我有一个很简单的JS使用navigator。geolocation。getcurrentposition jammy。
$(document).ready(function(){
$("#business-locate, #people-locate").click(function() {
navigator.geolocation.getCurrentPosition(foundLocation, noLocation);
});
navigator.geolocation.getCurrentPosition(foundLocation, noLocation);
function foundLocation(position) {
var lat = position.coords.latitude;
var lon = position.coords.longitude;
var userLocation = lat + ', ' + lon;
$("#business-current-location, #people-current-location").remove();
$("#Near-Me")
.watermark("Current Location")
.after("<input type='hidden' name='business-current-location' id='business-current-location' value='"+userLocation+"' />");
$("#people-Near-Me")
.watermark("Current Location")
.after("<input type='hidden' name='people-current-location' id='people-current-location' value='"+userLocation+"' />");
}
function noLocation() {
$("#Near-Me").watermark("Could not find location");
$("#people-Near-Me").watermark("Could not find location");
}
})//end DocReady
基本上，这里发生的事情是我们得到当前位置，如果它得到了，两个“水印”被放置在两个字段中，表示“当前位置”，两个隐藏字段被创建，并使用latong数据作为它们的值(它们在开始时被删除，这样它们就不会每次都重复)。还有两个按钮，它们有一个点击功能，做同样的事情。
不幸的是，每隔三次左右，它就会奏效。
这里有什么问题?
@brennanyoung的回答很好，但如果你想知道在失败的情况下该怎么做，你可以使用IP地理定位API，如https://ipinfo.io(这是我的服务)。这里有一个例子:
function do_something(coords) {
// Do something with the coords here
// eg. show the user on a map, or customize
// the site contents somehow
}
navigator.geolocation.getCurrentPosition(function(position) {
do_something(position.coords);
},
function(failure) {
$.getJSON('https://ipinfo.io/geo', function(response) {
var loc = response.loc.split(',');
var coords = {
latitude: loc[0],
longitude: loc[1]
};
do_something(coords);
});
};
});
详情见https://ipinfo.io/developers/replacing-getcurrentposition。
我也遇到了同样的情况。我尝试了超时解决方案，但不可靠。我发现如果你只调用它两次，位置就会正确刷新
function getLocation(callback)
{
if(navigator.geolocation)
{
navigator.geolocation.getCurrentPosition(function(position)
{
navigator.geolocation.getCurrentPosition(callback, function(){},{maximumAge:0, timeout:10000});
},function(){}, {maximumAge:0, timeout:10000});
}
return true;
}
这当然是有点慢，但我没有给我错误的位置一次。我有它击中超时几次，没有返回任何东西，但除此之外，它工作得很好。我知道这仍然有点老套，我期待有人找到真正的解决方案。
或者，如果你想确保它会一直尝试，直到你想放弃，你可以试试这样的方法。
//example
$(document).ready(function(){
getLocation(function(position){
//do something cool with position
console.log(position);
});
});
var GPSTimeout = 10; //init global var NOTE: I noticed that 10 gives me the quickest result but play around with this number to your own liking
//function to be called where you want the location with the callback(position)
function getLocation(callback)
{
if(navigator.geolocation)
{
var clickedTime = (new Date()).getTime(); //get the current time
GPSTimeout = 10; //reset the timeout just in case you call it more then once
ensurePosition(callback, clickedTime); //call recursive function to get position
}
return true;
}
//recursive position function
function ensurePosition(callback, timestamp)
{
if(GPSTimeout < 6000)//set at what point you want to just give up
{
//call the geolocation function
navigator.geolocation.getCurrentPosition(
function(position) //on success
{
//if the timestamp that is returned minus the time that was set when called is greater then 0 the position is up to date
if(position.timestamp - timestamp >= 0)
{
GPSTimeout = 10; //reset timeout just in case
callback(position); //call the callback function you created
}
else //the gps that was returned is not current and needs to be refreshed
{
GPSTimeout += GPSTimeout; //increase the timeout by itself n*2
ensurePosition(callback, timestamp); //call itself to refresh
}
},
function() //error: gps failed so we will try again
{
GPSTimeout += GPSTimeout; //increase the timeout by itself n*2
ensurePosition(callback, timestamp);//call itself to try again
},
{maximumAge:0, timeout:GPSTimeout}
)
}
}
我可能在这里有一些打字和拼写错误，但我希望你能明白。如果有人有问题或者找到更好的建议，请告诉我。
