这个问题是作为长度前缀字符串(LPS)与零终止字符串(SZ)的问题提出的，但主要暴露了长度前缀字符串的好处。这似乎有些势不可挡，但老实说，我们也应该考虑到LPS的缺点和SZ的优点。

在我看来，这个问题甚至可以被理解为一种带有偏见的提问方式:“零终止字符串的优势是什么?”

零终止字符串的优点(我看到了):

very simple, no need to introduce new concepts in language, char arrays/char pointers can do. the core language just include minimal syntaxic sugar to convert something between double quotes to a bunch of chars (really a bunch of bytes). In some cases it can be used to initialize things completely unrelated with text. For instance xpm image file format is a valid C source that contains image data encoded as a string. by the way, you can put a zero in a string literal, the compiler will just also add another one at the end of the literal: "this\0is\0valid\0C". Is it a string ? or four strings ? Or a bunch of bytes... flat implementation, no hidden indirection, no hidden integer. no hidden memory allocation involved (well, some infamous non standard functions like strdup perform allocation, but that's mostly a source of problem). no specific issue for small or large hardware (imagine the burden to manage 32 bits prefix length on 8 bits microcontrollers, or the restrictions of limiting string size to less than 256 bytes, that was a problem I actually had with Turbo Pascal eons ago). implementation of string manipulation is just a handful of very simple library function efficient for the main use of strings : constant text read sequentially from a known start (mostly messages to the user). the terminating zero is not even mandatory, all necessary tools to manipulate chars like a bunch of bytes are available. When performing array initialisation in C, you can even avoid the NUL terminator. Just set the right size. char a[3] = "foo"; is valid C (not C++) and won't put a final zero in a. coherent with the unix point of view "everything is file", including "files" that have no intrinsic length like stdin, stdout. You should remember that open read and write primitives are implemented at a very low level. They are not library calls, but system calls. And the same API is used for binary or text files. File reading primitives get a buffer address and a size and return the new size. And you can use strings as the buffer to write. Using another kind of string representation would imply you can't easily use a literal string as the buffer to output, or you would have to make it have a very strange behavior when casting it to char*. Namely not to return the address of the string, but instead to return the actual data. very easy to manipulate text data read from a file in-place, without useless copy of buffer, just insert zeroes at the right places (well, not really with modern C as double quoted strings are const char arrays nowaday usually kept in non modifiable data segment). prepending some int values of whatever size would implies alignment issues. The initial length should be aligned, but there is no reason to do that for the characters datas (and again, forcing alignment of strings would imply problems when treating them as a bunch of bytes). length is known at compile time for constant literal strings (sizeof). So why would anyone want to store it in memory prepending it to actual data ? in a way C is doing as (nearly) everyone else, strings are viewed as arrays of char. As array length is not managed by C, it is logical length is not managed either for strings. The only surprising thing is that 0 item added at the end, but that's just at core language level when typing a string between double quotes. Users can perfectly call string manipulation functions passing length, or even use plain memcopy instead. SZ are just a facility. In most other languages array length is managed, it's logical that is the same for strings. in modern times anyway 1 byte character sets are not enough and you often have to deal with encoded unicode strings where the number of characters is very different of the number of bytes. It implies that users will probably want more than "just the size", but also other informations. Keeping length give use nothing (particularly no natural place to store them) regarding these other useful pieces of information.

也就是说，在标准C字符串确实效率低下的罕见情况下，没有必要抱怨。图书馆是可用的。如果我遵循这个趋势，我应该抱怨标准C不包括任何正则表达式支持函数……但实际上每个人都知道这不是一个真正的问题，因为有库可以用于此目的。因此，当字符串操作效率是需要的，为什么不使用像bstring库?或者甚至是c++字符串?

编辑:我最近看了看D弦。有趣的是，所选择的解决方案既不是大小前缀，也不是零终止。与C语言一样，双引号括起来的字面值字符串只是不可变字符数组的简写，并且该语言也有一个字符串关键字表示(不可变字符数组)。

但是D数组比C数组丰富得多。在静态数组的情况下，长度在运行时是已知的，因此不需要存储长度。编译器在编译时拥有它。在动态数组的情况下，长度是可用的，但D文档没有说明它保存在哪里。就我们所知，编译器可以选择将它保存在某个寄存器中，或者存储在远离字符数据的某个变量中。

正常char数组或非字符串没有最终为零,因此程序员必须把它本身如果他想叫一些C函数从D .字符串字面量的具体情况,然而D编译器仍然把零在每个字符串(允许容易把C字符串容易调用C函数?),但这零不是字符串的一部分(D不计算字符串大小)。

The only thing that disappointed me somewhat is that strings are supposed to be utf-8, but length apparently still returns a number of bytes (at least it's true on my compiler gdc) even when using multi-byte chars. It is unclear to me if it's a compiler bug or by purpose. (OK, I probably have found out what happened. To say to D compiler your source use utf-8 you have to put some stupid byte order mark at beginning. I write stupid because I know of not editor doing that, especially for UTF-8 that is supposed to be ASCII compatible).

