility_off);
//Show Password
edit_password.setTransformationMethod(HideReturnsTransformationMethod.getInstance());
}
else{
((ImageView)(view)).setImageResource(R.drawable.ic_visibility);
//Hide Password
edit_password.setTransformationMethod(PasswordTransformationMethod.getInstance());
}
}
}
只需在Xml文件中创建一个复选框
然后简单的用Java代码编写这个函数
checkbox = findViewById(R.id.checkbox);
checkbox.setOnCheckedChangeListener(new CompoundButton.OnCheckedChangeListener(){
@Override
public void onCheckedChanged(CompoundButton buttonView, boolean isChecked){
if (isChecked) {
password.setTransformationMethod(null);
}
else{
password.setTransformationMethod(new PasswordTransformationMethod());
}
}
});
试试这个:
passwordEditText.setInputType(1);
Or
passwordEditText.setInputType(InputType.TYPE_CLASS_TEXT);
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