我有两个表，table1是一个列ID的父表，table2是一个列IDFromTable1(不是实际的名称)，当我把一个FK IDFromTable1到ID在table1，我得到的错误外键约束是不正确形成的错误。我想删除表2记录，如果表1记录被删除。谢谢你的帮助
ALTER TABLE `table2`
ADD CONSTRAINT `FK1`
FOREIGN KEY (`IDFromTable1`) REFERENCES `table1` (`ID`)
ON UPDATE CASCADE
ON DELETE CASCADE;
如果还需要其他信息，请告诉我。我是mysql的新手
当前回答
试着运行以下命令:
show create table Parent //and check if type for both tables are the same, like myISAM or innoDB, etc //Other aspects to check with this error message: the columns used as foreign keys must be indexed, they must be of the same type (if i.e one is of type smallint(5) and the other of type smallint(6), it won't work), and, if they are integers, they should be unsigned. //or check for charsets show variables like "character_set_database"; show variables like "collation_database"; //edited: try something like this ALTER TABLE table2 ADD CONSTRAINT fk_IdTable2 FOREIGN KEY (Table1_Id) REFERENCES Table1(Table1_Id) ON UPDATE CASCADE ON DELETE CASCADE;
其他回答
我在这里遗漏的另一个解决方案是，在创建约束的表中，引用表的每个主键都应该有一个带有外键的条目。
试着运行以下命令:
show create table Parent //and check if type for both tables are the same, like myISAM or innoDB, etc //Other aspects to check with this error message: the columns used as foreign keys must be indexed, they must be of the same type (if i.e one is of type smallint(5) and the other of type smallint(6), it won't work), and, if they are integers, they should be unsigned. //or check for charsets show variables like "character_set_database"; show variables like "collation_database"; //edited: try something like this ALTER TABLE table2 ADD CONSTRAINT fk_IdTable2 FOREIGN KEY (Table1_Id) REFERENCES Table1(Table1_Id) ON UPDATE CASCADE ON DELETE CASCADE;
如果一切正常，只需添加->unsigned();在外键的末尾。
如果不行，请检查两个字段的数据类型。它们必须是一样的。
我面临这个问题，当你把主键放在不同的数据类型，比如:
表1:
Schema::create('products', function (Blueprint $table) {
$table->increments('id');
$table->string('product_name');
});
表2:
Schema::create('brands', function (Blueprint $table) {
$table->bigIncrements('id');
$table->string('brand_name');
});
第二个表id的数据类型必须为增量
我在使用HeidiSQL时也遇到了同样的问题。您收到的错误非常神秘。我的问题是外键列和引用列的类型或长度不相同。
外键列是SMALLINT(5) UNSIGNED，引用列是INT(10) UNSIGNED。一旦我将它们都设置为完全相同的类型，外键的创建就会完美地工作。