围绕C语言的许多设计决策都源于这样一个事实:在最初实现C语言时，参数传递的代价有些昂贵。如果在两者之间作选择。

void add_element_to_next(arr, offset)
  char[] arr;
  int offset;
{
  arr[offset] += arr[offset+1];
}

char array[40];

void test()
{
  for (i=0; i<39; i++)
    add_element_to_next(array, i);
}

与

void add_element_to_next(ptr)
  char *p;
{
  p[0]+=p[1];
}

char array[40];

void test()
{
  int i;
  for (i=0; i<39; i++)
    add_element_to_next(arr+i);
}

后者会稍微便宜一点(因此是首选)，因为它只需要传递一个参数而不是两个。如果被调用的方法不需要知道数组的基址，也不需要知道其中的索引，那么将这两个值组合在一起传递一个指针比分别传递值要便宜。

While there are many reasonable ways in which C could have encoded string lengths, the approaches that had been invented up to that time would have all required functions that should be able to work with part of a string to accept the base address of the string and the desired index as two separate parameters. Using zero-byte termination made it possible to avoid that requirement. Although other approaches would be better with today's machines (modern compilers often pass parameters in registers, and memcpy can be optimized in ways strcpy()-equivalents cannot) enough production code uses zero-byte terminated strings that it's hard to change to anything else.

PS——为了在某些操作上稍微降低速度，以及在较长的字符串上稍微增加一点额外开销，可以让处理字符串的方法直接接受指向字符串的指针、经过边界检查的字符串缓冲区或标识另一个字符串的子字符串的数据结构。像“strcat”这样的函数看起来像[现代语法]

void strcat(unsigned char *dest, unsigned char *src)
{
  struct STRING_INFO d,s;
  str_size_t copy_length;

  get_string_info(&d, dest);
  get_string_info(&s, src);
  if (d.si_buff_size > d.si_length) // Destination is resizable buffer
  {
    copy_length = d.si_buff_size - d.si_length;
    if (s.src_length < copy_length)
      copy_length = s.src_length;
    memcpy(d.buff + d.si_length, s.buff, copy_length);
    d.si_length += copy_length;
    update_string_length(&d);
  }
}

比K&R strcat方法大一点，但它支持边界检查，而K&R方法不支持。此外，与当前的方法不同，它可以轻松地连接任意子字符串，例如。

/* Concatenate 10th through 24th characters from src to dest */

void catpart(unsigned char *dest, unsigned char *src)
{
  struct SUBSTRING_INFO *inf;
  src = temp_substring(&inf, src, 10, 24);
  strcat(dest, src);
}

注意，由temp_substring返回的字符串的生命周期将受到s和src的生命周期的限制，后者更短(这就是为什么该方法需要传入inf——如果它是本地的，它将在方法返回时死亡)。

In terms of memory cost, strings and buffers up to 64 bytes would have one byte of overhead (same as zero-terminated strings); longer strings would have slightly more (whether one allowed amounts of overhead between two bytes and the maximum required would be a time/space tradeoff). A special value of the length/mode byte would be used to indicate that a string function was given a structure containing a flag byte, a pointer, and a buffer length (which could then index arbitrarily into any other string).

当然，K&R并没有实现任何这样的东西，但这很可能是因为他们不想在字符串处理上花费太多精力——即使在今天，许多语言在这方面似乎都相当薄弱。

懒惰、寄存器节俭和可移植性考虑到任何语言的汇编核心，尤其是C语言，它比汇编高出一步(因此继承了大量汇编遗留代码)。 你会同意null字符在那些ASCII的日子里是无用的，它(可能和EOF控件字符一样好)。

让我们看看伪代码

function readString(string) // 1 parameter: 1 register or 1 stact entries
    pointer=addressOf(string) 
    while(string[pointer]!=CONTROL_CHAR) do
        read(string[pointer])
        increment pointer

共使用1个寄存器

案例2

 function readString(length,string) // 2 parameters: 2 register used or 2 stack entries
     pointer=addressOf(string) 
     while(length>0) do 
         read(string[pointer])
         increment pointer
         decrement length

