如何使用PHP5类创建单例类?


当前回答

简单的例子:

final class Singleton
{
    private static $instance = null;

    private function __construct(){}

    private function __clone(){}

    private function __wakeup(){}

    public static function get_instance()
    {
        if ( static::$instance === null ) {
            static::$instance = new static();
        }
        return static::$instance;
    }
}

希望有帮助。

其他回答

这应该是Singleton的正确方式。

class Singleton {

    private static $instance;
    private $count = 0;

    protected function __construct(){

    }

    public static function singleton(){

        if (!isset(self::$instance)) {

            self::$instance = new Singleton;

        }

        return self::$instance;

    }

    public function increment()
    {
        return $this->count++;
    }

    protected function __clone(){

    }

    protected function __wakeup(){

    }

} 
class Database{

        //variable to hold db connection
        private $db;
        //note we used static variable,beacuse an instance cannot be used to refer this
        public static $instance;

        //note constructor is private so that classcannot be instantiated
        private function __construct(){
          //code connect to database  

         }     

         //to prevent loop hole in PHP so that the class cannot be cloned
        private function __clone() {}

        //used static function so that, this can be called from other classes
        public static function getInstance(){

            if( !(self::$instance instanceof self) ){
                self::$instance = new self();           
            }
             return self::$instance;
        }


        public function query($sql){
            //code to run the query
        }

    }


Access the method getInstance using
$db = Singleton::getInstance();
$db->query();

PHP 5.3允许通过后期静态绑定创建可继承的单例类:

class Singleton
{
    protected static $instance = null;

    protected function __construct()
    {
        //Thou shalt not construct that which is unconstructable!
    }

    protected function __clone()
    {
        //Me not like clones! Me smash clones!
    }

    public static function getInstance()
    {
        if (!isset(static::$instance)) {
            static::$instance = new static;
        }
        return static::$instance;
    }
}

这解决了一个问题,在PHP 5.3之前,任何扩展了Singleton的类都会生成父类的实例,而不是它自己的实例。

现在你可以做:

class Foobar extends Singleton {};
$foo = Foobar::getInstance();

$foo将是Foobar的一个实例而不是Singleton的一个实例。

简单的例子:

final class Singleton
{
    private static $instance = null;

    private function __construct(){}

    private function __clone(){}

    private function __wakeup(){}

    public static function get_instance()
    {
        if ( static::$instance === null ) {
            static::$instance = new static();
        }
        return static::$instance;
    }
}

希望有帮助。

我喜欢使用trait的@jose-segura方法,但不喜欢在子类上定义静态变量的需要。下面是一个解决方案,通过将实例缓存在一个静态局部变量中到按类名索引的工厂方法中来避免这种情况:

<?php
trait Singleton {

  # Single point of entry for creating a new instance. For a given
  # class always returns the same instance.
  public static function instance(){
    static $instances = array();
    $class = get_called_class();
    if( !isset($instances[$class]) ) $instances[$class] = new $class();
    return $instances[$class];
  }

  # Kill traditional methods of creating new instances
  protected function __clone() {}
  protected function __construct() {}
}

用法与@jose-segura相同,只是在子类中不需要静态变量。