FORTRAN并不是一个真正的WTF时刻，而更像是一个“为什么我需要输入所有这些垃圾时刻”

IF(12 .gt. 11) THEN
 // Do some magic
ENDIF

“.gt.”在我玩这门语言的时候把我弄糊涂了，直到我意识到它是“>”符号。哦，我多喜欢不学生物，不用天天接触这些垃圾

在C语言中，数组可以像这样被索引:

a[10]

这很常见。

然而，鲜为人知的形式(真正有效!)是:

10[a]

这与上面的意思相同。

在fortran中(当然是77，可能在95中也是如此)，未声明的变量和以I到N开头的参数(“In”组)将是INTEGER，所有其他未声明的变量和参数将是REAL(源)。这与“在某些情况下可选的空白”相结合，导致了最著名的错误之一。

正如弗雷德·韦伯在1990年的《另类民间传说:计算机》一书中所说:

I worked at Nasa during the summer of 1963. The group I was working in was doing preliminary work on the Mission Control Center computer systems and programs. My office mate had the job of testing out an orbit computation program which had been used during the Mercury flights. Running some test data with known answers through it, he was getting answers that were close, but not accurate enough. So, he started looking for numerical problems in the algorithm, checking to make sure his tests data was really correct, etc. After a couple of weeks with no results, he came across a DO statement, in the form: DO 10 I=1.10 This statement was interpreted by the compiler (correctly) as: DO10I = 1.10 The programmer had clearly intended: DO 10 I = 1, 10 After changing the . to a , the program results were correct to the desired accuracy. Apparently, the program's answers had been "good enough" for the sub-orbital Mercury flights, so no one suspected a bug until they tried to get greater accuracy, in anticipation of later orbital and moon flights. As far as I know, this particular bug was never blamed for any actual failure of a space flight, but the other details here seem close enough that I'm sure this incident is the source of the DO story.

我认为这是一个很大的WTF，如果DO10I被作为DO10I，并且反过来，因为隐式声明被认为是类型REAL。这是个很棒的故事。

在c#中: A = cond ?B: c; 如果“b”和“c”是“赋值不兼容”，你永远不会得到结果，即使“a”是对象。 它是ms中最常用和最愚蠢的实现运算符。有关比较，请参阅D语言中的实现(关于类型推断的注意)。

在ColdFusion中，文本值自动转换为各种数据类型，用于各种目的。我遇到了一个奇怪的问题，“00A”和“000”被返回为相等。事实证明，ColdFusion将“00A”解释为时间，转换为某种数字时间格式，并将其转换为0。“000”被转换为0。所以它们都被认为是相等的。那时我学习了字符串的比较函数。

在Java中，字符串如何处理==操作符取决于它是如何构造的，这存在一些不一致性。

String a = "Hello";
String b = "Hello";
System.out.println(a == b ); // prints true.
String c = new String("Hello");
String d = new String("Hello"); 
System.out.println(c == d ); // prints false