我如何检查一个字符串(NSString)包含另一个较小的字符串?
我希望是这样的:
NSString *string = @"hello bla bla";
NSLog(@"%d",[string containsSubstring:@"hello"]);
但我能找到的最接近的是:
if ([string rangeOfString:@"hello"] == 0) {
NSLog(@"sub string doesnt exist");
}
else {
NSLog(@"exists");
}
不管怎样，这是找出字符串是否包含另一个字符串的最好方法吗?
当前回答
对于iOS 8.0+和macOS 10.10+，你可以使用NSString的本地containsString:。
对于旧版本的iOS和macOS，你可以为NSString创建自己的(过时的)类别:
@interface NSString ( SubstringSearch )
- (BOOL)containsString:(NSString *)substring;
@end
// - - - -
@implementation NSString ( SubstringSearch )
- (BOOL)containsString:(NSString *)substring
{
NSRange range = [self rangeOfString : substring];
BOOL found = ( range.location != NSNotFound );
return found;
}
@end
注意:观察Daniel Galasko下面关于命名的评论
其他回答
在Swift 4中:
let a = "Hello, how are you?"
a.contains("Hello") //will return true
在iOS 8和Swift中，我们可以使用localizedCaseInsensitiveContainsString方法
let string: NSString = "Café"
let substring: NSString = "É"
string.localizedCaseInsensitiveContainsString(substring) // true
第一串是否包含第二串，
NSString *first = @"Banana";
NSString *second = @"BananaMilk";
NSRange range = [first rangeOfString:second options:NSCaseInsensitiveSearch];
if (range.length > 0) {
NSLog(@"Detected");
}
else {
NSLog(@"Not detected");
}
Swift 4及以上
let str = "Hello iam midhun"
if str.contains("iam") {
//contains substring
}
else {
//doesn't contain substring
}
objective - c
NSString *stringData = @"Hello iam midhun";
if ([stringData containsString:@"iam"]) {
//contains substring
}
else {
//doesn't contain substring
}
联机(更少的代码。DRY，因为你只有一个NSLog):
NSString *string = @"hello bla bla";
NSLog(@"String %@", ([string rangeOfString:@"bla"].location == NSNotFound) ? @"not found" : @"cotains bla");
