以下是移植到JSR 353的Vikas代码:

import java.util.ArrayList;
import java.util.HashMap;
import java.util.Iterator;
import java.util.List;
import java.util.Map;

import javax.json.JsonArray;
import javax.json.JsonException;
import javax.json.JsonObject;

public class JsonUtils {
    public static Map<String, Object> jsonToMap(JsonObject json) {
        Map<String, Object> retMap = new HashMap<String, Object>();

        if(json != JsonObject.NULL) {
            retMap = toMap(json);
        }
        return retMap;
    }

    public static Map<String, Object> toMap(JsonObject object) throws JsonException {
        Map<String, Object> map = new HashMap<String, Object>();

        Iterator<String> keysItr = object.keySet().iterator();
        while(keysItr.hasNext()) {
            String key = keysItr.next();
            Object value = object.get(key);

            if(value instanceof JsonArray) {
                value = toList((JsonArray) value);
            }

            else if(value instanceof JsonObject) {
                value = toMap((JsonObject) value);
            }
            map.put(key, value);
        }
        return map;
    }

    public static List<Object> toList(JsonArray array) {
        List<Object> list = new ArrayList<Object>();
        for(int i = 0; i < array.size(); i++) {
            Object value = array.get(i);
            if(value instanceof JsonArray) {
                value = toList((JsonArray) value);
            }

            else if(value instanceof JsonObject) {
                value = toMap((JsonObject) value);
            }
            list.add(value);
        }
        return list;
    }
}

使用Gson，你可以做以下事情:

Map<String, Object> retMap = new Gson().fromJson(
    jsonString, new TypeToken<HashMap<String, Object>>() {}.getType()
);

递归方式:

public static Map<String, Object> jsonToMap(JSONObject json) throws JSONException {
    Map<String, Object> retMap = new HashMap<String, Object>();
    
    if(json != JSONObject.NULL) {
        retMap = toMap(json);
    }
    return retMap;
}

public static Map<String, Object> toMap(JSONObject object) throws JSONException {
    Map<String, Object> map = new HashMap<String, Object>();

    Iterator<String> keysItr = object.keys();
    while(keysItr.hasNext()) {
        String key = keysItr.next();
        Object value = object.get(key);
        
        if(value instanceof JSONArray) {
            value = toList((JSONArray) value);
        }
        
        else if(value instanceof JSONObject) {
            value = toMap((JSONObject) value);
        }
        map.put(key, value);
    }
    return map;
}

public static List<Object> toList(JSONArray array) throws JSONException {
    List<Object> list = new ArrayList<Object>();
    for(int i = 0; i < array.length(); i++) {
        Object value = array.get(i);
        if(value instanceof JSONArray) {
            value = toList((JSONArray) value);
        }

        else if(value instanceof JSONObject) {
            value = toMap((JSONObject) value);
        }
        list.add(value);
    }
    return list;
}

使用Jackson库:

import com.fasterxml.jackson.databind.ObjectMapper;

Map<String, Object> mapping = new ObjectMapper().readValue(jsonStr, HashMap.class);

You can convert any JSON to map by using Jackson library as below: String json = "{\r\n\"name\" : \"abc\" ,\r\n\"email id \" : [\"abc@gmail.com\",\"def@gmail.com\",\"ghi@gmail.com\"]\r\n}"; ObjectMapper mapper = new ObjectMapper(); Map<String, Object> map = new HashMap<String, Object>(); // convert JSON string to Map map = mapper.readValue(json, new TypeReference<Map<String, Object>>() {}); System.out.println(map); Maven Dependencies for Jackson : <dependency> <groupId>com.fasterxml.jackson.core</groupId> <artifactId>jackson-core</artifactId> <version>2.5.3</version> <scope>compile</scope> </dependency> <dependency> <groupId>com.fasterxml.jackson.core</groupId> <artifactId>jackson-databind</artifactId> <version>2.5.3</version> <scope>compile</scope> </dependency> Hope this will help. Happy coding :)

有一个使用javax的旧答案。json发布在这里，然而它只转换JsonArray和JsonObject，但仍然有JsonString, JsonNumber和JsonValue包装类在输出。如果你想摆脱这些，这是我的解决方案，它会打开所有东西。

除此之外，它还使用Java 8流，并包含在单个方法中。

/**
 * Convert a JsonValue into a “plain” Java structure (using Map and List).
 * 
 * @param value The JsonValue, not <code>null</code>.
 * @return Map, List, String, Number, Boolean, or <code>null</code>.
 */
public static Object toObject(JsonValue value) {
    Objects.requireNonNull(value, "value was null");
    switch (value.getValueType()) {
    case ARRAY:
        return ((JsonArray) value)
                .stream()
                .map(JsonUtils::toObject)
                .collect(Collectors.toList());
    case OBJECT:
        return ((JsonObject) value)
                .entrySet()
                .stream()
                .collect(Collectors.toMap(
                        Entry::getKey,
                        e -> toObject(e.getValue())));
    case STRING:
        return ((JsonString) value).getString();
    case NUMBER:
        return ((JsonNumber) value).numberValue();
    case TRUE:
        return Boolean.TRUE;
    case FALSE:
        return Boolean.FALSE;
    case NULL:
        return null;
    default:
        throw new IllegalArgumentException("Unexpected type: " + value.getValueType());
    }
}

使用Jackson转换:

JSONObject obj = new JSONObject().put("abc", "pqr").put("xyz", 5);

Map<String, Object> map = new ObjectMapper().readValue(obj.toString(), new TypeReference<Map<String, Object>>() {});