共使用2个寄存器

这在当时似乎是短视的，但考虑到代码和寄存器的节俭(这在当时是PREMIUM，那时你知道，他们使用穿孔卡)。因此，更快(当处理器速度可以以kHz计)，这个“黑客”是相当不错的，可轻松移植到无寄存器处理器。

为了便于讨论，我将实现2个常见的字符串操作

stringLength(string)
     pointer=addressOf(string)
     while(string[pointer]!=CONTROL_CHAR) do
         increment pointer
     return pointer-addressOf(string)

复杂度O(n)，在大多数情况下PASCAL字符串是O(1)，因为字符串的长度是预先挂起的字符串结构(这也意味着该操作必须在更早的阶段进行)。

concatString(string1,string2)
     length1=stringLength(string1)
     length2=stringLength(string2)
     string3=allocate(string1+string2)
     pointer1=addressOf(string1)
     pointer3=addressOf(string3)
     while(string1[pointer1]!=CONTROL_CHAR) do
         string3[pointer3]=string1[pointer1]
         increment pointer3
         increment pointer1
     pointer2=addressOf(string2)
     while(string2[pointer2]!=CONTROL_CHAR) do
         string3[pointer3]=string2[pointer2]
         increment pointer3
         increment pointer1
     return string3

复杂度O(n)和预先设置字符串长度不会改变操作的复杂性，而我承认它会减少3倍的时间。

另一方面,如果你使用PASCAL字符串将不得不重新设计您的API来考虑在长度和bit-endianness注册,帕斯卡字符串的众所周知的限制255字符(0 xff)因为中存储的长度是1个字节(8位),而且你想要更长的字符串(16位- >任何)你必须考虑在一层的架构代码,这意味着在大多数情况下不相容的字符串API如果你想要更长的字符串。

例子:

One file was written with your prepended string api on an 8 bit computer and then would have to be read on say a 32 bit computer, what would the lazy program do considers that your 4bytes are the length of the string then allocate that lot of memory then attempt to read that many bytes. Another case would be PPC 32 byte string read(little endian) onto a x86 (big endian), of course if you don't know that one is written by the other there would be trouble. 1 byte length (0x00000001) would become 16777216 (0x0100000) that is 16 MB for reading a 1 byte string. Of course you would say that people should agree on one standard but even 16bit unicode got little and big endianness.

当然，C也有它的问题，但它不会受到这里提出的问题的影响。

不知怎的，我把这个问题理解为C中没有编译器支持以长度为前缀的字符串。下面的例子显示，至少你可以开始你自己的C字符串库，其中字符串长度在编译时计算，使用这样的构造:

#define PREFIX_STR(s) ((prefix_str_t){ sizeof(s)-1, (s) })

typedef struct { int n; char * p; } prefix_str_t;

int main() {
    prefix_str_t string1, string2;

    string1 = PREFIX_STR("Hello!");
    string2 = PREFIX_STR("Allows \0 chars (even if printf directly doesn't)");

    printf("%d %s\n", string1.n, string1.p); /* prints: "6 Hello!" */
    printf("%d %s\n", string2.n, string2.p); /* prints: "48 Allows " */

    return 0;
}

然而，这不会带来任何问题，因为你需要小心什么时候特别释放字符串指针，什么时候它是静态分配的(字面字符数组)。

编辑:作为对这个问题更直接的回答，我的观点是，这是C既可以支持可用的字符串长度(作为编译时间常数)的方式，如果你需要它，但如果你只想使用指针和零终止，仍然没有内存开销。

当然，使用以零结尾的字符串似乎是推荐的做法，因为标准库一般不接受字符串长度作为参数，而且提取长度的代码不像char * s = "abc"那样简单，正如我的示例所示。

假设C以Pascal的方式实现字符串，通过前缀长度:7字符长字符串与3字符字符串的数据类型相同吗?如果答案是肯定的，那么当我将前者分配给后者时，编译器应该生成什么样的代码?字符串应该被截断，还是自动调整大小?如果调整大小，该操作是否应该被锁保护以使其线程安全?不管你喜不喜欢，C语言的方法回避了所有这些问题。

我不相信“C没有字符串”的答案。没错，C语言不支持内置的高级类型，但你仍然可以用C语言表示数据结构，这就是字符串。在C语言中，字符串只是一个指针，但这并不意味着前N个字节不能作为长度具有特殊意义。

Windows/COM开发人员将非常熟悉BSTR类型，它就像这样——一个有长度前缀的C字符串，其中实际的字符数据不是从字节0开始的。

因此，使用空终止符的决定似乎只是人们喜欢的，而不是语言的必要。